On Desk: Learning Log: HW: p. 20, #1-2, 17, 18

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On Desk: Learning Log: HW: p. 20, #1-2, 17, 18 Math CC7/8 – Be Prepared On Desk: Pencil Calculator Math Journal New S&P Learning Log HW: WS Practice MAD Parent Signatures? Learning Log: HW: p. 20, #1-2, 17, 18 Pass back FW Test-corrections due Friday for ½ credit End of Trimester –Friday! Half Day – next Friday, 3/23

Tasks for Today Discuss HW Finish Lesson 1.1 Pass back FW Test

-67 -90 Warm Up -3 = (-4) = 5 = Use order of operations to solve: 2 -3 = - (3 x 3) = -9 3 (-4) = (-4 x -4 x -4) = -64 3 5 = (5 x 5 x 5) = 125 Use order of operations to solve: -90 -67

Copy down Jun and Mia’s test scores in your journal Yesterday we found that the measures of center, or mean and median for both kids were the same. How do we decide who performed better? Now we need to look at measures of variability – range and MAD! Copy down Jun and Mia’s test scores in your journal

40 = 13.33 3 MAD = mean absolute deviation Range = max – min Find the difference of each data value and the mean. Add all the absolute values of the differences you found together. Divide the sum by the number of data values. The final quotient is the MAD. Range = max – min Range = 100 – 60 Range = 40 80 – 80 + 60 – 80 + 100 – 80 0 + 20 + 20 = 40 3 40 = 13.33 3

10 = 3.33 3 Range = max – min Range = 85 – 75 Range = 10 MAD = mean absolute deviation Find the difference of each data value and the mean. Add all the absolute values of the differences you found together. Divide the sum by the number of data values. The final quotient is the MAD. 75 – 80 + 80 – 80 + 85 – 80 5 + 0 + 5 = 10 3 10 = 3.33 3

Mia’s results are more consistent and Jun’s are more variable. Overall, Mia’s performance is more successful than Jun’s if success is judged on how consistently each student performs. There is probably not enough data since 3 scores each isn’t a large data set.

Several possible answers/reasoning follow…