The Big Bahm Theorem 3x2 + x – 10 3x2 + x – 10 3 3 (x – 5)(x + 2) 3 (3x – 5)(x + 2) Step 1 = Slide “a” to the end and multiply it by the constant (c). Step 2 = Factor like normal Step 3 = You have to “put back” the number you slid to the end (a). You do this by dividing the constant in each factor by the leading coefficient you “slid” out of the way Step 4 = Simplify the fractional terms you end up with. Step 5 = Once it is simplified, if there is a fraction left, the denominator becomes the coefficient of the variable term.

The Big Bahm Theorem 10x2 + 17x + 3 10x2 + 17x +3 10 10 (x + 3)(x + 1) 2 5 (2x+3)(5x + 1) Step 1 = Slide “a” to the end and multiply it by the constant (c). Step 2 = Factor like normal Step 3 = You have to “put back” the number you slid to the end (a). You do this by dividing the constant in each factor by the leading coefficient you “slid” out of the way Step 4 = Simplify the fractional terms you end up with. Step 5 = Once it is simplified, if there is a fraction left, the denominator becomes the coefficient of the variable term.

The Big Bahm Theorem 5x2 + 7x – 6 5x2 + 7x – 6 5 5 (x – 3)(x + 2) 5 (5x – 3)(x + 2) Step 1 = Slide “a” to the end and multiply it by the constant (c). Step 2 = Factor like normal Step 3 = You have to “put back” the number you slid to the end (a). You do this by dividing the constant in each factor by the leading coefficient you “slid” out of the way Step 4 = Simplify the fractional terms you end up with. Step 5 = Once it is simplified, if there is a fraction left, the denominator becomes the coefficient of the variable term.