Two-Dimensional Motion

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Presentation transcript:

Two-Dimensional Motion Inclined Planes

A simple block on an incline Inclined Planes A simple block on an incline A simple block on an incline 30° Fg

Inclined Planes B/c the block in on an incline, we adjust our coordinate system to fit the incline Y A simple block on an incline X 30° Fg Aligning the X axis with the Incline

Inclined Planes Notice the gravitational force (Fg) is pulling straight down Doesn’ t the Fg also pull you down the hill? YEP! So, there are components of the Fg (x and y)

Inclined Planes There is an Fgx and an Fgy Fgx Fgy Fg

Inclined Planes Notice that the coordinate system has been adjusted… How much? Y X 30° Fg It has been adjusted by the incline, 30°

Inclined Planes Therefore the angle between Fg and Fgy is… 30° Fgx Fgy

Inclined Planes Therefore the angle between Fg and Fgy is… 30° Fgx Fgy

Inclined Planes Now we are able to solve for fgx and fgy Fgx is the force pulling the block down the incline Fgy is the force keeping the block in contact with the incline

Inclined Planes Realign the vectors (Tip-to-Tail) to complete a right triangle and you get… Fgy 30° Fg 30° Fgx

Inclined Planes Lets take a closer (magnified) look at the similar triangle Fgy 30° Fg 30° Fgx

Inclined Planes Lets take a closer (magnified) look at the similar triangle Y Nice! Fgy 30° Fgx X Fg

Inclined Plane Problem A 784-N skier on a hill that makes a 35 angle with the horizontal begins to accelerate down the hill. Draw the pictorial diagram and free-body diagram What is the component of the skier’s weight parallel to the incline plane? What is the normal force?