ACCELERATION

final velocity -- initial velocity V final - V initial time t ACCELERATION - Acceleration is the _________ at which the _____________ of a moving object changes. (Actually includes both speeding up and slowing down) rate velocity -Velocity describes the ____________ of an object. -Acceleration describes how the ______________ changes. motion motion acceleration = _____________________ or a = ______________ final velocity -- initial velocity V final - V initial time t -Possible units for velocity are: ________________________________ -Since acceleration is the rate at which velocity changes its unit will be any unit for ______________ over ________________. Ex. ____________________________ m/s due north, mi/h due east, cm/day due west, etc. velocity time m/s/h, mi/h/min, cm/day/hour (due North)

the same you can square them. 2 3 = 3 1 -What if the two time units are the same? 5 m 5 m/s/s also written as s s 2 3 3 2 5 m/s So, if the time units are the same you can square them. 2 3 = 3 1 (another way to write this is . . .) 2 2 1 x = 3 3 2 3

V final - V initial a= t 15 m/s - 10 m/s a= 1 s 5 m/s 2 a= Sample Problems: -Captain America is running north at a velocity of 5 m/s. Noticing that he is not catching up to the villain he is chasing he decides to pick up his speed. Within one second he increases his velocity to 10 m/s. Within one more second he increases his velocity from 10 m/s to 15 m/s. What is his acceleration? V final - V initial a= t 15 m/s - 10 m/s a= 1 s 5 m/s 2 a= 5 m/s/s or 5 m/s a= 1 s

V final - V initial a= t 32 m/s - 0 m/s a= 4 s 32 m/s a= 4 s 2 -How quickly would the Batmobile accelerate if it’s forward velocity changed from 0 to 32 meters per second in 4 seconds? V final - V initial a= t 32 m/s - 0 m/s a= 4 s 32 m/s a= 4 s 2 8m/s/s or 8 m/s a=

V final - V initial a= t 222 mi/h - 204 mi/h a= 2 s 18 mi/h a= 2 s -What would be the acceleration of Hawkeye’s arrow if its speed increased from 204 miles per hour to 222 miles per hour within 2 seconds? V final - V initial a= t 222 mi/h - 204 mi/h a= 2 s 18 mi/h a= 2 s 9 mi/h/s a=

deceleration negative V final - V initial a= t -_________________ is a word often used to describe a decrease in velocity. Since acceleration includes any change in velocity (increase or decrease) deceleration is calculated using the same formula. -When calculating deceleration you will always end up with a ______________ answer. deceleration negative V final - V initial a= t

-Since acceleration measures changes in velocity, an object that changes either its ______________ or _________________ is accelerating. An object may be accelerating even if its speed is constant. speed direction

accelerating decelerating constant velocity going backwards stopped Line Curved up= _____________ Line Curved down= ____________ Straight line angled up= __________ Straight line angled down= _________ Flat Horizontal line= ____________ Flat Vertical line= ___________ accelerating decelerating constant velocity going backwards stopped not possible

increasing your rate of accelerating increasing your rate Line Curved up= _____________ Line Curved down= ____________ Straight line angled up= __________ Straight line angled down= _________ Flat Horizontal line= ____________ Flat Vertical line= ___________ increasing your rate of accelerating increasing your rate of decelerating constant acceleration constant deceleration constant speed not possible