2.1(c) Notes: Quadratic Functions Date: 2.1(c) Notes: Quadratic Functions   Lesson Objective: Find the maximum or minimum, the A/S and y-intercept from a quadratic equation CCSS: A.SSE.3a, A.REI.1 You will need: a calculator This is Jeopardy!!!: This is the graph of y = 4x² – 4x + 1.

Direction, +a up, -a down: y-int, f(0) = c: A/S: x = −b 2a = Lesson 1: Using a, b and c Find the direction, the y-intercept, the equation of the A/S, the vertex, and the domain and range. Deter-mine whether it has a maximum or a minimum. #6 y = 4x² – 4x + 1 Direction, +a up, -a down: y-int, f(0) = c: A/S: x = −b 2a = V: −b 2a , 𝑓 −b 2a = Max or Min: y = Domain: {x| } Range: {y| }

Direction, +a up, -a down: y-int, f(0) = c: A/S: x = −b 2a = Lesson 1: Using a, b and c Find the direction, the y-intercept, the equation of the A/S, the vertex, and the domain and range. Deter-mine whether it has a maximum or a minimum. #5 y = -2x² – 8x – 5 Direction, +a up, -a down: y-int, f(0) = c: A/S: x = −b 2a = V: −b 2a , 𝑓 −b 2a = Max or Min: y = 𝑓 −b 2a Domain: {x| } Range: {y| }

Direction, +a up, -a down: y-int, f(0) = c: A/S: x = −b 2a = Lesson 1: Using a, b and c Find the direction, the y-intercept, the equation of the A/S, the vertex, and the domain and range. Deter-mine whether it has a maximum or a minimum. #4 y = x² – 9 Direction, +a up, -a down: y-int, f(0) = c: A/S: x = −b 2a = V: −b 2a , 𝑓 −b 2a = Max or Min: y = Domain: {x| } Range: {y| }

Lesson 1: Using a, b and c #9 y = 3 2 x² + 4x – 9 A/S: x = −b 2a = Find the direction, the y-intercept, the equation of the A/S, the vertex, and the domain and range. Deter-mine whether it has a maximum or a minimum. #9 y = 3 2 x² + 4x – 9 Direction, +a up, -a down: y-int, f(0) = c: A/S: x = −b 2a = V: −b 2a , 𝑓 −b 2a = Max or Min: y = 𝑓 −b 2a Domain: {x| } Range: {y| }

2.1(c): Do I Get It? Yes or No 1.(#7) y = 5x² – 2x + 2 Find the direction, the y-intercept, the equation of the A/S, the vertex, and the domain and range. Determine whether it has a maximum or a minimum. 1.(#7) y = 5x² – 2x + 2 2.(#8) y = -x² + 5x – 10 Direction, +a up, -a down: y-int, f(0) = c: A/S: x = −b 2a = V: −b 2a , 𝑓 −b 2a = Max or Min: y = 𝑓 −b 2a Domain: {x| } Range: {y| }