Gas Stoichiometry.

Slides:

Advertisements

Similar presentations

Wrap up Proving “R” constant.  We can find out the volume of gas through Stoichiometry CH 4 + O 2  CO 2 + H 2 O22 Think of the coefficients as volume.

Advertisements

Gas Stoichiometry A balanced equation shows the ratio of moles being used and produced Because of Avogrado’s principle, it also shows the ratio of volumes.

April 3, 2014 Stoichiometry. Stoichiometry is the study of quantities of materials consumed and produced in chemical reactions Stoikheion (Greek, “element”)

Stoichiometry II. Solve stoichiometric problems involving moles, mass, and volume, given a balanced chemical reaction. Include: heat of reaction Additional.

I. I.Stoichiometric Calculations Stoichiometry – Ch. 8.

Proportional Relationships b Stoichiometry mass relationships between substances in a chemical reaction based on the mole ratio b Mole Ratio indicated.

Stoichiometry The study of quantities of materials consumed and produced in chemical reactions.

The Mole & Stoichiometry!

Basic Chemistry Copyright © 2011 Pearson Education, Inc. 1 Chapter 11 Gases 11.9 Gas Laws and Chemical Reactions Under water, the pressure on a diver is.

Can’t directly measure moles Measure units related to moles: –Mass (molar mass) –Number of particles (6.02 x ) –Liters of gas (22.4 Liters at STP)

Stoichiometry Mass-Volume Volume-Mass Volume-Volume.

Gas Stoichiometry Section 7.3 pg

Stoichiometric Calculations (p )

Stoichiometry “In solving a problem of this sort, the grand thing is to be able to reason backward. This is a very useful accomplishment, and a very easy.

Gas Stoichiometry Molar volume can be used in stoichiometry calculations to convert quantities of chemicals in a chemical reaction. This ONLY works if.

Bellwork: What is the volume, in liters, of mol of oxygen gas at 20.0ºC and atm pressure? V = ? n = mol T = 20ºC = 293 K P =

Gas Laws Robert Boyle Jacques Charles Amadeo Avogadro

Calculations with Equations

IV. Gas Stoichiometry at Non-STP Conditions (p )

12/10/99 Gas Stoichiometry.

Stoichiometric Calculations (p )

Bellwork: What is the volume, in liters, of mol of oxygen gas at 20.0ºC and atm pressure? V = ? n = mol T = 20ºC = 293 K P =

Unit 8 Stoichiometry Notes

Gas Stoichiometry At STP

Ideal Gas Law PV=nRT.

Gas Stoichiometry Non-STP Conditions.

Clicker #1 When comparing what you’re given to a balanced chemical equation, you must be in units of A) moles B) grams C) molarity D) atm E) Any unit can.

Clicker #1 When comparing what you’re given to a balanced chemical equation, you must be in units of A) moles B) grams C) molarity D) atm E) Any unit can.

12.2 Chemical Calculations

Clicker #1 When comparing what you’re given to a balanced chemical equation, you must be in units of A) moles B) grams C) molarity D) Any unit can be directly.

Gas Laws Robert Boyle Jacques Charles Amadeo Avogadro

Stoichiometric Calculations (p )

Stoichiometric Calculations

12/10/99 Gas Stoichiometry.

Volume and Moles (Avogadro’s Law)

Ch. 11: Molecular Composition of Gases

Molar Volume & Gas Stoichiometry

Unit 4 Stoichiometry Stoichiometry, mol-mol Stoich. , volume-volume

Chemical Calculations

Chapter 12 Stoichiometry 12.2 Chemical Calculations

Chemical Calculations

Gas Stoichiometry at Non-STP Conditions

Gas Laws Robert Boyle Jacques Charles Amadeo Avogadro

Gas Laws Robert Boyle Jacques Charles Amadeo Avogadro

Gas Law Stoichiometry BHS-PS1-9 Level 4.

Ch. 13 – Gases Gas Stoichiometry.

Announcements Prelaboratory Assignment due at the beginning of lab tomorrow (pg. 42 of lab book). Proper dress required for lab! Online HW 4 (Type II)

Clicker #1 When comparing what you’re given to a balanced chemical equation, you must be in units of A) moles B) grams C) molarity D) atm E) Any unit can.

Clicker #1 When comparing what you’re given to a balanced chemical equation, you must be in units of A) moles B) grams C) molarity D) Any unit can be directly.

Warm Up #6 Balance the following:

( ) ( ) ( ) = 2 C6H14(g) + 19 O2 (g) 12 CO2(g) + 14 H20(g) KNOWN

Stoichiometric Calculations **video #18** (p )

( ) ( ) ( ) = 2 C6H14(g) + 19 O2 (g) 12 CO2(g) + 14 H20(g) KNOWN

12/10/99 Gas Stoichiometry.

12/10/99 Gas Stoichiometry.

Stoichiometry “Cookbook Chemistry”.

12/10/99 N-34 Gas Stoichiometry

Stoichiometry of Gases

Gas Stoichiometry.

Chem Get HW stamped off Work on STP Gas Stoichiometry Warm Up Problems

Review Write your answer on a piece of paper:

Stoichiometry Follow along in your text Chapter 9 Section 1 Pages 302 – 311 Put on Pg.33 of your notebook!

STOICHIOMETRY!!!!.

PVm = nRT Molar Volume: Vm = _____ 22.4 L 1 mol the ______ of ______

Mass to volume stoichiometry problems Note handout p. 8

Stoichiometry – Ch. 9 Stoichiometric Calculations **video #18** (stoich: Chem CC) (p )

Stoichiometry volume -to- volume:

Clicker #1 When comparing what you’re given to a balanced chemical equation, you must be in units of A) moles B) grams C) molarity D) atm E) Any unit can.

Presentation transcript:

Gas Stoichiometry

PVm = nRT Molar Volume: Vm = _____ 22.4 L mol the ______ of ______ of any gas at ____. volume 1 mole STP PVm = nRT (1.00 atm) Vm = (1 mol )(0.0821)(273 K) The volume of 1 mole of any gas at STP will be: Vm = _____ 22.4 L mol but… ONLY at STP!!!

Gas Stoichiometry At STP Start with a balanced equation. Convert mass to moles (use molar mass) or volume to moles (use 22.4 L/mol), if necessary. Use mole ratios to calculate moles of unknown. Convert moles to mass (use molar mass) or volume (use 22.4 L/mol), if necessary.

Gas Stoich with Molar Volume What volume of NH3(g) can be produced from reacting completely 11.2 L of N2(g) at STP? 3 H2(g) + N2(g)  2 NH3(g) 1 mol N2 2 mol NH3 22.4 L NH3 11.2 L N2 x x x 22.4 L N2 1 mol N2 1 mol NH3 2 mol NH3 OR 11.2 L N2 x = ____L NH3 22.4 L NH3 1 mol N2

Gas Stoich with Molar Volume Calculate the mass of H2(g) consumed to produce 44.8 L of NH3(g) at STP. 3 H2(g) + N2(g)  2 NH3(g) 1 mol NH3 3 mol H2 2.02 g H2 44.8 L NH3 x x x 22.4 L NH3 2 mol NH3 1 mol H2 = ____g H2 6.06 g H2

Now you try this one alone: What volume of O2 gas is produced when 980 g KClO3 is decomposed at STP? KClO3(s)  KClO(s) + O2(g) 1 mol KClO3 1 mol O2 22.4 L O2 980 g KClO3 x x x 122.55 g KClO3 1 mol KClO3 1 mol O2 = ____L O2 179 L O2 Molar Mass of KClO3 is 122.55 g/mol

Gas Stoichiometry NOT at STP Start with a balanced equation. Convert to moles (if amount is L, use n = PV/RT). Use mole ratios to calculate moles of unknown. Convert moles to desired measurement (to convert to L use V=nRT). P

Gas Stoichiometry NOT at STP Start with a balanced equation. Convert mass to moles (use molar mass) or volume to moles (use PV = nRT), if necessary. Use mole ratios to calculate moles of unknown. Convert moles to mass (use molar mass) or volume (use PV = nRT), if necessary.

KClO3(s)  KClO(s) + O2(g) NOT at STP PV = nRT use… What volume of O2 gas is produced from 490 g KClO3 at 298 K and 1.06 atm? KClO3(s)  KClO(s) + O2(g) 1 mol KClO3 1 mol O2 490 g KClO3 x x = 4.00 mol O2 122.55 g KClO3 1 mol KClO3 (1.06 atm) V = (4.00 mol )(0.0821)(298 K) = ____L O2 92.3 L O2 Molar Mass of KClO3 is 122.55 g/mol