M4A1 Carbine Round type Round mass (g) Range (m) Muzzle velocity (m/s)

Slides:

Advertisements

Similar presentations

Problem A small 200-g collar C can slide on a

Advertisements

By Kevin Renner.  Every civilization has had developed some sort of armor  But it’s purpose has remained unchanged.

Infantry Common Skills ICS0100 M16A4 SERVICE RIFLE United States Marine Corps Training Command ICS0100, Chart 1 20 July 05.

A look at a firearm, Barrett M caliber sniper rifle By Dustin Mortsolf.

JAN 2014 TACP 027 THREAT ID AND WEZ. JAN 2014 TACP 027 ROLAND II  RANGE: 3.4 NM  ALT: FT  Detection range:16.5 KM.

Acceleration. MEANING FORMULA = A = Acceleration V f = V i = t=

Newton’s Second Law of Motion Chapter 4, Section 3 Pg

Force, Mass and Momentum. Newton’s Second Law: F = ma 1 newton = 1 kg ∙ 1 m/s² Force: 1 pound = 4.45 newtons Your weight is the force of gravity: F =

Newton’s Second Law of Motion

1.2 Order of Operations and Evaluating Expressions: Power: Has two parts, the base and exponent ( b 2  b = base, 2 = exponent ) Exponent: The number that.

 He was born in Russia,in November 10, 1919.Now he is 90 year. when he was young, so he was in the Soviet Army. He wanted to make a weapon that is effective,

Motion Revision Quiz questions. Round 1 1.Which of the following is a scalar measurement? displacement distance velocity.

Warm Up  1. Find the range of a 4 kg projectile launched at a 45 degree angle with an initial velocity of 7 m/s.  2. Define Force.

How to Calculate Net Force

U.S. INFANTRY WEAPON SYSTEMS

Forces Chapter 6.1. What You Already Learned Velocity is the ratio of the change in position of an object over a period of time. Acceleration describes.

My Fact Files. CONTENTS 1.My Personal Favourites 2.Rocket Launchers 3.Tanks 4.Machine Guns 5.Pistols 6.BOMBS 7.The End.

1) If drag is 26,400 N and the lift is 29,300 N, determine the weight, mass and thrust, given that the plane is traveling at a constant velocity. What.

With Ms. Fleming $100 $200 $300 $400 $500 $100 $200 $300 $400 $500 $100 $200 $300 $400 $500 $100 $200 $300 $400 $500 $100 $200 $300 $400.

Myles Stover EDT 180i (Summer 13) Arizona State University 1.

An Introduction to engineering analysis

Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley Newton’s Second Law Physics 102 Goderya Chapter(s): 4 Learning Outcomes:

Coefficient of Friction The force of friction is directly proportional to the normal force. When we increase the mass or acceleration of an object we also.

With Ms. Patterson $100 $200 $300 $400 $500 $100 $200 $300 $400 $500 $100 $200 $300 $400 $500 $100 $200 $300 $400 $500 $100 $200 $300 $400.

Momentum Conservation Chapter 8: Momentum Conservation K = (1/2) m v 2 Work-Energy Theorem Energy Conservation p = m v Impulse-Momentum Theorem Momentum.

Semi-Automatic Handguns A Brief Introduction & History 1893-Present.

With Ms. Doolittle $100 $200 $300 $400 $500 $100 $200 $300 $400 $500 $100 $200 $300 $400 $500 $100 $200 $300 $400 $500 $100 $200 $300 $400.

Kinetic Energy m s F v E k = 1 / 2 mv 2 E k - Kinetic energy v - velocity m - mass.

6. Flow of fluids and Bernoulli’s equation.

PHYSICS CLASS ACTIVITY. C.A.: Vo of Marble Launcher.

Sample Impulse Problem A 0

Notes: Forces Big “G” and little “g” Newton’s Law of Universal Gravity -F g, the force of attraction between two objects is directly proportional to the.

Impulse = F  t = m  v F = Force (N)  t = Elapsed time (s) m = Mass (kg)  v = Change in velocity (m/s) Force, time, mass, and  velocity Example: A.

With Ms. Jones $100 $200 $300 $400 $500 $100 $200 $300 $400 $500 $100 $200 $300 $400 $500 $100 $200 $300 $400 $500 $100 $200 $300 $400 $500.

F = ma F = Force m = Mass a = Acceleration. The Manned Manoeuvring Unit.

Defence Academy of the United Kingdom Royal Military College of Science Lt Col C J Finch PARA DS Light Weapons.

F = ma.  When forces are balanced…  Fnet = 0  At rest or  Moving at a constant velocity  Newton’s 1 st law applies  What happens if the forces are.

Acceleration Acceleration is the rate of change of velocity.

Problem 6 V terminal = mg / b = (70kg)(9.8m/s^2) / 0.13 Ns^/m^2 = 5277 m/s Problem 1 If we assume that a salt shaker holds about 1/2 cup of salt than this.

Significant figures A significant figure represents an actual measurement A measurement of all the digits known with certainty, plus one that is estimated.

The reading is 7.38 mm. The reading is 7.72 mm.

Velocity vs time graph Calculating the area under the graph.

Formula Momentum (p) = Mass x velocity Unit is kgm/s.

Significant figures A significant figure represents an actual measurement A measurement of all the digits known with certainty, plus one that is estimated.

Coefficient of Friction

SW Series The SW series are fast, non-latching MEMS switches available both for single mode and multimode fibers. They are available in configurations.

I can solve for a bunch more stuff Fg= 400 N θ = 40° Fg = mg

Notes 2.2: Newton’s 2nd Law of Motion

Mass and Weight Standards 1.3.

Find the velocity of a particle with the given position function

Action and Reaction.

نحو مفهوم شامل للجودة ومتطلبات التأهيل للأيزو

AP Physics Chapter 4 Answers

until an unbalanced force acts on it!!

Find the velocity of a particle with the given position function

MOMENTUM (p) is defined as the product of the mass and velocity -is based on Newton’s 2nd Law F = m a F = m Δv t F t = m Δv IMPULSE MOMENTUM.

A velocity selector consists of magnetic and electric fields

What is Motion? Motion: A change in position of an object compared to a reference point Motion can be measured in the following ways:

THREAT ID AND WEZ.

Notes Over 8.3 Simplifying Natural Base Expressions

This waveform is 35.0 cm long. How long is the wavelength?

Pistol Caliber Carbine Classifier Score Sheet

3. a. What is the force of gravity between a 2

1) BEFORE AFTER 2) BEFORE AFTER

AP Forces Review Problem Set Answers

Force, time, mass, and velocity

What I expect to see in Skyline

Consider 7.0 kg mass pulled with a force of 60 N up an incline with an angle of 15º. The coefficient of friction between the surfaces is Given:

Presentation transcript:

M4A1 Carbine Round type Round mass (g) Range (m) Muzzle velocity (m/s) 5.56×45mm NATO 4.1 500-600 936

Desert Eagle Round type Round mass (g) Range (m) Muzzle velocity (m/s) .50 Action Express 21.1 50 430

Arctic Warfare Round type Round mass (g) Range (m) Muzzle velocity (m/s) 7.62×51mm NATO 11.3 800 790

Avtomat Kalashnikova (AK47) Round type Round mass (g) Range (m) Muzzle velocity (m/s) 7.62×39mm 8.0 400 641

Beretta 92 Round type Round mass (g) Range (m) Muzzle velocity (m/s) .40 S&W 10.7 50 350

FN P90 Round type Round mass (g) Range (m) Muzzle velocity (m/s) FN 5.7x28mm 2.0 200 716