Synthesis, Decomposition &Combustion Unit 6 – Lesson 2 Synthesis, Decomposition &Combustion

A + B  AB 1. Synthesis 2 or more reactants form one product Examples Types of chemical reactions 1. Synthesis 2 or more reactants form one product A + B  AB Examples 2 H2 + O2  2 H2O CaO + H2O  Ca(OH)2

Balance the equation: 2Mg + O2 → 2MgO Predict the products of a synthesis reaction between Magnesium and Oxygen. Mg + O2 → MgO Balance the equation: 2Mg + O2 → 2MgO Oxygen is a diatomic! Mg2+ O2- You should NOT balance the equation and predict products at the same time, they are separate processes

Binary because one compound is split into two elements 2. Decomposition 1 reactant forms two or more products Binary because one compound is split into two elements AB  A + B Examples 2 HgO  2 Hg + O2 2 NaCl  2 Na + Cl2 2 Ag₂O  4 Ag + O2 video

Complete the skeleton equations : Use page 6 of your reference packet to identify and predict products of other types of decomposition reactions M means any metal CuCO3  Complete the skeleton equations : Ca(OH)2  KClO3  H2SO4  Ca(HCO3)2  Videos are linked on each picture above CuO + CO2 KCl + O2 CaCO3 + CO2 + H2O SO3 + H2O CaO + H2O

Copper(II) oxide  Copper + Oxygen Copper(II) Oxide will decompose when heated strongly. Give the word and formula equation. Balance the equation Copper(II) oxide  Copper + Oxygen CuO  Cu + O2 2CuO  2Cu + O2

What products will be formed when Al2(CO3)3 decomposes What products will be formed when Al2(CO3)3 decomposes? Balance the equation. Al2(CO3)3  3 CO2 + Al2O3 2 2 Al C O 3 1 3 9 5 9

3. Combustion When a compound (usually a hydrocarbon) reacts with oxygen producing water, carbon dioxide and heat. hydrocarbon  compound made of H & C Examples No hydrocarbon: C2H5OH + 3 O2  2 CO2 + 3 H2O Hydrocarbon: CH4 + 2 O2  CO2 + 2 H2O

Predict the products of the following reaction: C6H14 + O2 → hydrocarbon oxygen Combustion When balancing combustion equations, focus on the hydrocarbon first and match the carbons…… If the equation will not balance with 1 hydrocarbon, make it 2, and so forth. 2 C6H14 + O2 → CO2 + H2O 19 12 6 14 7 12 6 1 C H O 6 12 28 14 2 14 28 38 2 3 13 19 38