Another Example: Aluminum chloride, Al2Cl6, can be made by the reaction of aluminum with chlorine according to the following equation:                        2.

Slides:



Advertisements
Similar presentations
Prentice-Hall © 2002 General Chemistry: Chapter 4 Slide 1 of 29 Philip Dutton University of Windsor, Canada Prentice-Hall © 2002 Chapter 4: Chemical Reactions.
Advertisements

Theoretical and Percent Yield
Yields, Limiting Reactants, and Solutions Copyright © 2008 Pearson Prentice Hall, Inc.Chapter 1/1.
Chapter 9 Combining Reactions and Mole Calculations.
Chemistry 101 Chapter 9 Chemical Quantities.
Chapter 9 Combining Reactions and Mole Calculations.
Review Jeopardy States of Matter SolutionsStoichiometry.
Chapter 3 Stoichiometry.
Limiting Reagent Problem. Calculate the mass of aluminum chloride that can be produced from 20.0 g of aluminum and 30.0 g of chlorine gas. Step 1: Write.
Increasing energy with temp? The added energy in a substance that occurs as temperature increases is stored in modes of motion in the substance For any.
CHAPTER 3 Chemical E quations & Reaction Stoichiometry.
Chemistry 11 Stoichiometry Reality II: Percent Yield.
Chapter 12 Stoichiometry Mr. Mole. Molar Mass of Compounds Molar mass (MM) of a compound - determined by up the atomic masses of – Ex. Molar mass of CaCl.
Solutions Solute Solvent Solutions are homogenous mixtures. When a substance is mixed with a liquid and it disintegrates into sub microscopic particles.
Quantitative Chemistry
Stoichiopardy Holy Moley Do the 2 or 3 step Random Limit my Percent Q $100 Q $200 Q $300 Q $400 Q $500 Q $100 Q $200 Q $300 Q $400 Q $500 Final Chempardy.
Ch 11 & 12 DefinitionsSolubilityRandomCalculations $100 $200 $300 $400 $500.
Chemistry II Chemical Reactions Principles and Modern Applications
Ideal gases and molar volume
Chapter 10 - Review States of Matter Milbank High School.
AP Chemistry Dickson County High School Mrs. Laura Peck 1.
Elements in Group 1A will form what type of ion? +1 cation.
Stoichiometry Stoichiometry CDO High School. Stoichiometry Consider the chemical equation: 4NH 3 + 5O 2  6H 2 O + 4NO There are several numbers involved.
Stoichiometry. Information Given by the Chemical Equation  The coefficients in the balanced chemical equation show the molecules and mole ratio of the.
INTRODUCTION TO SOLUTIONS/ACIDS AND BASES HONORS CHEMISTRY MAY 27 TH, 2014.
Stoichiometry The accounting of chemistry. Moles WWhat are moles? Moles are a measure of matter in chemistry. Moles help us understand what happens.
IB1 Chemistry Quantitative 1b.. Topic 1: Quantitative chemistry 1.1 The mole concept and Avogadro’s constant Apply the mole concept to substances.
Elements in Group 1A will form what type of ion? +1 cation.
States of Matter Kinetic Molecular Theory: the idea that particles of matter are always in motion; this applies to all states of matter Used to explain.
Mass Relationships By Doba Jackson, Ph.D.. Balancing Chemical Equations A balanced chemical equation shows that the law of conservation of mass is adhered.
Stoichiometry Chemical Quantities Chapter 9. What is stoichiometry? stoichiometry- method of determining the amounts of reactants needed to create a certain.
Calculate the mass of Cu produced? Mass of beaker and Cu – mass of beaker.
Stoichiometry Review 1.Write the equation for a reaction between Ca(OH) 2 and NaCl Unbalanced: Ca(OH) 2 + NaCl  CaCl 2 + NaOH Balanced: 1 Ca(OH)
 I can define stoichiometry.  I can identify the number of moles required in a reaction based on the coefficients.  I can determine how many moles.
Solutions Textbook Chapter 14. Definitions n A solution is a homogeneous mixture n A solute is dissolved in a solvent. –solute is the substance being.
Let’s talk… mole to mole
Stoichiometry is the study of quantitative (i. e
Solving a Stoichiometry Problem
Stoichiometry.
Chemistry 200 Fundamentals E Limiting Reagents.
Stoichiometry and the Mole
Stoichiometry II.
Stoichiometry.
Chemistry for Changing Times 12th Edition Hill and Kolb
Chemical Sentences: Equations
Kinetic Molecular Theory
I CHEMISTRY.
Chapter 12 Practice Test Assignment #2
Limiting & Excess Reactants
Quantity Relationships in Chemical Reactions
Quantitative chemistry
Basic Chemistry Chapter 11 Gases Chapter 11 Lecture
Chapter 12 “Stoichiometry”
Solutions L. Breen Chemistry 1405.
Equilibrium Expressions
Visualizing Limiting Reactant
Quantities In Chemical Reactions
Stoichiometry.
Physical Science Chapter 3
CHEMISTRY.
Limiting Reactant Most of the time in chemistry we have more of one reactant than we need to completely use up other reactant. That reactant is said to.
What Really Happens in Stoichiometry, Most of the Time
Objectives Explain the kinetic theory of matter.
Stoichiometry.
Chapter 6 Chemical Quantities.
Chapter 9 Key Terms Mole Molar Mass Avogadro's Number Percent Composition Stoichiometry Limiting Reactant Excess Reactant Actual Yield Theoretical Yield.
10.2 Properties of Solids Different kinds of matter have different characteristics. Characteristics that can you observe directly are called physical.
GASES.
Chapter 9 “Stoichiometry”
Presentation transcript:

Another Example: Aluminum chloride, Al2Cl6, can be made by the reaction of aluminum with chlorine according to the following equation:                        2 Al  + 3 Cl2 → Al2Cl6 What is the limiting reactant if 20.0 grams of Al and 30.0 grams of Cl2 are used? How much Al2Cl6 can form? What is the fractional and percentage yield of the product? It is known that Al = 26.98 g/mol, Cl2 =  70.90 g/mol and Al2Cl6 =  266.7 g/mol

Moles of Al = 20.00 g/26.98 g/mol = 0.74 moles Moles of Cl2 = 30.00 g/70.90 g/mol = 0.42 moles Recall the balanced chemical reaction: 2 Al  + 3 Cl2 → Al2Cl6 Every two moles of Al produces one mole of product. If all the Al is consumed, we will get 0.74/2 = 0.37 moles of product. Every three moles of Cl2 produces one mole of product. If all the Cl2 is consumed, we will get 0.42/3 = 0.14 moles of product.

Moles of Al are in excess; the moles of Cl2 are insufficient for complete reaction; Cl2 is the limiting reagent. If we use up all the Cl2 available, all 0.42 moles, we will get 0.42/3 = 0.14 moles of Al2Cl6. Theoretically, if all Al had reacted, we would have had 0.37 moles of Al2Cl6. The fractional yield is actual yield divided by theoretical yield: 0.14/0.37 = 0.378 The percentage yield is the fractional yield times 100: 0.378 x 100 = 37.8%.

When is 2 + 2 not equal to 4? Dilution Problem: If you have available a 0.25 M NaOH solution and pure water, how much water needs to be added to make 10 liters of 0.2 molar solution of NaOH? Strategy: Moles of NaOH are not changed by dilution. In 10 L of 0.2 M NaOH the number of moles of NaOH present are 2 mol. So, you need to add 8 L of the 0.25 M NaOH to 2 L of pure water to arrive at the final desired solution concentration.

States of Matter: A Simple-Minded View DIGRESSION ◄► ◄► ◄► ◄► ◄► States of Matter: A Simple-Minded View ◄► ◄► ◄► ◄► ◄► The three principal states of matter are said to be: ● Gases ● Liquids ● Solids These are called different phases, and it is possible to go from one phase to another by a temperature change. Example: water as steam, liquid, ice

Space-Filling Property Gas – takes shape of container and fills it Liquid – takes shape of container without necessarily filling it Solid – has its own well-defined shape irrespective of container

Density Gas – 1019 molecules per cm3 at STP Chemical change occurs by means of binary collisions. Liquid – ~1022 molecules per cm3 Chemical change occurs in the “solvent cage”; followed by escape. Solid – ~1022 molecules per cm3 Chemical change occurs by hopping to vacancy sites; otherwise nothing happens!

Response to Shear Force Gas – inelastic ; little resistance Liquid – inelastic; viscous resistance Solid – elastic over finite range of force, then breaks shape.

Microscopic Structure Gas – disordered throughout Liquid – short-range order, long-range disorder Solid – short-range and long-range order Essentially random relative positioning of the gas molecules Approximately, close-packed ; first two or three shells around a given molecule are identifiable, but well-defined positional relationships die out with distance. Molecules have well-defined positions in a crystal lattice.

Not All Matter Fits the Three-Way Division ! Think about: liquid crystals amorphous solids polymers glasses, gels, foams, aerosols, etc. Conclusion: Chemistry is really more complex than you might first imagine … … and it does not fit neatly into boxes!

Adventures in Liquid Crystals The liquid crystal state is a distinct phase of matter observed between the crystalline (solid) and isotropic (liquid) states. There are many types of liquid crystal states, depending upon the amount of order in the material.

Nematic Phase The nematic liquid crystal phase is characterized by molecules that have no positional order but tend to point in the same direction (along the director).

Smectic Phase In the smectic state, the molecules maintain the general orientational order of nematics, but also tend to align themselves in layers or planes. Motion is restricted to within these planes, and separate planes are observed to flow past each other. The increased order means that the smectic state is more "solid-like" than the nematic.

Smectic Phase In the smectic-A phase, the director is perpendicular to the smectic plane and there is particular positional order in the layer.

Smectic Phase In the smectic-C phase, molecules are arranged as in the smectic-A phase, but the director is at a constant tilt angle measured with respect to the smectic plane.

Simulation of Phase Change in Liquid Crystals The material begins in the crystalline state, and as the user increases the temperature, it undergoes a phase change. The first liquid crystal phase is the smectic A, where there is layer-like arrangement as well as translational and rotational motion of the molecules. A further increase in temperature leads to the nematic phase, where the molecules rapidly diffuse out of the initial lattice structure and from the layer-like arrangement as well. At the highest temperatures, the material becomes an isotropic liquid. http://plc.cwru.edu/tutorial/enhanced/files/lc/phase/phase.htm