10.3 - Quadratic Applications Do NOW Solve for the following. (x – 3)(x + 8) = 0 (2x – 7)(5x + 9) = 0 x2 – 3x – 10 = 0 Find the roots of the following. 4) 5) x y -3 8 -2 4 -1 -4 1 2/17/2019 10:32 AM 10.3 - Quadratic Applications
10.3 - Quadratic Applications Worksheet Key 2/17/2019 10:32 AM 10.3 - Quadratic Applications
10.3 - Quadratic Applications Worksheet Key 2/17/2019 10:32 AM 10.3 - Quadratic Applications
10.3 - Quadratic Applications Worksheet Key 2/17/2019 10:32 AM 10.3 - Quadratic Applications
Factoring Applications Section 9.5, Revised ©2013, vdang@houstonisd.org 2/17/2019 10:32 AM 10.3 - Quadratic Applications
Quadratic Applications Read the question TWICE Understand the Question Underline key numbers and terms Plug in equation using the graphing calculator When graphing, ALWAYS label the x and y-axis (Remember: y depends on x) Plot out the points from the graphing calculator 2/17/2019 10:32 AM 10.3 - Quadratic Applications
10.3 - Quadratic Applications Review If a rectangle has the length of (x – 4) and width of (x – 4), what is the area? 2/17/2019 10:32 AM 10.3 - Quadratic Applications
10.3 - Quadratic Applications Example 1 A square has an area of x2 – 8x + 16. Find the length and width using tiles. 2/17/2019 10:32 AM 10.3 - Quadratic Applications
10.3 - Quadratic Applications Example 2 A square has an area of x2 + 4x + 4. Find the length of the side. 2/17/2019 10:32 AM 10.3 - Quadratic Applications
10.3 - Quadratic Applications Your Turn A square has an area of x2 – 10x + 25. Find the length of the side. 2/17/2019 10:32 AM 10.3 - Quadratic Applications
10.3 - Quadratic Applications Example 3 A plot of land is rectangular and has an area of x2 – 5x – 24 m2. The length is x + 3 m. Find the width of the plot of land. 2/17/2019 10:32 AM 10.3 - Quadratic Applications
10.3 - Quadratic Applications Example 4 The area of a poster board is x2 + 3x – 10 inches. The width is x – 2 inches. Find the length of the poster board. Then, find the dimensions when x = 14. 2/17/2019 10:32 AM 10.3 - Quadratic Applications
10.3 - Quadratic Applications Your Turn The area of a rectangle is given by A = x2 + 4x – 5 m. Find expressions for the length and width of the rectangle. Then, find the dimensions if x = 10 m. 2/17/2019 10:32 AM 10.3 - Quadratic Applications
10.3 - Quadratic Applications Example 5 The area of a rectangle is 12x2 + 6x. Find the length of the rectangle if the width is 6x. Then find the dimensions if x = 5. 2/17/2019 10:32 AM 10.3 - Quadratic Applications
10.3 - Quadratic Applications Example 6 An antique Persian carpet has an area of x2 + x – 20 ft2 and a length of x + 5 ft. The rug is displayed on a wall in a museum. The wall has a width of x + 2 feet and an area of x2 + 17x + 30 ft2. Write expressions for the length and width of both the rug and wall. Then find the dimensions of the rug and if x = 20 feet. 2/17/2019 10:32 AM 10.3 - Quadratic Applications
10.3 - Quadratic Applications Example 6 An antique Persian carpet has an area of x2 + x – 20 ft2 and a length of x + 5 ft. The rug is displayed on a wall in a museum. The wall has a width of x + 2 feet and an area of x2 + 17x + 30 ft2. Write expressions for the length and width of both the rug and wall. Then find the dimensions of the rug and if x = 20 feet. (x + 15) ft. 2/17/2019 10:32 AM 10.3 - Quadratic Applications
10.3 - Quadratic Applications Example 6 An antique Persian carpet has an area of x2 + x – 20 ft2 and a length of x + 5 ft. The rug is displayed on a wall in a museum. The wall has a width of x + 2 feet and an area of x2 + 17x + 30 ft2. Write expressions for the length and width of both the rug and wall. Then find the dimensions of the rug and if x = 20 feet. (x + 15) ft. 2/17/2019 10:32 AM 10.3 - Quadratic Applications
10.3 - Quadratic Applications Your Turn A carpet has an area of x2 + 5x – 6 ft2 and a length of x + 6 ft. The rug is displayed on a wall in a museum. The wall has a width of x – 2 feet and an area of x2 + 10x – 24 ft2. Write expressions for the length and width of both the rug and wall. Then find the dimensions of the rug and if x = 15 feet. (x – 2) ft. (x + 6) ft. 2/17/2019 10:32 AM 10.3 - Quadratic Applications
10.3 - Quadratic Applications Assignment Worksheet 2/17/2019 10:32 AM 10.3 - Quadratic Applications