Unit 5: Momentum Lesson 3: Collisions.

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Presentation transcript:

Unit 5: Momentum Lesson 3: Collisions

Conservation of Momentum During a collision, total momentum is conserved! In equation form: p1b + p2b = p1a + p2a (This assumes there are NO OUTSIDE FORCES.) 5 min

Collision Problems p before = p after mgvg + 0 = mgmvgm Example 1: A 4000 kg garbage truck going 72 km/h collides with a stationary Mini of mass 900 kg. They stick together just after the collision. Find the velocity of the combined wreckage. 10 min p before = p after mgvg + 0 = mgmvgm (4000)(72/3.6) = (4000+900)v v = 16.3 m/s = 59 km/h

p before = p after (800)(33.3) + (1400)(-13.9) = 2200v v = 3.26 m/s Example 2 (Try it!): A 1400 kg PT Cruiser going 50 km/h West collides head-on with a 800 kg VW Beetle going East at 120 km/h. If they stick together, find the final velocity. (50 km/h)/3.6 = 13.9 m/s 15 min (120 km/h)/3.6 = 33.3 m/s p before = p after (800)(33.3) + (1400)(-13.9) = 2200v v = 3.26 m/s = 12 km/h East

Brain Break!

Example 3 (Try it!): A 1700 kg truck collides head-on with a 68 tonne tank going West at 15 m/s. The wreckage sticks together and moves West at 13.5 m/s just after the collision. Find the initial velocity of the truck. ? 15 m/s 13.5 m/s 15 min p before = p after 1700v + 68000(-15) = (68000+1700)(-13.5) 1700v = 68000(15) + 69700(-13.5) v = 46.5 m/s or 167 km/h

Homework Pg. 125 #1-3 and pg. 126 #4 and 6 10 min

Lesson 4: More Collisions Unit 5: Momentum Lesson 4: More Collisions

Example 4: A 250 g pool ball going 1 Example 4: A 250 g pool ball going 1.7 m/s strikes a stationary 320 g ball which bounces forwards at 0.80 m/s. Find the velocity of the first ball just after the collision. before after ? 10 min p before = p after (0.25)(+1.7) + 0 = .25v + (0.32)(+0.8) .25v = -(0.32)(+0.8) + (0.25)(+1.7) v = +0.68 m/s

? p before = p after (7500+1200)v = 7500(24) + 1200(62) 8700v = 254400 Example 5 (Try it!): A 7500 kg spaceship deploys a 1200 kg satellite at 62 m/s forwards. The final velocity of the ship is 24 m/s forwards. Find the initial velocity. before after ? p before = p after (7500+1200)v = 7500(24) + 1200(62) 8700v = 254400 v = 29.2 m/s forwards 15 min

Brain Break!

Practice Time! Do Collision Problems #1-6