Equations – Success if you can do these

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Presentation transcript:

Equations – Success if you can do these 3x = 6 4x + 2 = 3x + 7 x/4 = 2 5x – 3 = 7 + 3x x + 3 = 17 3(x + 2) = 12 x – 4 = 13 4(x + 5) = 32 3x + 4 = 25 3(2x – 2) = 2(x + 6) 4x – 3 = 17 4(3x + 5) = 2(x + 15)

How to solve the Ax = B type of equation The letters A and B can be any number

For example, how to solve 5x = 20 5x = 20 means 5 X x = 20 You get rid of the 5 X by ÷ 5 5 X x ÷ 5 = 20 ÷ 5 x = 4 But you must divide both sides by 5

just divide both sides by that multiplies the x. For equations like 5x = 20 just divide both sides by that multiplies the x. 5x = 20 5x ÷ 5 = 20 ÷ 5 X = 4 Like this

x/C = D type of equation C and D How to solve the The letters can be any number