Find: FR [kN] on the door Twater= 30 C 1.5 [m] door water wall 1 [m] hinge door 14.7 17.1 25.7 36.7 1.5 [m] Find the reaction force on the the door, in kiloNewtons. [pause]. In this problem, water is filled to a depth of --- FR

Find: FR [kN] on the door Twater= 30 C 1.5 [m] door water wall 1 [m] hinge door 14.7 17.1 25.7 36.7 1.5 [m] 2.5 meters, where the bottom 1.5 meters, --- FR

Find: FR [kN] on the door Twater= 30 C 1.5 [m] door water wall 1 [m] hinge door 14.7 17.1 25.7 36.7 1.5 [m] is held back by a door, and the top meter is held back, --- FR

Find: FR [kN] on the door Twater= 30 C 1.5 [m] door water wall 1 [m] hinge door 14.7 17.1 25.7 36.7 1.5 [m] by a wall, where, the door and the wall are connected by a hinge --- FR

Find: FR [kN] on the door Twater= 30 C 1.5 [m] door water wall 1 [m] hinge door 14.7 17.1 25.7 36.7 1.5 [m] [pause]. The temperature of the water is given as, --- FR

Find: FR [kN] on the door Twater= 30 C 1.5 [m] door water wall 1 [m] hinge door 14.7 17.1 25.7 36.7 1.5 [m] 30 degrees celsius, and the door measures --- FR

Find: FR [kN] on the door Twater= 30 C 1.5 [m] door water wall 1 [m] hinge door 14.7 17.1 25.7 36.7 1.5 [m] 1 meter wide, by 1.5 meters tall. [pause] The reaction force, --- FR

Find: FR [kN] on the door FR = PC *A water wall 1.0 [m] 1 [m] hinge F R, equals, P C, times A. Where P C, represents, ----- hinge door 1.5 [m] 1.5 [m] door FR o Twater= 30 C

Find: FR [kN] on the door FR = PC *A reaction force centroidal pressure water wall 1 [m] 1.0 [m] the pressure at the centroid of the door, and A represents, --- hinge door 1.5 [m] 1.5 [m] door FR o Twater= 30 C

Find: FR [kN] on the door FR = PC *A area reaction force centroidal pressure water wall 1 [m] 1.0 [m] the area of the door. [pause] The door is the shape of a rectangle, --- hinge door 1.5 [m] 1.5 [m] door FR o Twater= 30 C

Find: FR [kN] on the door FR = PC *A area reaction force centroidal pressure water wall 1 [m] 1.0 [m] so we can calculate the area of the door by mulitiplying , --- hinge door 1.5 [m] 1.5 [m] door FR o Twater= 30 C

Find: FR [kN] on the door FR = PC *A area reaction force centroidal pressure Adoor= wdoor * hdoor water wall 1 [m] 1.0 [m] the width of the door by the height of the door, which equals, --- hinge door 1.5 [m] 1.5 [m] door FR o Twater= 30 C

Find: FR [kN] on the door FR = PC *A area reaction force centroidal pressure Adoor= 1.5 [m2] Adoor= wdoor * hdoor water wall 1 [m] 1.0 [m] 1.5 meters squared. [pause] The pressure acting upon, --- hinge door 1.5 [m] 1.5 [m] door FR o Twater= 30 C

Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A reaction force PC = ρ * g * yC water wall 1 [m] 1.0 [m] the centroid of the door, equals, rho, g, y c. In this equation, --- hinge door 1.5 [m] 1.5 [m] door FR o Twater= 30 C

Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A reaction force PC = ρ * g * yC centroidal pressure density water wall 1 [m] 1.0 [m] rho represents, density, [pause] g represents, --- hinge door 1.5 [m] 1.5 [m] door FR o Twater= 30 C

Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A acceleration reaction force PC = ρ * g * yC centroidal pressure density water wall 1 [m] 1.0 [m] the gravitational acceleration constant, and y c represents, hinge door 1.5 [m] 1.5 [m] door FR o Twater= 30 C

Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A acceleration reaction force PC = ρ * g * yC centroidal pressure depth density to centroid water 1 [m] 1.0 [m] the depth from the surface of the water, to the centroid of the door. We can look up the density of water --- yC 1.5 [m] 1.5 [m] door FR door o Twater= 30 C

Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A acceleration reaction force PC = ρ * g * yC centroidal pressure depth density to centroid water temperature water density 1 [m] o 25 C 997.1 [kg/m3] from a table, for different temperatures. Sinece we’ve been given the water is --- yC o 30 C 995.7 [kg/m3] 1.5 [m] o 40 C 992.3 [kg/m3] FR o Twater= 30 C

Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A acceleration reaction force PC = ρ * g * yC centroidal pressure depth density to centroid water temperature water density 1 [m] o 25 C 997.1 [kg/m3] 30 degrees celcius, then we’ll use a water density of, --- yC o 30 C 995.7 [kg/m3] 1.5 [m] o 40 C 992.3 [kg/m3] FR o Twater= 30 C

Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A acceleration reaction force PC = ρ * g * yC centroidal pressure depth density to centroid water temperature water density 1 [m] o 25 C 997.1 [kg/m3] 995.7 kilograms per meters cubed. In metric units, the acceleration, ---- yC o 30 C 995.7 [kg/m3] 1.5 [m] o 40 C 992.3 [kg/m3] FR o Twater= 30 C

Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A acceleration reaction force PC = ρ * g * yC centroidal pressure density 9.81 [m/s2] water temperature water density 1 [m] o 25 C 997.1 [kg/m3] g, equals 9.81 meters per second squared. And the depth to the centroid, y c, --- yC o 30 C 995.7 [kg/m3] 1.5 [m] o 40 C 992.3 [kg/m3] FR o Twater= 30 C

Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A reaction 9.81 [m/s2] force PC = ρ * g * yC centroidal pressure depth ρ= 995.7 [kg/m3] to centroid water yC = y1 + y2 y1 1 [m] yC 1.0 [m] equals the depth from the water surface, to the hinge, plus, --- y2 1.5 [m] 1.5 [m] door FR

Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A reaction 9.81 [m/s2] force PC = ρ * g * yC centroidal pressure depth ρ= 995.7 [kg/m3] to centroid water yC = y1 + y2 y1 1 [m] yC 1.0 [m] the vertical distance from the hinge, to the centroid of the door. 1 meter, plus, --- y2 1.5 [m] 1.5 [m] door FR

Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A reaction 9.81 [m/s2] force PC = ρ * g * yC centroidal pressure depth ρ= 995.7 [kg/m3] to centroid water yC = y1 + y2 y1 1 [m] yC 1.0 [m] half the door height, which is 0.75 meters, equals, --- y2=dheight/2 y2 1.5 [m] 1.5 [m] door FR y2=0.75 [m]

Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A reaction 9.81 [m/s2] force PC = ρ * g * yC centroidal pressure ρ= 995.7 [kg/m3] yc=1.75 [m] water yC = y1 + y2 y1 1 [m] yC 1.0 [m] a depth to centroid, of, 1.75 meters. [pause] This makes the centroidal pressure, P c, --- y2=dheight/2 y2 1.5 [m] 1.5 [m] door FR y2=0.75 [m]

Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A reaction 9.81 [m/s2] force PC = ρ * g * yC centroidal pressure ρ= 995.7 [kg/m3] yc=1.75 [m] water PC = 17,094 [kg/m*s2] y1 1 [m] yC equal to 17,094 kilogram per meter second squared. [pause] When plugged in for variable P c, --- y2 1.5 [m] door FR

Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A reaction 9.81 [m/s2] force PC = ρ * g * yC centroidal pressure ρ= 995.7 [kg/m3] yc=1.75 [m] water PC = 17,094 [kg/m*s2] y1 1 [m] yC this makes the reaction force on the door equal to, --- y2 1.5 [m] door FR

Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A reaction 9.81 [m/s2] force PC = ρ * g * yC centroidal pressure ρ= 995.7 [kg/m3] yc=1.75 [m] water PC = 17,094 [kg/m*s2] y1 1 [m] yC 25,641 kilogram meters per second squred. After converting to units of kiloNewtons, --- FR = 25,641 [kg*m/s2] y2 1.5 [m] FR

Find: FR [kN] on the door * Adoor= 1.5 [m2] FR = PC *A reaction 9.81 [m/s2] force PC = ρ * g * yC centroidal pressure ρ= 995.7 [kg/m3] yc=1.75 [m] water PC = 17,094 [kg/m*s2] y1 1 [m] yC FR = 25,641 [kg*m/s2] the reaction force on the door equals, --- y2 kN*s2 1 1.5 [m] * 1,000 kg*m FR

Find: FR [kN] on the door * Adoor= 1.5 [m2] FR = PC *A reaction 9.81 [m/s2] force PC = ρ * g * yC centroidal pressure ρ= 995.7 [kg/m3] yc=1.75 [m] water PC = 17,094 [kg/m*s2] y1 1 [m] yC FR = 25,641 [kg*m/s2] 25.6 kiloNewtons. [pause] y2 kN*s2 1 1.5 [m] * 1,000 kg*m FR FR = 25.6 [kN]

Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A reaction 9.81 [m/s2] force PC = ρ * g * yC centroidal pressure ρ= 995.7 [kg/m3] yc=1.75 [m] water 14.7 17.1 25.7 36.7 y1 1 [m] yC When reviewing the possible solutions, --- y2 1.5 [m] FR FR = 25.6 [kN]

Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A reaction 9.81 [m/s2] force PC = ρ * g * yC centroidal pressure ρ= 995.7 [kg/m3] yc=1.75 [m] water 14.7 17.1 25.7 36.7 y1 1 [m] yC the answer is C. [fin] answerC y2 1.5 [m] FR FR = 25.6 [kN]

* ΔP13=-ρA* g * (hAB-h1)+… depth to centroid kg*cm3 1,000 g * m3 a monometer contains 5 different fluids, which include, --- kg*cm3 1,000 * g * m3