Heat sink analysis: analytically and via ANSYS ME 340 Final Project - Dr. Soloviev - Fall 2010 by Mathew Marshal & Kevin Hoopes
Problem definition Intel core i7 processors can dissipate up to 130W under full load They must be kept below 373 K to prevent hardware damage We are given a certain rectangular fin, integral heat sink Find the required convection coefficient to keep the base below 373 K.
Boundary Conditions Base exposed to constant heat input of 130W Sides of base are adiabatic Sides and tops of fins are exposed to convective heat transfer to surrounding atmosphere at 298 K Heat sink is solid Aluminum
ANSYS Solution Define Geometry Apply boundary conditions Mesh Solve
ANSYS Solution Results obtained for initial guess for h Iterated until base temperature reached approximately 373 K h value found to be 37.6 W*K/m^2
Analytical Solution h = 39.8 W*K/m^2
Summary ANSYS Solution – 37.5 Analytical Solution – 39.8
Appendix Analytical Solution ANSYS Log file
*SET,_REMOTE_VIS_ID,'39' /SOL FITEM,2,-6 WPSTYLE,,,,,,,,0 FITEM,2,82 /PREP7 FITEM,2,-83 !DEFINE THE BLOCK !DEFINE ELEMENT TYPE BLC4,0,0,0.042,0.001,0.045 ET,1,SOLID70 FLST,2,1,5,ORDE,1 !MAKE A FIN ET,2,SOLID70 FITEM,2,3 BLC4,0,0.001,0.0021,0.055,0.045 MPTEMP,,,,,,,, !COPY THE FINS MPTEMP,1,0 !DEFINE HEAT FLUX ON BOTTOM OF HEAT SINK FLST,3,1,6,ORDE,1 !DEFINE CONDUCTION COEFICIENT SFA,P51X,1,HFLUX,68783 FITEM,3,2 MPDATA,KXX,1,,250 VGEN,2,P51X, , ,0.004433333, , , ,0 FLST,2,59,5,ORDE,23 FITEM,2,10 FITEM,3,3 FITEM,2,12 /POST1 FITEM,2,-14 FITEM,2,16 FITEM,3,4 FITEM,2,-20 SMRT,6 FITEM,2,22 SMRT,2 FITEM,2,-26 SMRT,1 FITEM,3,5 FITEM,2,28 MSHAPE,1,3D FITEM,2,-32 MSHKEY,0 FITEM,2,34 CM,_Y,VOLU FITEM,3,6 FITEM,2,-38 VSEL, , , , 12 FITEM,2,40 CM,_Y1,VOLU FITEM,2,-44 CHKMSH,'VOLU' FITEM,3,7 FITEM,2,46 CMSEL,S,_Y FITEM,2,-50 VMESH,_Y1 FITEM,2,52 CMDELE,_Y FITEM,3,8 FITEM,2,-56 CMDELE,_Y1 FITEM,2,58 CMDELE,_Y2 FITEM,2,-60 FITEM,3,9 FITEM,2,64 FITEM,2,-65 SOLVE FITEM,2,67 FITEM,3,10 FITEM,2,-81 /GO FLST,2,11,6,ORDE,2 !DEFINE CONVECTION COEFICIENT, THIS IS ITERATED TO OBTAIN THIS SOLUTION FITEM,2,1 FITEM,2,-11 SFA,P51X,1,CONV,37.60,298 VADD,P51X FLST,2,4,5,ORDE,4 FINISH FITEM,2,5