Conservation of momentum

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Presentation transcript:

Conservation of momentum

Scenario 1

Scenario 2

Scenario 3

positive ball A ball B mass = 2 kg mass = 3 kg initial velocity = 3 ms-1 initial velocity = 0 ms-1 initial momentum = 6 Ns initial momentum = 0 Ns final velocity = 1 ms-1 final velocity = ? final momentum = 2 Ns final momentum = 3v Ns impulse on A = impulse on B = change in momentum = 2x1 – 2x3 = -4 ms-1 change in momentum = 3v - 0 The Impulse on ball A is equal in magnitude to the Impulse on ball B but in the opposite direction 4 = 3v v = 4/3 ms-1

positive ball B ball A mass = m1 mass = m2 initial velocity = u1 initial velocity = u2 final velocity = v1 final velocity = v2 I1 = m1v1-m1u1 I2 = m2v2-m2u2 The Impulse on ball A is equal in magnitude to the Impulse on ball B but in the opposite direction I1 = -I2 m1v1-m1u1 = -(m2v2-m2u2) m1v1-m1u1 = -m2v2+m2u2 m1v1+m2v2 = m1u1+m2u2 The total momentum before impact = the total momentum after impact