Bellwork Tuesday 5.9 L of carbon dioxide is combined with 8.4 g MgO in a synthesis reaction to form magnesium carbonate. How many grams of magnesium carbonate.

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Bellwork Tuesday 5.9 L of carbon dioxide is combined with 8.4 g MgO in a synthesis reaction to form magnesium carbonate. How many grams of magnesium carbonate is created in this reaction?

Unit 8 Ch 12 Part 4 % Yield

Percent Yield Theoretical Yield – The maximum amount of product that could be formed from given amounts of reactants. (What you should get). Actual Yield - amount of product actually obtained in the reaction (What you really get).

% yield = Actual Yield x 100 Theoretical Yield Amount you actually obtain in an experiment % yield = Actual Yield x 100 Theoretical Yield Amount you should obtain in an experiment (this we will calculate)

EXAMPLE If 12.5 g of copper are reacted with an excess of chlorine gas, then 25.4 g of copper(II) chloride, CuCl2(s), are obtained. Calculate the theoretical yield and the percent yield. First write the balanced equation, then find the theoretical yield (amount you “should get”)

First write the balanced equation, then find the theoretical yield (amount you “should get”) Cu + Cl2 → CuCl2 12.5 g Cu 1 mol Cu 1 mol CuCl2 134.5 g CuCl2 63.5 g Cu 1 mol Cu 1 mol CuCl2 GFM mol-mol ratio GFM = 26.5 g CuCl2 this is the theoretical yield

Now do the % yield calculation % yield = Actual Yield x 100 Theoretical Yield given in problem 25.4 g CuCl2 % yield = X 100 = 95.8 % 26.5 g CuCl2 from calculation