Linked List Demo Node third = new Node(); third.item = "Carol";

Slides:



Advertisements
Similar presentations
1 Traversing a List Iteration. Idiom for traversing a null-terminated linked list. for (Node x = first; x != null; x = x.next) { StdOut.println(x.item);
Advertisements

1 Linked List Demo Node third = new Node(); third.item = "Carol"; third.next = null; Node second = new Node(); second.item = "Bob"; second.next = third;
Linked list Applications: Polynomial handling. Representing a polynomial using a linked list Store the coefficient and exponent of each term in nodes.
Advanced Computer Architecture Exercise 10 – Routing Deadlock Animation Interesting article about routing:
The Anatomy of a Zip File
Geog 100: World Regional Geography
L 8-9 Musical Scales, Chords, and Intervals, The Pythagorean and Just Scales.
CE Statics Chapter 6 – Lecture 20. THE METHOD OF JOINTS All joints are in equilibrium since the truss is in equilibrium. The method of joints is.
FPtree/FPGrowth (Complete Example). First scan – determine frequent 1- itemsets, then build header B8 A7 C7 D5 E3.
FP-Tree/FP-Growth Practice. FP-tree construction null B:1 A:1 After reading TID=1: After reading TID=2: null B:2 A:1 C:1 D:1.
Adaptive Huffman coding The trees are automatically generated by a Generator Designed at SUCO.
Introduction to C Programming CE Lecture 20 Insertion and Deletion with Linear Linked Lists.
Pattern Lattice Traversal by Selective Jumps Osmar R. Zaïane and Mohammad El-Hajj Department of Computing Science, University of Alberta Edmonton, AB,
Class 3: Linked Lists. cis 335 Fall 2001 Barry Cohen What is a linked list? n A linked list is an ordered series of ‘nodes’ n Each node contains some.
Introduction to C Programming CE Lecture 19 Linear Linked Lists.
CS 192 Lecture 19 Winter 2003 February 9-10, 2004 Dr. Shafay Shamail.
Code Converters Section 3-4 Mano & Kime.
Self Referential Structure. A structure may not contain a member of its own type. struct check { int item; struct check n; // Invalid };
Parallel Lines and Proportional Parts By: Jacob Begay.
Stack Data Structure By : Imam M Shofi. What is stack? A stack is a limited version of an array. A stack is a limited version of an array. New elements,
4.3 Stacks and Queues Introduction to Programming in Java: An Interdisciplinary Approach · Robert Sedgewick and Kevin Wayne · Copyright © 2008 · October.
A Soils generally without limiting chemical or physical properties Ba Deep, highly structured soils with high initial fertility Bb Soils naturally.
ليست هاي پيوندي Linked Lists ساختمان داده ها و الگوريتم ها.
Balanced search trees: 2-3 trees. 2-3 trees allow us to process ordered lists in more efficient way than binary trees with an ordering property. Recall.
ENG2410 Digital Design LAB #5 Modular Design and Hierarchy using VHDL.
COMPUTER SCIENCE Data Representation and Machine Concepts Section 2.1 Instructor: Lin Chen Sept 2013.
Self-Referential Classes A Self-referential class is a class that contains a reference to an object that has the same class type. –A self-referential class.
Today’s Agenda  Linked Lists  Double ended Linked Lists  Doubly Linked Lists CS2336: Computer Science II.
A DPLL example C1:(a  b) C2:(  a   b) C3:(a   c) C4:(c  d  e) C5:(d   e) C6:(  d   f) C7:(f  e) C8:(  f   e) false true a a a=false by.
Balanced search trees: trees (or 2-4) trees improve the efficiency of insertItem and deleteItem methods of 2-3 trees, because they are performed.
CONSTRUCTIVISM A Model for Designing Constructivist Learning Environments.
AES Encryption FIPS 197, November 26, Bit Block Encryption Key Lengths 128, 192, 256 Number of Rounds Key Length Rounds Block.
A horse race has the following horses running. How many different first, second and third place results are possible: Mushroom Pepper Sausage Tomato Onion.
Geometry: Plane Figures Chapter. point A point marks a location. A A B B line segment the part of the line between 2 points endpoints.
PORTFOLIO CD COVER examples IMS Portfolio Workshop Spring 2012.
2/21/20161 List Operations Advanced Programming Ananda Gunawardena.
 Array is a data structure were elements are stored in consecutive memory location.in the array once the memory is allocated.it cannot be extend any more.
Team 3 JaphethCrystal ChristianRaj JohnathanAmanda.
Linked list: a list of items (nodes), in which the order of the nodes is determined by the address, called the link, stored in each node C++ Programming:
Fig Storage of a C program. Fig Memory allocation with malloc.
EE345 Chapter 2 Lecture 3 April 4. Quiz every Wednesday 1 quiz = 1% extra credit five quizzes before midterm  5% for midterm. five quizzes before final.
LAB #5 Modular Design and Hierarchy using VHDL
Linked List ADT used to store information in a list
UNIT – I Linked Lists.
2.5 Distributive Review Prize Show
Combinations COURSE 3 LESSON 11-3
Presentation Test. Second Slide Third Slide It worked.
The Singly-Linked Structure
Prof. Neary Adapted from slides by Dr. Katherine Gibson
EECS 498 Introduction to Distributed Systems Fall 2017
Make an Organized List and Simulate a Problem
VI. Scales & Consonance Dr. Bill Pezzaglia
CS 140 Lecture Notes: Protection
CS 140 Lecture Notes: Protection
Compute the colour at point G – Guraud Shading
Review & Lab assignments
Shortest path algorithm
Ceremonies (in 3 minutes)
CS 140 Lecture Notes: Protection
Race Conditions David Ferry CSCI 3500 – Operating Systems
Linked Lists.
Red Black Trees.
Traversing a Linked List
刘振 上海交通大学 计算机科学与工程系 电信群楼3-509
A Series of Slides in 5 Parts Movement 4. Best-First
A Series of Slides in 5 Parts Movement 4. Best-First
V1a – In Need Arr: Shane Coffman Words and Music by: Ross King
A Series of Slides in 5 Parts Movement 3. IDFS
Balanced search trees: trees.
Balanced search trees: 2-3 trees.
Presentation transcript:

Linked List Demo Node third = new Node(); third.item = "Carol"; addr Value Node third = new Node(); third.item = "Carol"; third.next = null; Node second = new Node(); second.item = "Bob"; second.next = third; Node first = new Node(); first.item = "Alice"; first.next = second; C0 - C1 - C2 - C3 - C4 - C5 - C6 - C7 - C8 - C9 - CA - CB - CC - CD - CE - CF - main memory

Linked List Demo Node third = new Node(); third.item = "Carol"; addr Value Node third = new Node(); third.item = "Carol"; third.next = null; Node second = new Node(); second.item = "Bob"; second.next = third; Node first = new Node(); first.item = "Alice"; first.next = second; C0 - C1 - C2 - C3 - C4 - C5 - third C0 C6 - C7 - C8 - C9 - CA - CB - CC - third CD - CE - null CF - item next main memory

Linked List Demo Node third = new Node(); third.item = "Carol"; addr Value Node third = new Node(); third.item = "Carol"; third.next = null; Node second = new Node(); second.item = "Bob"; second.next = third; Node first = new Node(); first.item = "Alice"; first.next = second; C0 "Carol" C1 - C2 - C3 - C4 - C5 - third C0 C6 - C7 - C8 - C9 - CA - CB - CC - third CD - CE - Carol CF - item next main memory

Linked List Demo Node third = new Node(); third.item = "Carol"; addr Value Node third = new Node(); third.item = "Carol"; third.next = null; Node second = new Node(); second.item = "Bob"; second.next = third; Node first = new Node(); first.item = "Alice"; first.next = second; C0 "Carol" C1 null C2 - C3 - C4 - C5 - third C0 C6 - C7 - C8 - C9 - CA - CB - CC - third CD - CE - Carol null CF - item next main memory

Linked List Demo Node third = new Node(); third.item = "Carol"; addr Value Node third = new Node(); third.item = "Carol"; third.next = null; Node second = new Node(); second.item = "Bob"; second.next = third; Node first = new Node(); first.item = "Alice"; first.next = second; C0 "Carol" C1 null C2 - C3 - C4 - second CA C5 - third C0 C6 - C7 - C8 - C9 - CA - CB - CC - second third CD - CE - Carol null CF - item next main memory

Linked List Demo Node third = new Node(); third.item = "Carol"; addr Value Node third = new Node(); third.item = "Carol"; third.next = null; Node second = new Node(); second.item = "Bob"; second.next = third; Node first = new Node(); first.item = "Alice"; first.next = second; C0 "Carol" C1 null C2 - C3 - C4 - second CA C5 - third C0 C6 - C7 - C8 - C9 - CA "Bob" CB - CC - second third CD - CE - Bob Carol null CF - item next main memory

Linked List Demo Node third = new Node(); third.item = "Carol"; addr Value Node third = new Node(); third.item = "Carol"; third.next = null; Node second = new Node(); second.item = "Bob"; second.next = third; Node first = new Node(); first.item = "Alice"; first.next = second; C0 "Carol" C1 null C2 - C3 - C4 - second CA C5 - third C0 C6 - C7 - C8 - C9 - CA "Bob" CB C0 CC - second third CD - CE - Bob Carol null CF - item next main memory

Linked List Demo Node third = new Node(); third.item = "Carol"; addr Value Node third = new Node(); third.item = "Carol"; third.next = null; Node second = new Node(); second.item = "Bob"; second.next = third; Node first = new Node(); first.item = "Alice"; first.next = second; C0 "Carol" C1 null C2 - C3 - first C4 C4 - second CA C5 - third C0 C6 - C7 - C8 - C9 - CA "Bob" CB C0 CC - first second third CD - CE - Bob Carol null CF - item next main memory

Linked List Demo Node third = new Node(); third.item = "Carol"; addr Value Node third = new Node(); third.item = "Carol"; third.next = null; Node second = new Node(); second.item = "Bob"; second.next = third; Node first = new Node(); first.item = "Alice"; first.next = second; C0 "Carol" C1 null C2 - C3 - first C4 C4 "Alice" second CA C5 - third C0 C6 - C7 - C8 - C9 - CA "Bob" CB C0 CC - first second third CD - CE - Alice Bob Carol null CF - item next main memory

Linked List Demo Node third = new Node(); third.item = "Carol"; addr Value Node third = new Node(); third.item = "Carol"; third.next = null; Node second = new Node(); second.item = "Bob"; second.next = third; Node first = new Node(); first.item = "Alice"; first.next = second; C0 "Carol" C1 null C2 - C3 - first C4 C4 "Alice" second CA C5 CA third C0 C6 - C7 - C8 - C9 - CA "Bob" CB C0 CC - first second third CD - CE - Alice Bob Carol null CF - item next main memory

Linked List Demo Node third = new Node(); third.item = "Carol"; addr Value Node third = new Node(); third.item = "Carol"; third.next = null; Node second = new Node(); second.item = "Bob"; second.next = third; Node first = new Node(); first.item = "Alice"; first.next = second; C0 "Carol" C1 null C2 - C3 - first C4 C4 "Alice" second CA C5 CA third C0 C6 - C7 - C8 - C9 - CA "Bob" CB C0 CC - first second third CD - CE - Alice Bob Carol null CF - item next main memory