Charles’ Law Matter and energy December 20, 2017 Learning Target: I CAN Develop a relationship between volume and temperature and apply Charles’ Law to gas law problems

Do Now (4 min) December 20, 2017 Learning target: I can Develop a relationship between volume and temperature and apply Charles’ Law to gas law problems Do Now: (Answer on your Do Now Sheet) Identify all critical pieces of information from the following: A closed container contains 2 moles of Helium at 25oC and 1 L. The container is then heated to 50oC. What is the new volume? Learning Target: I CAN Develop a relationship between volume and temperature and apply Charles’ Law to gas law problems

December 20, 2017 Units of Temperature!!!! K = Kelvin!! *Your new best friend 0oC = frozen water K = oC + 273 Learning Target: I CAN Develop a relationship between volume and temperature and apply Charles’ Law to gas law problems

December 20, 2017 Charles’ law You have your handy balloon all blown up. What happens to the speed of the molecules when the temperature is increased? If the molecules (speed up/slow down), what happens to the volume of your balloon? Learning Target: I CAN Develop a relationship between volume and temperature and apply Charles’ Law to gas law problems

Example #1: Temperature! December 20, 2017 Example #1: Temperature! K = oC + 273 Example #1: Convert the following temperature readings into the desired units: 25.0˚C = 100˚C = -273˚C = Learning Target: I CAN Develop a relationship between volume and temperature and apply Charles’ Law to gas law problems

December 20, 2017 Standard temperature: 273 K = 00C Standard pressure: 1 atm Charles’ law Example #2: A gas at 20.0˚C is increased to 40.0˚C, and the original volume was 1.00 L. What would the new volume be? V1 T1 = V2 T2 1.00 L 20.0 oC 293 K   FIND ME!! 40.O oC 313 K Learning Target: I CAN Develop a relationship between volume and temperature and apply Charles’ Law to gas law problems

December 20, 2017 Standard temperature: 273 K = 00C Standard pressure: 1 atm Charles’ law Use V1 = V2 to find V2 T1 T2 1.00 L = V2 293 K 313K (293 K) V2 = (1.00 L) (313 K) V2 = 1.07 L Learning Target: I CAN Develop a relationship between volume and temperature and apply Charles’ Law to gas law problems

December 20, 2017 Standard temperature: 273 K = 00C Standard pressure: 1 atm You try: Charles’ law Example #3: A sample of O2 under 2.00 atm occupies 500 ml at 25.0˚C.What will be the temperature of the sample at 1500 ml ? V1 T1 = V2 T2 25.0 oC _____ K   Learning Target: I CAN Develop a relationship between volume and temperature and apply Charles’ Law to gas law problems

December 20, 2017 pair work (15 min) Work in PAIRS Draw relationship boxes AND write out equations! Learning Target: I CAN Develop a relationship between volume and temperature and apply Charles’ Law to gas law problems

December 20, 2017 Exit ticket (3 min) EXIT TICKET: complete on a separate sheet of paper: What happens to the temperature, in Kelvin, when the volume is doubled? Learning Target: I CAN Develop a relationship between volume and temperature and apply Charles’ Law to gas law problems