Minimum spanning trees

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Presentation transcript:

Minimum spanning trees

Minimum Connector Algorithms Kruskal’s algorithm Select the shortest edge in a network Select the next shortest edge which does not create a cycle Repeat step 2 until all vertices have been connected Prim’s algorithm Select any vertex Select the shortest edge connected to that vertex Select the shortest edge connected to any vertex already connected Repeat step 3 until all vertices have been connected

Example A cable company want to connect five villages to their network which currently extends to the market town of Avonford. What is the minimum length of cable needed? Avonford Fingley Brinleigh Cornwell Donster Edan 2 7 4 5 8 6 3

We model the situation as a network, then the problem is to find the minimum connector for the network A F B C D E 2 7 4 5 8 6 3

Prim’s Algorithm B C 3 6 8 A D F 7 5 4 2 E Starting from A Select the shortest edge from a connected vertex to an unconnected vertex AB 3

Prim’s Algorithm B C 3 6 8 A D F 7 5 4 2 E Select the shortest edge from a connected vertex to an unconnected vertex A F B C D E 2 7 4 5 8 6 3 AE 4

Prim’s Algorithm B C 3 6 8 A D F 7 5 4 2 E Select the shortest edge from a connected vertex to an unconnected vertex A F B C D E 2 7 4 5 8 6 3 ED 2

Prim’s Algorithm B C 3 6 8 A D F 7 5 4 2 E Select the shortest edge from a connected vertex to an unconnected vertex A F B C D E 2 7 4 5 8 6 3 DC 4

Prim’s Algorithm B C 3 6 8 A D F 7 5 4 2 E Select the shortest edge from a connected vertex to an unconnected vertex A F B C D E 2 7 4 5 8 6 3 EF 5

Prim’s Algorithm B C 3 6 8 A D F 7 5 4 2 E All vertices have been connected. The solution is ED 2 AB 3 CD 4 AE 4 EF 5 Total weight of tree: 18 A F B C D E 2 7 4 5 8 6 3

Some points to note Both algorithms will always give solutions with the same length. They will usually select edges in a different order – you must show this in your workings. Occasionally they will use different edges – this may happen when you have to choose between edges with the same length. In this case there is more than one minimum connector for the network.