Solving Systems of Equations

Slides:



Advertisements
Similar presentations
Example 1 Solution by Elimination Chapter 7.1 Solve the system  2009 PBLPathways.
Advertisements

Solve Systems of Equations by Elimination
Part 2.  Review…  Solve the following system by elimination:  x + 2y = 1 5x – 4y = -23  (2)x + (2)2y = 2(1)  2x + 4y = 2 5x – 4y = -23  7x = -21.
Solving a System of Equations by ELIMINATION. Elimination Solving systems by Elimination: 1.Line up like terms in standard form x + y = # (you may have.
Solving a System of Equations using Multiplication
Solving Systems of Equations by Elimination
5.3 Solving Systems using Elimination
7-2 and 7-3 Solving Systems of Equations Algebraically The Substitution and Elimination Method.
Solving Linear Systems by Linear Combinations
9.2 Solving Systems of Linear Equations by Addition BobsMathClass.Com Copyright © 2010 All Rights Reserved. 1 Step 1.Write both equations in the form Ax.
Warm up 12/6 or 7 1) Write the equation of a line that is parallel to y = -3x –5 and goes through the point (6,10). 2) Write the equation of a line that.
SOLVING SYSTEMS ALGEBRAICALLY SECTION 3-2. SOLVING BY SUBSTITUTION 1) 3x + 4y = 12 STEP 1 : SOLVE ONE EQUATION FOR ONE OF THE VARIABLES 2) 2x + y = 10.
Solve by using the ELIMINATION method The goal is to eliminate one of the variables by performing multiplication on the equations, and then add the two.
Solving by Elimination Example 1: STEP 2: Look for opposite terms. STEP 1: Write both equations in Standard Form to line up like variables. STEP 5: Solve.
Solving Systems Using Elimination
Solve the following system using the elimination method.
Solving Systems of Equations: The Elimination Method Solving Systems of Equations: The Elimination Method Solving Systems of Equations: The Elimination.
Section 5.3 Solving Systems of Equations Using the Elimination Method There are two methods to solve systems of equations: The Substitution Method The.
Systems of Equations: Substitution Method
7.4. 5x + 2y = 16 5x + 2y = 16 3x – 4y = 20 3x – 4y = 20 In this linear system neither variable can be eliminated by adding the equations. In this linear.
7.3 Solving Systems of Equations The Elimination Method.
Wednesday: Factoring Warm-up Find the factors and solutions.
 Recall that when you wanted to solve a system of equations, you used to use two different methods.  Substitution Method  Addition Method.
Solving 2 step equations. Two step equations have addition or subtraction and multiply or divide 3x + 1 = 10 3x + 1 = 10 4y + 2 = 10 4y + 2 = 10 2b +
Solving Systems of Equations Using the Elimination Method.
Solving Systems of Equations The Elimination Method.
In your groups Complete subtraction problems with positive and negative numbers.
Elimination Method - Systems. Elimination Method  With the elimination method, you create like terms that add to zero.
Solving a System of Equations by ELIMINATION. Elimination Solving systems by Elimination: 1.Line up like terms in standard form x + y = # (you may have.
Warm Up Find the solution to linear system using the substitution method. 1) 2x = 82) x = 3y - 11 x + y = 2 2x – 5y = 33 x + y = 2 2x – 5y = 33.
ELIMINATION AND GRAPHING Systems of Nonlinear Equations.
3.6 Systems with Three Variables
Solving Systems of Equations
10.3 Solving Linear Systems
Solving Systems of Equations
Solve Systems of Equations by Elimination
5.3 Solving Systems of Linear Equations by Elimination
3.4 Solving Systems with 3 variables
Solving Systems of Equations
Dividing & Solving Equations With Complex Numbers
Solve Systems of Equations by Elimination
3-2: Solving Linear Systems
Solving Systems of Equations
Solving Linear Systems by Linear Combinations
5.3 Solving Systems of Linear Equations by Elimination
Solving Systems of Equations by Elimination
REVIEW: Solving Linear Systems by Elimination
Solve Systems of Equations by Elimination
3.5 Solving systems of equations in 3 variables
Solving Systems of Linear and Quadratic Equations
Notes Solving a System by Elimination
Notes Solving a System by Elimination
SIMULTANEOUS EQUATIONS 1
3-2: Solving Linear Systems
Solving Equations Finding Your Balance
Solving Systems of Equations
Solving Systems of Equations
Solving Systems of Linear and Quadratic Equations
Solving Systems of Equations
Elimination Using Multiplication.
3-2: Solving Linear Systems
5.3 Elimination Eliminate means to get rid of…so lets get rid of a variable by adding the two equations together. -3x + 4y = 12 3x - 6y = 18 -2y = 30.
Example 2B: Solving Linear Systems by Elimination
Solving Systems of Equations
System of Equations: Elimination
11.8 Rational Equations & Functions
6.3 Elimination with Multiplication!
6-3 & 6-4 Solving Systems by Elimination
3-2: Solving Linear Systems
Solving Systems by ELIMINATION
Presentation transcript:

Solving Systems of Equations The Elimination Method

Objectives Learn the procedure of the Elimination Method using addition Learn the procedure of the Elimination Method using multiplication Solving systems of equations using the Elimination Method

Elimination using Addition Consider the system x - 2y = 5 Lets add both equations to each other 2x + 2y = 7 REMEMBER: We are trying to find the Point of Intersection. (x, y)

Elimination using Addition Consider the system x - 2y = 5 Lets add both equations to each other + 2x + 2y = 7 NOTE: We use the Elimination Method, if we can immediately cancel out two like terms.

Elimination using Addition Consider the system x - 2y = 5 Lets add both equations to each other + 2x + 2y = 7 3x = 12 x = 4  ANS: (4, y) NOTE: We use the Elimination Method, if we can immediately cancel out two like terms.

Elimination using Addition Consider the system x - 2y = 5 Lets substitute x = 4 into this equation. 2x + 2y = 7 4 - 2y = 5 Solve for y - 2y = 1 y = 1 2  ANS: (4, y) NOTE: We use the Elimination Method, if we can immediately cancel out two like terms.

Elimination using Addition Consider the system x - 2y = 5 Lets substitute x = 4 into this equation. 2x + 2y = 7 4 - 2y = 5 Solve for y - 2y = 1 1 2 y =  1 2 ANS: (4, ) NOTE: We use the Elimination Method, if we can immediately cancel out two like terms.

Elimination using Addition Consider the system 3x + y = 14 4x - y = 7 NOTE: We use the Elimination Method, if we can immediately cancel out two like terms.

Elimination using Addition Consider the system 3x + y = 14 + 4x - y = 7 7x = 21 x = 3  ANS: (3, y)

Elimination using Addition Consider the system 3x + y = 14 Substitute x = 3 into this equation 4x - y = 7 3(3) + y = 14 9 + y = 14 y = 5  ANS: (3, ) 5 NOTE: We use the Elimination Method, if we can immediately cancel out two like terms.

Examples… 1. 2. ANS: (4, -3) ANS: (-1, 2)

Elimination using Multiplication Consider the system 6x + 11y = -5 6x + 9y = -3

Elimination using Multiplication Consider the system 6x + 11y = -5 + 6x + 9y = -3 12x + 20y = -8 When we add equations together, nothing cancels out

Elimination using Multiplication Consider the system 6x + 11y = -5 6x + 9y = -3

Elimination using Multiplication Consider the system -1 ( ) 6x + 11y = -5 6x + 9y = -3

Elimination using Multiplication Consider the system - 6x - 11y = 5 + 6x + 9y = -3 -2y = 2  y = -1 ANS: (x, ) -1

Elimination using Multiplication Consider the system 6x + 11y = -5 6x + 9y = -3 Lets substitute y = -1 into this equation y = -1 6x + 9(-1) = -3 6x + -9 = -3 +9 6x = 6  x = 1 ANS: (x, ) -1

Elimination using Multiplication Consider the system 6x + 11y = -5 6x + 9y = -3 Lets substitute y = -1 into this equation y = -1 6x + 9(-1) = -3 6x + -9 = -3 +9 6x = 6  x = 1 ANS: ( , ) 1 -1

Elimination using Multiplication Consider the system x + 2y = 6 Multiply by -3 to eliminate the x term 3x + 3y = -6

Elimination using Multiplication Consider the system -3 ( ) x + 2y = 6 3x + 3y = -6

Elimination using Multiplication Consider the system -3x + -6y = -18 + 3x + 3y = -6 -3y = -24 y = 8  ANS: (x, 8)

Elimination using Multiplication Consider the system x + 2y = 6 Substitute y = 8 into equation 3x + 3y = -6 y =8 x + 2(8) = 6 x + 16 = 6 x = -10  ANS: (x, 8)

Elimination using Multiplication Consider the system x + 2y = 6 Substitute y = 8 into equation 3x + 3y = -6 y =8 x + 2(8) = 6 x + 16 = 6  x = -10 ANS: ( , 8) -10

Examples 1. 2. x + 2y = 5 x + 2y = 4 2x + 6y = 12 x - 4y = 16 ANS: (3, 1) ANS: (8, -2)

More complex Problems Consider the system 3x + 4y = -25 Multiply by 2

More complex Problems Consider the system 2( ) 3x + 4y = -25 -3( ) 2( ) 3x + 4y = -25 -3( ) 2x - 3y = 6

More complex Problems + Consider the system 6x + 8y = -50  ANS: (x, -4)

More complex Problems Consider the system 3x + 4y = -25 2x - 3y = 6 Substitute y = -4 2x - 3(-4) = 6 2x - -12 = 6 2x + 12 = 6 2x = -6 x = -3  ANS: (x, -4)

More complex Problems Consider the system 3x + 4y = -25 2x - 3y = 6 Substitute y = -4 2x - 3(-4) = 6 2x - -12 = 6 2x + 12 = 6 2x = -6 x = -3  ANS: ( , -4) -3

Examples… 2. 1. 2x + 3y = 1 4x + y = 9 5x + 7y = 3 3x + 2y = 8 ANS: (2, 1) ANS: (2, -1)