Let’s examine the figure to see what molecules are being represented. 2 C2H2 + 5 O2  4 CO2 + 2 H2O QUESTION: Consider the pictorial representation of a chemical change shown below. Using the smallest set of whole numbers, the coefficient of C2H2 in the balanced chemical equation for this reaction is... A. 1, B. 2, C. 3, D. 4 Consider the pictorial representation of a chemical change shown below. Using the smallest set of whole numbers, the coefficient of C2H2 in the balanced chemical equation for this reaction is... 1, B. 2, C. 3, D. 4 PAUSE Let’s examine the figure to see what molecules are being represented. According to the legend, a carbon atom is represented here by a filled circle. HIGHLIGHT carbon in legend and a hydrogen atom is represented by a small unfilled circle. HIGHLIGHT hydrogen in legend Therefore, this … CALLOUT “C2H2” pointing to one of the C2H2 molecules in before picture is a C2H2 molecule. We have three of this before picture. One… HIGHLIGHT Two… HIGHLIGHT Three… In the after picture, we have only one left. HIGHLIGHT. This means that during the reaction, the amount of C2H2 decreases. C2H2 is being consumed. It’s a reactant. In the pictures, we lost two molecules of C2H2. CLICK What else do we have? According to the legend., large unfilled atoms are oxygen atoms... HIGHLIGHT Legend Therefore, these... HIGHLIGHT five O2 molecules in before picture are O2 molecules. We have five of these before... and none after the reaction. Therefore, O2 is a reactant. The pictures shows the loss five O2 molecules in this picture. CLICK CLICK Similarly, we should be able to identify CO2 as a product of this reaction. On the left, we have no CO2 molecules. On the right, we have four CO2 molecules shown. HIGHLIGHT CO2 molecules while counting one...two...three four Therefore, the picture shows the formation of four CO2 molecules. We should also be able to identify H2O as a product of this reaction. THere is no H2O molecule on the left, and there are two shown on the right. HIGHLIHGT H2O molecules while counting one...two... Therefore, the picture shows the formation of two H2O molecules Therefore, one possible balanced equation for this reaction is 2 C2H2 HIGHLIGHT plus 5 O2 yields 4 CO2 2 H2O. The coefficients are CIRCLE coefficients as they are called out. 2..., 5..., 4..., and 2.... This is not the one of many ways of balancing the equation. We can multiply or divide all the coefficients by the same number and still have a balanced equation. For example, we can double all the coefficients, and still get have a balanced equation CLICK In this case, the coefficients would be 4, 10, 8, and 4. Or we can divide all the coefficients by 2 CLICK We still have a balanced equation with coefficients set to 1, CALLOUT “implied 1” 5/2, ... 2... and 1... CALLOUT “implied 1” This question is specifically asking for the coefficient of C2H2 is the equation with the smallest set of whole number coefficients. HIGHLIGHT “smallest set of whole numbers” in the question THe coefficients 2, 5, 4, and 2 HIGHLIGHT eqeuation at the top are the smallest set of whole number coefficients. Why? Because their greatest common factor is 1. Besides one, there is no number that you can use to divide all four coefficients to get a set of smaller whole numbers. Therefore, the correct answer is B. The coefficient of C2H2 is 2, provided we use the smallest set of whole number coefficients. Note that test makers are sometimes sloppy. If you see a question like this on a test and it doesn’t specifically specify the smallest set of coefficients, assume that this is implied. CLICK PAUSE END RECORDING 4 C2H2 + 10 O2  8 CO2 + 4 H2O C2H2 + 5/2 O2  2 CO2 + H2O

Video ID: 1-31-5 © 2008, Project VALUE (Video Assessment Library for Undergraduate Education), Department of Physical Sciences Nicholls State University Author: Glenn V. Lo Narrator: Funded by Louisiana Board of Regents Contract No. LA-DL-SELECT-13-07/08