Lecture 4.4 – Particles to Particles and Complex Stoichiometry

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Presentation transcript:

Lecture 4.4 – Particles to Particles and Complex Stoichiometry

Today’s Learning Targets LT 4.7 – I can convert from particles of one compound to particles of another compound LT 4.8 – I can complete a complex stoichiometric conversion that incorporates molarity, particles, mass, moles, and volumes of substances.

Molarity of Substance A Molarity of Substance B Moles of A Moles of B Grams of Substance B Grams of Substance A Atoms of Substance A Atoms of Substance B

Our Focus for Today Moles of A Moles of B Atoms of Element or Compound B Atoms of Element or Compound A

How do we convert particles of one substance to particles of another substance?

I. Moles to Particles Conversion Factor Our conversion factor for moles  particles is: 6.022 x 1023 particles mole Can be reversed to fit conversion

II. Moles to Particles Between 2 Substances We can utilize what we know about converting between moles to convert between particles for a different substance. We simply follow the same rules and conversion factors

Class Example You react 30 x 1023 particles of HCl for the following reaction: HCl + MnO2  MnCl4 + H2O How many molecules of MnCl4 did you use for this reaction?

Example You react 3 moles of MnO2 for the following reaction: HCl + MnO2  MnCl4 + H2O How many molecules of HCl did you use for this reaction?

NH4SCN + FeCl3NH3(g) + HCl + Fe(SCN) 3 Table Talk For the following reaction: NH4SCN + FeCl3NH3(g) + HCl + Fe(SCN) 3 If you react 4 moles of FeCl3, how many particles of NH3 would you produce?

Table Talk If you react 12 x 1023 particles of MnO2 with HCl in the following reaction: HCl + MnO2  MnCl4 + H2O How many moles of MnCl4 did you use in this reaction?

How do I complete complex stoichiometry problems?

Molarity of Substance A Molarity of Substance B Moles of A Moles of B Grams of Substance B Grams of Substance A Have students fill in all arrows with the necessary conversion factors Atoms of Substance A Atoms of Substance B

(C2OH5)2S + 2 HCl → (C2H4Cl)2S + 2 H2O Class Example You wish to make mustard gas using the reaction: (C2OH5)2S + 2 HCl → (C2H4Cl)2S + 2 H2O If I add 52 g of HCl, then how many particles of H2O will I produce?

Molarity of Substance A Molarity of Substance B Moles of A Moles of B Grams of Substance B Grams of Substance A Have students fill in all arrows with the necessary conversion factors Atoms of Substance A Atoms of Substance B

(C2OH5)2S + 2 HCl → (C2H4Cl)2S + 2 H2O Table Talk You wish to make mustard gas using the reaction: (C2OH5)2S + 2 HCl → (C2H4Cl)2S + 2 H2O If I add 143 g of (C2OH5)2S , then how many grams of (C2H4Cl)2S will I produce?

Molarity of Substance A Molarity of Substance B Moles of A Moles of B Grams of Substance B Grams of Substance A Have students fill in all arrows with the necessary conversion factors Atoms of Substance A Atoms of Substance B

Table Talk You run the Haber – Bosh Reaction to make NH3: N2 + 3H2  2NH3 If you begin with 15 x 1023 particles of H2, then how many grams of NH3 do you produce?

Molarity of Substance A Molarity of Substance B Moles of A Moles of B Grams of Substance B Grams of Substance A Have students fill in all arrows with the necessary conversion factors Atoms of Substance A Atoms of Substance B