Microsoft Visual Basic 2005: Reloaded Second Edition

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Presentation transcript:

Microsoft Visual Basic 2005: Reloaded Second Edition Chapter 6 String Manipulation and More Controls

Objectives After studying this chapter, you should be able to: Determine the number of characters contained in a string Remove characters from a string Replace one or more characters in a string Insert characters within a string Search a string for one or more characters Microsoft Visual Basic 2005: Reloaded, Second Edition

Objectives (continued) Access characters contained in a string Compare strings Include radio buttons in an interface Include check boxes in an interface Microsoft Visual Basic 2005: Reloaded, Second Edition

Manipulating Strings in Visual Basic Most applications need to manipulate string data in some fashion String properties and methods are used to manipulate string data Microsoft Visual Basic 2005: Reloaded, Second Edition

Determining the Number of Characters Contained in a String Microsoft Visual Basic 2005: Reloaded, Second Edition

Determining the Number of Characters Contained in a String (continued) Microsoft Visual Basic 2005: Reloaded, Second Edition

Determining the Number of Characters Contained in a String (continued) Microsoft Visual Basic 2005: Reloaded, Second Edition

Determining the Number of Characters Contained in a String (continued) Microsoft Visual Basic 2005: Reloaded, Second Edition

Removing Characters from a String TrimStart method: removes one or more characters from the beginning of a string TrimEnd method: removes one or more characters from the end of a string Trim method: removes one or more characters from both the beginning and end of a string Each of these methods returns a string with the appropriate characters removed Microsoft Visual Basic 2005: Reloaded, Second Edition

Removing Characters from a String (continued) Microsoft Visual Basic 2005: Reloaded, Second Edition

Removing Characters from a String (continued) trimChars argument: Comma-separated list of characters to be removed If omitted, spaces will be removed Default value is the space character: “ ” Microsoft Visual Basic 2005: Reloaded, Second Edition

Removing Characters from a String (continued) Microsoft Visual Basic 2005: Reloaded, Second Edition

Removing Characters from a String (continued) Microsoft Visual Basic 2005: Reloaded, Second Edition

The Remove Method Remove method: Index: Removes characters from a string Can remove one or more characters located anywhere in the string Returns a string with the appropriate characters removed Index: The position of a character in a string Is zero-relative (starts with 0 as first position) Microsoft Visual Basic 2005: Reloaded, Second Edition

The Remove Method (continued) Microsoft Visual Basic 2005: Reloaded, Second Edition

The Remove Method (continued) Microsoft Visual Basic 2005: Reloaded, Second Edition

The Remove Method (continued) Microsoft Visual Basic 2005: Reloaded, Second Edition

The Remove Method (continued) Microsoft Visual Basic 2005: Reloaded, Second Edition

Replacing Characters in a String Replace method: replaces a sequence of characters in a string with another sequence of characters Microsoft Visual Basic 2005: Reloaded, Second Edition

Replacing Characters in a String (continued) Microsoft Visual Basic 2005: Reloaded, Second Edition

Replacing Characters in a String (continued) Microsoft Visual Basic 2005: Reloaded, Second Edition

Replacing Characters in a String (continued) Microsoft Visual Basic 2005: Reloaded, Second Edition

Replacing Characters in a String (continued) Microsoft Visual Basic 2005: Reloaded, Second Edition

The Mid Statement Mid statement: Replaces a specified number of characters in a string with characters from another string targetString argument: the string in which characters are to be replaced replacementString argument: the replacement characters start argument: the starting position for the replacement count argument: number of characters to replace Microsoft Visual Basic 2005: Reloaded, Second Edition

The Mid Statement (continued) Character position of characters in the string starts with 1 (not the same as index) Count argument is optional Microsoft Visual Basic 2005: Reloaded, Second Edition

The Mid Statement (continued) Microsoft Visual Basic 2005: Reloaded, Second Edition

The Mid Statement (continued) Microsoft Visual Basic 2005: Reloaded, Second Edition

The Mid Statement (continued) Microsoft Visual Basic 2005: Reloaded, Second Edition

Inserting Characters in a String PadLeft method: inserts characters at the beginning of a string PadRight method: inserts characters at the end of a string length argument: represents the total length of the desired resulting string character argument: The character used to pad the string Default value is the space character Microsoft Visual Basic 2005: Reloaded, Second Edition

Inserting Characters in a String (continued) Microsoft Visual Basic 2005: Reloaded, Second Edition

Inserting Characters in a String (continued) Microsoft Visual Basic 2005: Reloaded, Second Edition

Inserting Characters in a String (continued) Microsoft Visual Basic 2005: Reloaded, Second Edition

Inserting Characters in a String (continued) Microsoft Visual Basic 2005: Reloaded, Second Edition

Inserting Characters in a String (continued) Microsoft Visual Basic 2005: Reloaded, Second Edition