The product of 3x5  2x4 is 6x20 6x9 5x20 5x9

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Presentation transcript:

The product of 3x5  2x4 is 6x20 6x9 5x20 5x9 UNIT 1 – RATIONAL NUMBERS, EXPONENTS AND SQUARE ROOTS Exponents: Product Rule (Algebra 1.1) The product of 3x5  2x4 is 6x20 6x9 5x20 5x9

6 The product of 3x5  2x4 is 6x20 6x9 5x20 5x9 UNIT 1 – RATIONAL NUMBERS, EXPONENTS AND SQUARE ROOTS Exponents: Product Rule (Algebra 1.1) The product of 3x5  2x4 is 6x20 6x9 5x20 5x9 To find the product of two exponential expressions, first multiply their coefficients, 3 and 2, to get 6. 6

6x9 The product of 3x5  2x4 is 6x20 6x9 5x20 5x9 UNIT 1 – RATIONAL NUMBERS, EXPONENTS AND SQUARE ROOTS Exponents: Product Rule (Algebra 1.1) The product of 3x5  2x4 is 6x20 6x9 5x20 5x9 To find the product of two exponential expressions, first multiply their coefficients, 3 and 2, to get 6. Next, add the exponents of the x terms, 5 and 4, and keep the base, x. The correct answer is B 6x9

UNIT 1 – RATIONAL NUMBERS, EXPONENTS AND SQUARE ROOTS Exponents: Product Rule (Algebra 1.1) The expression 23  42 is equivalent to 212 86 27 85

UNIT 1 – RATIONAL NUMBERS, EXPONENTS AND SQUARE ROOTS Exponents: Product Rule (Algebra 1.1) The expression 23  42 is equivalent to 212 86 27 85 This problem is tougher than the last one. The bases are different, and as you know, we can’t usually multiply exponential terms with different bases. But this is a special case, because 4 is a power of 2. It’s really just 22. So if we expand 42 into 22  22, we now have like terms that we can combine in multiplication. 23  22  22

UNIT 1 – RATIONAL NUMBERS, EXPONENTS AND SQUARE ROOTS Exponents: Product Rule (Algebra 1.1) The expression 23  42 is equivalent to 212 86 27 85 When we add the exponents of these now like terms, (3 + 2 + 2) we get 7 as the new exponent in the product, with 2 as the base. 23  22  22 The correct answer is C, or 27.