ANGLE AND LINE By: NIKMATUL HUSNA

SUPPLEMENTARY AOC +  BOC =  AOB a0 + b0 = 1800 We can write a0 = 1800 - b0 or b0 = 1800 - a0

Conclusion : The sum of supplementary angle is 1800. An angle is the supplement of another angle

COMPLEMENTARY PQS +  RQS =  PQR X0 + Y0 = 900 We can write X0 = 900 - Y0 or Y0 = 900 - X0

Conclusion : The sum of complementary angle is 900. An angle is the complement of another angle

OPPOSITE ANGLE POQ and  SOR are opposite angle. POQ =  SOR POS =  QOR POQ and  SOR are opposite angle. POS and  QOR are opposite angle.

Conclusion : The measure of opposite angle is same

Opposite Angles 1 and 7 2 and 8 3 and 5 4 and 6 1 = 7, 2 = 8, 3 = 5, 4 = 6

Alternate Interior Angles Alternate Exterior Angles Corresponding Angles Alternate Interior Angles Alternate Exterior Angles Consecutive Interior Angles Consecutive Exterior Angles 1 2 3 4 5 6 7 8 t

Corresponding Angles 4 and 2 3 and 1 5 and 7 6 and 8 t 1 4 = 2, 3 = 1, 5 = 7, 6 = 8

Alternate Interior Angles 3 and 7 2 and 6 5 6 4 7 3 8 2 t 1 3 = 7 and2 = 6

Alternate Exterior Angles 5 and 1 4 and 8 5 6 4 7 3 8 2 t 1 5 = 1 and4 = 8

Consecutive Interior Angles 5 3 and 2 6 and 7 6 4 7 3 8 2 t 1 3 +2 = 1800 and 6 +7 = 1800

Consecutive Exterior Angles 5 4 and 1 5 and 8 6 4 7 3 8 2 t 1 4 + 1 = 1800 and 5 + 8 = 1800

Example : Look at the picture. Given  1 = 750 and Find: 1  5 2  6 1  5 2  6 3  7 4  8 1 2 3 4 5 6 7 8 t

Answer : 1 = 750  5 = 750 2 = 1050  6 = 1050 3 = 750  7= 750 4 = 1050  8= 1050

Example : Look at the picture. Given  1 = (3x+45)0 and Find: 1  5 2  6 3  7 4  8 1 2 3 4 5 6 7 8 t

Answer : 1 + 4 =1800 (3x+45)0 + (5x+23)0 =1800 1 + 4 =1800 (3x+45)0 + (5x+23)0 =1800 3x 0+ 5x 0 +45 0 + 23 0 =1800 8x0 =1800- 450 – 230 8x0 =112 0 x = 140

1=(3x+45)0 = 3 X 140 +450 = 420 +450 = 870  4=1800- 870 = 930  2= 930  3= 870  5= 870  6= 930  7= 870  8= 930