Section 5.5 Additional Popper 34: Choice A for #1 – 10

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Section 5.5 Additional Popper 34: Choice A for #1 – 10

Section 5.5 Additional Popper 34: Choice A for #1 – 10

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Presentation transcript:

Section 5.5 Additional Popper 34: Choice A for #1 – 10 MATH 1310 Section 5.5 Additional Popper 34: Choice A for #1 – 10

Solving Exponential and Logarithmic Equations

Popper 33: Simplify the equation: a. e(x+5) = 2 b. e(x+5) = ½ c. e(x+5) = 3 d. e(x+5) = 48 2. Solve the equation: a. x = ln(½) + 5 b. x = log(½) – 5 c. x = ln(½) – 5 d. x = ln(½) 3. Approximate the answer (Calculator): a. x ≈ 4.317 b. x ≈ -5.301 c. x ≈ -5.693 d. x ≈ -0.693 4. Simplify the logarithmic answer (Question 2): a. x = ln(-3) b. x = ln(-4.5) c. x = ln(½) – 5 d. x = -ln(2) – 5

Popper 33 Continued: Solve the following equation: 3 (2)x – 7 + 6 = 12 5. Simplify the equation: a. (2)x – 7 = 2 b. (2)x – 7 = 6 c. (2)x – 7 = -3 d. (2)x – 7 = 12 6. Solve in base 2: log22 – 7 b. log22 + 13 c. log22 d. log22 + 7 7. Solve in base e: ln2 + 7 b.ln2 – 7 c. ln 2 ln 2 +7 d. ln 7 ln 2 +2 8. Simplify either answer: a. 7/2 b. 2/7 c. 5 d. 8

Additional Popper 31: #1 – 10, fill out Choice A

Popper 33: 9. Simplify the equation: a. log6(2x + 5) = 2 b. log6(7x) = 2 c. log6(x2 + 5x) = 2 d. log6(x2 + 5) = 2 10. Use Inverse Functions to each side: a. x2 + 5x = 2 b. x2 + 5x = 36 c. x2 + 5x = e2 d. x2 + 5x = 100 11. Solve the Resulting Equation for x: a. {-9, 4} b. {-4, 9} c. {-9, -4} d. No Real Solution 12. Check your answers to eliminate Extraneous Roots. The solution is/are: a. {-9, 4} b. {-9} c. {4} d. No Real Solution

Solve the following: log2x = log4(x + 56)