Conservation of Momentum

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Presentation transcript:

Conservation of Momentum

The law of conservation of momentum states that total momentum remains constant (When we ignore friction).

1. An object separates into pieces: 3 Possible situations: 1. An object separates into pieces: MiVi= Mf1Vf1 + Mf2Vf2 2. Two objects collide and stick together: Mi1Vi1 + Mi2Vi2 = Mf(1+2)Vf 3. Two objects collide and separate: Mi1Vi1 + Mi2Vi2 = Mf1Vf1 + Mf2Vf2

A 600 kg ship is traveling at 1000 m/s A 600 kg ship is traveling at 1000 m/s. The ship burns off 100 kg of fuel and the fuel is propelled out of the back of the ship at 2000 m/s. What is the final speed of the ship after the fuel is expelled? *Remember to consider direction!

Mi(r +f)Vi(r + f) = Mf(r)Vf(r) +Mf(f)Vf(f) A 600 kg ship is traveling at 1000 m/s. The ship burns off 100 kg of fuel and the fuel is propelled out of the ship at 2000 m/s. What is the final speed of the ship after the fuel is expelled? Mi(r +f)Vi(r + f) = Mf(r)Vf(r) +Mf(f)Vf(f) (600+100)(1000) = 600(Vf(r) ) + 100(-2000) 700,000 = 600(Vf ) - 200,000 700,000 + 200,000 = 600(Vfr ) 900,000 = 600Vf Vf = 1,500 m/s

A 2,000 kg truck traveling at 30 m/s North collides into a 1,000 kg car travelling at 10 m/s South. The vehicles stick together after the collision. What is their final velocity? Be sure to include direction!

Mi(t)Vi(t) + Mi(c)Vi(c) = Mf(t+c)Vf A 2,000 kg truck traveling at 30 m/s North collides into a 1,000 kg car travelling at 10 m/s South. The vehicles stick together after the collision. What is their final velocity? Be sure to include direction! Mi(t)Vi(t) + Mi(c)Vi(c) = Mf(t+c)Vf (2,000)(30) + (1,000)(-10) = (3,000)Vf 60,000 - 10,000 = (3,000)Vf 50,000 = (3,000)Vf 50,000/3,000 = Vf Vf = 16.67 m/s North

Two pool balls collide. Each ball weights 0. 5 kg Two pool balls collide. Each ball weights 0.5 kg. One ball has an initial velocity of 7 m/s, while the other ball travels with an initial velocity of 5 m/s. After the collision the first ball travels at 6 m/s. What is the final velocity of the second ball?

Two pool balls collide. Each ball weights 0. 5 kg Two pool balls collide. Each ball weights 0.5 kg. One ball has an initial velocity of 7 m/s, while the other ball travels with an initial velocity of 5 m/s. After the collision the first ball travels at 6 m/s. What is the final velocity of the second ball? Mi1Vi1 + Mi2Vi2 = Mf1Vf1 +Mf2Vf2 (.5)(7)+ (.5)(-5) = (.5)(6) + (.5)(Vf2) 3.5 - 2.5 = 3 + (.5)(Vf2) 1 = 3 + (.5)(Vf2) -2 = (.5)(Vf2) Vf2 = - 4 m/s