f(x) x Figure 1 g(z) z Normal distribution for Cholesterol with .4 Normal distribution for Cholesterol with Mean = 219 and SD = 50 .3 f(x) .2 .1 19 69 119 169 219 269 319 369 419 x 200 on N(219, 2500) Maps into -0.38 on N(0,1) Standard normal distribution i.e. mean = 0 and SD = 1 .4 .3 g(z) .2 .1 -1 -4 -3 -2 1 2 3 4 5 6 7 8 9 10 11 12 13 z
Normal distribution with Figure 2 Normal distribution with Mean = 5 and SD = 2 .4 .3 f(x) .2 .1 -3 -1 1 3 5 7 9 11 13 x .4 .3 g(z) 8 is one and a half SD’s (SD = 2) above the mean 5, so 8 maps into 1.5 which is one and a half SD’s (SD = 1) above mean 0. .2 .1 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 10 11 12 13
Normal distribution for Cholesterol Figure 3 Normal distribution for Cholesterol Mean = 219 and SD = 50 N(219,2500) = N(219,502) .4 .3 f(x) .2 .1 19 69 119 169 219 269 319 369 419 x 35% of area under curve 200 .4 .3 . di (200-219)/50 -.38 . di normal(-0.38) .35197271 . di normal((200 - 219)/50) .2 .1 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 10 11 12 13 -0.38 Standard Normal Distribution Mean = 0 and SD = 1
f(x) x Figure 4 35% of area under curve N(219,2500) = N(219,502) .4 .3 f(x) .2 .1 19 69 119 169 219 269 319 369 419 x 35% of area under curve 200 .4 .3 .2 . di invnormal(.35197271) -.37999999 .1 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 10 11 12 13 -0.38 Standard Normal Distribution Mean = 0 and SD = 1