Springs and Hooke’s Law

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Presentation transcript:

Springs and Hooke’s Law Physics 11

Springs A mass-spring system is given below. As mass is added to the end of the spring, how would you expect the spring to stretch?

Springs

Springs 2 times the mass results in a 2 times of the displacement from the equilibrium point… 3 time the mass… 3 times the displacement…

What kind of energy is this? Potential Energy Elastic Potential Energy to be exact!

What else besides springs has elastic potential energy? Diving boards Bows (bow and arrows) Bungee cord

Hooke’s Law Fspring: Applied force X : displacement of the spring from the equilibrium position (units: m) K: the spring constant (units: N/m)

Hooke’s Law the restoring force is opposite the applied force. (negative sign) Gravity applied in the negative direction, the restoring force is in the positive direction

Example An archery bow requires a force of 133N to hold an arrow at “full draw” (pulled back 71cm). Assuming that the bow obeys Hooke’s Law, what is its spring constant?

F = kx 133 = k(0.71) k = 133/0.71 k = 187.32 N/m  190 N/m

Restoring Force The restoring force is the force that is needed to put the spring back to equilibrium. Example: If you stretch a spring by 0.5m and you had to use 150N of force, the restoring force is -150N.

Example 2: A 70. kg person bungee jumps off a 50.m bridge with his ankles attached to a 15m long bungee cord. Assume the person stops at the edge of the water and he is 2.0m tall, what is the force constant of the bungee cord?