Density of a Gas at STP Lesson # 4.

Slides:



Advertisements
Similar presentations
Moles, volume and density
Advertisements

Chapter 9 – Review Stoichiometry
HIGHER GRADE CHEMISTRY CALCULATIONS Molar Volume. The molar volume is the volume occupied by one mole of a gas. Worked example 1. In an experiment the.
Molar & atomic Mass Mole  > particles Mass  > Mole Molar Volume of Gas Gas Density
Chemical Quantities.  Calculate the mass of compounds.  Calculate the molar volumes of gases.  Solve problems requiring conversions between mass, and.
Ch. 3 Stoichiometry: Calculations with Chemical Formulas.
Test Review Chemical Reactions and Stoichiometry.
Lesson 3 Percentage Yield and Energy. Sometimes reactions do not go to completion. Reaction can have yields from 1% to 100%. 1.How many grams of Fe are.
PRACTICE PROBLEMS How many moles of glucose, C 6 H 12 O 6, can be burned when 10.0 mol of oxygen is available? C 6 H 12 O 6 (s) + 6O 2 (g)  6CO 2 (g)
1 Chapter 11 Gases 11.7 Volume and Moles (Avogadro’s Law) Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings.
Percentage Yield and Energy Lesson 3. Sometimes reactions do not go to completion. Reaction can have yields from 1% to 100%. 1.How many grams of Fe are.
GAS DENSITY AND AVAGODRO’S LAW ONE MOLE OF ANY GAS OCCUPIES A VOLUME OF 22.4 LITERS AT STP. 1.GAS PRESSURE IS A COLLIGATIVE PROPERTY AT STP. 2.COLLIGATIVE:
Density of a Gas at STP Lesson # 4. 1.Calculate the density of N 2 at STP. Calculate Density=grams litre Assume that you have 1 mole of N 2.
Percentage Yield.
Remembering: Molarity and Stoichiometry Because we know you brain is getting full!!!
Stoichiometry Chapter 10.
Percent Yield. Definitions The theoretical yield is the maximum amount of product that could be made from the reactants. The actual yield is the amount.
Density of a Gas at STP Lesson # 4. 1.Calculate the density of N 2 at STP. Assume that you have 1 mole of N L 28.0 g =1.25 g/L litre grams Density=
WARM UP The reaction of iron ore with carbon follows the equation: 2 Fe 2 O C  4 Fe + 3 CO 2. How many moles of Fe can be produced from 37 moles.
Stoichiometry Review 1.Write the equation for a reaction between Ca(OH) 2 and NaCl Unbalanced: Ca(OH) 2 + NaCl  CaCl 2 + NaOH Balanced: 1 Ca(OH)
Mole Measures Problems Random Vocab. $100 $200 $300 $400 $500 $400 $500.
7.7 Volume and Moles (Avogadro’s Law)
Chapter 12 Review “Stoichiometry”
7.3 Percentage Yield.
Molar Volume and Density Problems
Calculations based on Chemical Equations
Stoichiometry with a Twist
7.5 Percentage Yield.
Stoichiometry 1. Mole - mole 2. Mole - mass 3. Mass - mole
Stoichiometry Lesson 1.
Gram to moles to moles to Grams pg 8
Unit 8 Chemical Quantities.
10.5 NOTES Avogadro Molar Volumes
Equation Calculations
Calculations with Equations
Chapter 12 Review “Stoichiometry”
Ch. 10 Chemical Quantities
Stoichiometry Quiz Please take a card from the front
Percentage Yield and Energy Lesson 3.
Chapter 5 Chemical Reactions and Quantities
Density of a Gas at STP Lesson # 4.
Calculations Based on Chemical Equations
2.50g C2H4 x 1 mole C2H4 x 2 mol CO2 x 22.4 L at STP = 4.00 L at STP
Stoichiometry w/Volume
Stoichiometry Lesson 1.
Chapter 8 Chemical Quantities in Reactions
3.3 The Molar Volume Pages
Volume and Moles (Avogadro’s Law)
Chapter 6 Chemical Reactions and Quantities
Stoichiometry w/Volume
Chapter 12 Stoichiometry 12.2 Chemical Calculations
Chapter 12 Stoichiometry 12.2 Chemical Calculations
Molar Volume of a Gas at STP Lesson 2.
Lesson 3 Percentage Yield and Energy.
REVIEW 12/11, MOLES For the combustion reaction
Stoichiometry Lesson # 1.
Stoichiometry w/Volume
Students type their answers here
Calculations Based on Chemical Equations
Moles, Volume and Density
Calculations with Moles
Chapter 12 Stoichiometry 12.2 Chemical Calculations
Stoichiometry.
Stoichiometry.
10.2 Molar Relationships.
Limiting Reagents Problem: Find the amount of cakes we can make when we have 4 sticks of butter and 50 cups of flour. 1 Butter + 2 Flour -> 1 Cake We.
C2H6 CH3 B. Empirical Formula
Moles practice Q’s Ch 10 Pearson.
Percentage Yields.
Chapter 5 Chemical Quantities and Reactions
Presentation transcript:

Density of a Gas at STP Lesson # 4

1. Calculate the density of N2 at STP. Calculate Density = grams litre Assume that you have 1 mole of N2

1. Calculate the density of N2 at STP. Calculate Density = grams litre 28.0 g = Assume that you have 1 mole of N2

1. Calculate the density of N2 at STP. Calculate Density = grams litre 28.0 g = 22.4 L Assume that you have 1 mole of N2

1. Calculate the density of N2 at STP. Calculate Density = grams litre 28.0 g = 1.25 g/L 22.4 L Assume that you have 1 mole of N2

2. Calculate the density of CO2 at STP. Density = grams litre Assume that you have 1 mole of CO2

2. Calculate the density of CO2 at STP. Calculate Density = grams litre 44.0 g = Assume that you have 1 mole of CO2

2. Calculate the density of CO2 at STP. Calculate Density = grams litre 44.0 g = 22.4 L Assume that you have 1 mole of CO2

2. Calculate the density of CO2 at STP. Calculate Density = grams litre 44.0 g = 1.96 g/L 22.4 L Assume that you have 1 mole of CO2

3. Calculate the volume of O2 gas produced at STP for the 3. Calculate the volume of O2 gas produced at STP for the complete decomposition of 12.5 g HgO if the yield is 45.0 %. 2HgO → 2Hg + O2 12.5 g ? L 1 2

3. Calculate the volume of O2 gas produced at STP for the 3. Calculate the volume of O2 gas produced at STP for the complete decomposition of 12.5 g HgO if the yield is 45.0 %. 2HgO → 2Hg + O2 12.5 g ? L 12.5 g HgO x 1mole 216.6g

3. Calculate the volume of O2 gas produced at STP for the 3. Calculate the volume of O2 gas produced at STP for the complete decomposition of 12.5 g HgO if the yield is 45.0 %. 2HgO → 2Hg + O2 12.5 g ? L 12.5 g HgO x 1mole x 1 mole O2 216.6g 2 mole HgO

3. Calculate the volume of O2 gas produced at STP for the 3. Calculate the volume of O2 gas produced at STP for the complete decomposition of 12.5 g HgO if the yield is 45.0 %. 2HgO → 2Hg + O2 12.5 g ? L 12.5 g HgO x 1mole x 1 mole O2 x 22.4 L 216.6g 2 mole HgO 1 mole

3. Calculate the volume of O2 gas produced at STP for the 3. Calculate the volume of O2 gas produced at STP for the complete decomposition of 12.5 g HgO if the yield is 45.0 %. 2HgO → 2Hg + O2 12.5 g ? L 12.5 g HgO x 1mole x 1 mole O2 x 22.4 L x 0.450 216.6g 2 mole HgO 1 mole

3. Calculate the volume of O2 gas produced at STP for the 3. Calculate the volume of O2 gas produced at STP for the complete decomposition of 12.5 g HgO if the yield is 45.0 %. 2HgO → 2Hg + O2 12.5 g ? L 12.5 g HgO x 1mole x 1 mole O2 x 22.4 L x 0.450 = 0.291 L 216.6g 2 mole HgO 1 mole

4. How many litres of CO2 are produced by the reaction of 100. g 4. How many litres of CO2 are produced by the reaction of 100. g of Fe2O3, if the actual yield was 19.0 L @ STP, calculate the percentage yield. 19.0 L 2Fe2O3 + 3C  4Fe + 3CO2 100. g ? L 3 2

4. How many litres of CO2 are produced by the reaction of 100. g 4. How many litres of CO2 are produced by the reaction of 100. g of Fe2O3, if the actual yield was 19.0 L @ STP, calculate the percentage yield. 19.0 L 2Fe2O3 + 3C  4Fe + 3CO2 100. g ? L 100. g Fe2O3 x 1 mole x 3 mole CO2 x 22.4 L = 21.05 L 159.6 g 2 mole Fe2O3 1 mole Percentage yield = 19.0 L x 100% = 90.3 % 21.05 L 3 2