Applied Math II 13.1 13.2 13.3 13.4 13.5 100 100 100 100 100 200 200 200 200 200 300 300 300 300 300 400 400 400 400 400 500 500 500 500 500 600 600 600.

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Presentation transcript:

Applied Math II 13.1 13.2 13.3 13.4 13.5 100 100 100 100 100 200 200 200 200 200 300 300 300 300 300 400 400 400 400 400 500 500 500 500 500 600 600 600 600 600 Credits

13.1 - 100 Simplify: Answer

13.1- 200 Simplify: Answer

13.1- 300 Simplify: x Answer

13.1- 400 Simplify: Answer

13.1- 500 Simplify: Answer

13.1 - 600 Simplify: Answer

13.1- 100 Answer Simplify: Answer: 2

13.1- 200 Answer Simplify: Answer: 6

13.1- 300 Answer Simplify: x Answer: 2

13.1- 400 Answer Simplify: Answer:

13.1- 500 Answer Simplify: Answer:

13.1- 600 Answer Simplify: Answer:

13.2- 100 Solve for x: 45 x 3 45 3 Answer

13.2 - 200 Solve for x: 45 x 5 45 5 Answer

13.2- 300 Solve for x and y: 45 8 x 45 y Answer

13.2- 400 Solve for x and y: 45 7 x 45 y Answer

13.2 - 500 Solve for x and y: 45 8 x 45 y Answer

Find the length of the diagonal of a square that has an area of 25in² 13.2- 600 Find the length of the diagonal of a square that has an area of 25in² Answer

13.2- 100 Answer Solve for x: 45 x 3 45 3 Answer:

13.2- 200 Answer Solve for x: 45 x 5 45 5 Answer:

13.2- 300 Answer Solve for x and y: 45 8 x 45 y Answer: x = 8, y = 8

13.2- 400 Answer Solve for x and y: 45 7 x 45 y Answer: x = y =

13.2- 500 Answer Solve for x: 45 8 x 45 y Answer: x = y =

Find the length of the diagonal of a square that has an area of 25in² 13.2- 600 Answer Find the length of the diagonal of a square that has an area of 25in² Answer: in

13.3 - 100 Solve for x and y: 30 y x 60 2 Answer

13.3 - 200 Solve for x and y: 30 y x 60 5 Answer

13.3- 300 Solve for x and y: 30 y 6 60 x Answer

13.3 - 400 Solve for x and y: 30 y 36 60 x Answer

13.3- 500 Solve for x and y: 30 y 60 x Answer

13.3- 600 Find the length of the altitude of an equilateral triangle with sides of 10 inches. Answer

13.3 - 100 Answer Solve for x and y: 30 y x 60 2 Answer: x = 4, y =2

13.3 - 200 Answer Solve for x and y: 30 y x 60 5 Answer: x = 10, y = 5

13.3 - 300 Answer Solve for x and y: 30 y 6 60 x Answer: x = 3, y =

13.3 - 400 Answer Solve for x and y: 30 y 36 60 x Answer: x = 18, y =

13.3 - 500 Answer Solve for x and y: 30 y 60 x Answer: x = 7, y = 14

13.3 - 600 Answer Find the length of the altitude of an equilateral triangle with sides of 10 inches. Answer:

13.4 – 100 Find tanA A 5 4 C B 3 Answer

13.4 - 200 Find tanB A 5 4 C B 3 Answer

13.4 – 300 Solve for x: x 40 12 Answer

13.4 - 400 Solve for x: 40 70 x Answer

13.4 - 500 Solve for x: x 40 10 Answer

13.4 - 600 Given a right triangle, if the side adjacent to a 23° angle is 10 inches, find the length of the opposite side. Answer

13.4 - 100 Answer Find tanA A 5 4 C B 3 Answer: tanA = 3/4

13.4 - 200 Answer Find tanB A 5 4 C B 3 Answer: tan B = 4/3

13.4 - 300 Answer Solve for x: x 40 12 Answer: x = 10.07

13.4 - 400 Answer Solve for x: 40 70 x Answer: x = 14.56

13.4 - 500 Answer Solve for x: x 40 10 Answer: 14.04°

13.4 - 600 Answer Given a right triangle, if the side adjacent to a 23° angle is 10 inches, find the length of the opposite side. Answer: 4.2 in

13.5- 100 Find the sinA A 5 4 C B 3 Answer

13.5 - 200 Find the cos B A 5 4 C B 3 Answer

13.5 - 300 Solve for x: 28 x 59 Answer

13.5 - 400 Solve for x: 40 72 x Answer

13.5 - 500 Solve for x: x 5 23 Answer

13.5 - 600 Jamie is flying a kite. She let out 40 ft of string and the kite is 28 ft off of the ground. What is the angle of elevation? Answer

13.5 - 100 Answer Find the sinA A 5 4 C B 3 Answer: 3/5

13.5 - 200 Answer Find the cosB A 5 4 C B 3 Answer: 3/5

13.5 - 300 Answer Solve for x: 28 x 59 Answer: x = 24

13.5 - 400 Answer Solve for x: 40 72 x Answer: x = 12.36

13.5 - 500 Answer Solve for x: x 5 23 Answer: x = 12.6°

13.5 - 600 Answer Jamie is flying a kite. She let out 40 ft of string and the kite is 28 ft off of the ground. What is the angle of elevation? Answer: 44.4°