CS152 Computer Architecture and Engineering Lecture 16 Compiler Optimizations (Cont) Dynamic Scheduling with Scoreboards.

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Presentation transcript:

CS152 Computer Architecture and Engineering Lecture 16 Compiler Optimizations (Cont) Dynamic Scheduling with Scoreboards

The Big Picture: Where are We Now? The Five Classic Components of a Computer Today’s Topics: Recap last lecture Hardware loop unrolling with Tomasulo algorithm Administrivia Speculation, branch prediction Reorder buffers Control Datapath Memory Processor Input Output So where are in in the overall scheme of things. Well, we just finished designing the processor’s datapath. Now I am going to show you how to design the control for the datapath. +1 = 7 min. (X:47)

Scoreboard: a bookkeeping technique Out-of-order execution divides ID stage: 1. Issue—decode instructions, check for structural hazards 2. Read operands—wait until no data hazards, then read operands Scoreboards date to CDC6600 in 1963 Instructions execute whenever not dependent on previous instructions and no hazards. CDC 6600: In order issue, out-of-order execution, out- of-order commit (or completion) No forwarding! Imprecise interrupt/exception model for now

Scoreboard Architecture(CDC 6600) FP Mult FP Mult FP Divide Registers Functional Units FP Add Integer SCOREBOARD Memory

Scoreboard Implications Out-of-order completion => WAR, WAW hazards? Solutions for WAR: Stall writeback until registers have been read Read registers only during Read Operands stage Solution for WAW: Detect hazard and stall issue of new instruction until other instruction completes No register renaming! Need to have multiple instructions in execution phase => multiple execution units or pipelined execution units Scoreboard keeps track of dependencies between instructions that have already issued. Scoreboard replaces ID, EX, WB with 4 stages

Four Stages of Scoreboard Control Issue—decode instructions & check for structural hazards (ID1) Instructions issued in program order (for hazard checking) Don’t issue if structural hazard Don’t issue if instruction is output dependent on any previously issued but uncompleted instruction (no WAW hazards) Read operands—wait until no data hazards, then read operands (ID2) All real dependencies (RAW hazards) resolved in this stage, since we wait for instructions to write back data. No forwarding of data in this model!

Four Stages of Scoreboard Control Execution—operate on operands (EX) The functional unit begins execution upon receiving operands. When the result is ready, it notifies the scoreboard that it has completed execution. Write result—finish execution (WB) Stall until no WAR hazards with previous instructions: Example: DIVD F0,F2,F4 ADDD F10,F0,F8 SUBD F8,F8,F14 CDC 6600 scoreboard would stall SUBD until ADDD reads operands

Three Parts of the Scoreboard Instruction status: Which of 4 steps the instruction is in Functional unit status:—Indicates the state of the functional unit (FU). 9 fields for each functional unit Busy: Indicates whether the unit is busy or not Op: Operation to perform in the unit (e.g., + or –) Fi: Destination register Fj,Fk: Source-register numbers Qj,Qk: Functional units producing source registers Fj, Fk Rj,Rk: Flags indicating when Fj, Fk are ready Register result status—Indicates which functional unit will write each register, if one exists. Blank when no pending instructions will write that register What you might have thought 1. 4 stages of instruction executino 2.Status of FU: Normal things to keep track of (RAW & structura for busyl): Fi from instruction format of the mahine (Fi is dest) Add unit can Add or Sub Rj, Rk - status of registers (Yes means ready) Qj,Qk - If a no in Rj, Rk, means waiting for a FU to write result; Qj, Qk means wihch FU waiting for it 3.Status of register result (WAW &WAR)s: which FU is going to write into registers Scoreboard on 6600 = size of FU 6.7, 6.8, 6.9, 6.12, 6.13, 6.16, 6.17 FU latencies: Add 2, Mult 10, Div 40 clocks

Scoreboard Example

Detailed Scoreboard Pipeline Control Read operands Execution complete Instruction status Write result Issue Rj and Rk Functional unit done Wait until f((Fj(f)≠Fi(FU) or Rj(f)=No) & (Fk(f) ≠Fi(FU) or Rk( f )=No)) Not busy (FU) and not result(D) Bookkeeping Rj No; Rk No f(if Qj(f)=FU then Rj(f) Yes); f(if Qk(f)=FU then Rj(f) Yes); Result(Fi(FU)) 0; Busy(FU) No Busy(FU) yes; Op(FU) op; Fi(FU) `D’; Fj(FU) `S1’; Fk(FU) `S2’; Qj Result(‘S1’); Qk Result(`S2’); Rj not Qj; Rk not Qk; Result(‘D’) FU; 1.Issue - if no structural haards AND non wAW (no Funtional Unit is going to write this destination register; 1 per clock cycle 2. Read -(RAW) if no instructions is going to write a source register of this instruction (alternatively, no write signal this clock cycle) +> gein exection of the instruction; many read ports, so can read many times 3. Execution Complete; multiple during clock cyle 4. Write result - (WAR) If no instructiion is watiing to read the destination register; assume multiple wriite ports; wait for clock cycle to write and tehn read the results; assume can oerlap issue & write show clock cyclesneed 20 or so Latency: minimum is 4 through 4 stages

Scoreboard Example: Cycle 1

Scoreboard Example: Cycle 2 Issue 2nd LD?

Scoreboard Example: Cycle 3 Issue MULT?

Scoreboard Example: Cycle 4

Scoreboard Example: Cycle 5

Scoreboard Example: Cycle 6

Scoreboard Example: Cycle 7 Read multiply operands?

Scoreboard Example: Cycle 8a (First half of clock cycle)

Scoreboard Example: Cycle 8b (Second half of clock cycle)

Scoreboard Example: Cycle 9 Note Remaining Read operands for MULT & SUB? Issue ADDD?

Scoreboard Example: Cycle 10

Scoreboard Example: Cycle 11

Scoreboard Example: Cycle 12 Read operands for DIVD?

Scoreboard Example: Cycle 13

Scoreboard Example: Cycle 14

Scoreboard Example: Cycle 15

Scoreboard Example: Cycle 16

Scoreboard Example: Cycle 17 WAR Hazard! Why not write result of ADD???

Scoreboard Example: Cycle 18

Scoreboard Example: Cycle 19

Scoreboard Example: Cycle 20

Scoreboard Example: Cycle 21 WAR Hazard is now gone...

Scoreboard Example: Cycle 22

Faster than light computation (skip a couple of cycles)

Scoreboard Example: Cycle 61

Scoreboard Example: Cycle 62

Review: Scoreboard Example: Cycle 62 In-order issue; out-of-order execute & commit

Limitations of 6600 scoreboard: CDC 6600 Scoreboard Speedup 1.7 from compiler; 2.5 by hand BUT slow memory (no cache) limits benefit Limitations of 6600 scoreboard: No forwarding hardware Limited to instructions in basic block (small window) Small number of functional units (structural hazards), especially integer/load store units Do not issue on structural hazards Wait for WAR hazards Prevent WAW hazards

Summary #1/2: Compiler techniques for parallelism Loop unrolling  Multiple iterations of loop in software: Amortizes loop overhead over several iterations Gives more opportunity for scheduling around stalls Software Pipelining  Take one instruction from each of several iterations of the loop Software overlapping of loop iterations Today will show hardware overlapping of loop iterations Very Long Instruction Word machines (VLIW)  Multiple operations coded in single, long instruction Requires sophisticated compiler to decide which operations can be done in parallel Trace scheduling  find common path and schedule code as if branches didn’t exist (+ add “fixup code”) All of these require additional registers

Summary #2/2 HW exploiting ILP Works when can’t know dependence at compile time. Code for one machine runs well on another Key idea of Scoreboard: Allow instructions behind stall to proceed (Decode => Issue instr & read operands) Enables out-of-order execution => out-of-order completion ID stage checked both for structural & data dependencies Original version didn’t handle forwarding. No automatic register renaming