Similar Right Triangles

Slides:



Advertisements
Similar presentations
8-1 Similarity in Right Triangles
Advertisements

Similarity in Right Triangles
Geometric Mean Theorem I
7.1 Geometric Mean.  Find the geometric mean between two numbers  Solve problems involving relationships between parts of right triangles and the altitude.
Altitudes Recall that an altitude is a segment drawn from a vertex that is perpendicular to the opposite of a triangle. Every triangle has three altitudes.
Chapter 7.1 Common Core G.SRT.5 - Use…similarity criteria for triangles to solve problems and to prove relationships in geometric figures. Objective –
Assignment P. 361: 32, 34, 36 P : 1-3, 5-23, 30, 31, 33, 38, 39 Challenge Problems.
MA.912.T.2.1 CHAPTER 9: RIGHT TRIANGLES AND TRIGONOMETRY.
Aim: How do we use ratio, proportion, and similarity effectively? Do now: If the degree measures of two complementary angles are in the ratio of 2 to 13,
Similar Right Triangles
7.4 Similarity in Right Triangles
Section 7.4 Similarity in Right Triangles. Geometric Mean The positive number of x such that ═
9.3 Altitude-On-Hypotenuse Theorems Objective: After studying this section, you will be able to identify the relationships between the parts of a right.
7.4 Similarity in Right Triangles In this lesson we will learn the relationship between different parts of a right triangle that has an altitude drawn.
Section 8-1 Similarity in Right Triangles. Geometric Mean If a, b, and x are positive numbers and Then x is the geometric mean. x and x are the means.
Geometry 8.1 Right Triangles.
7.4 Similarity in Right Triangles
Honors Geometry Warm-up 1/30 Ashwin is watching the Super Bowl on a wide screen TV with dimensions 32” by 18” while Emily is watching it on an old square.
8.4: Similarity in Right Triangles Objectives: Students will be able to… Find the geometric mean between 2 numbers Find and use relationships between similar.
Chapter 7: Proportions and Similarity
9.1 (old geometry book) Similar Triangles
Geometric Mean and Right Triangles
9.3 Altitude-On-Hypotenuse Theorems (a.k.a Geometry Mean)
Geometric and Arithmetic Means
Right Triangles and Trigonometry Chapter Geometric Mean  Geometric mean: Ex: Find the geometric mean between 5 and 45 Ex: Find the geometric mean.
Chapter 8 Lesson 4 Objective: To find and use relationships in similar right triangles.
Geometric Mean and the Pythagorean Theorem
To find the geometric mean between 2 numbers
7.3 Use Similar Right Triangles
7.3 Similar Right Triangles Geometry. Objective(s)  Students will understand geometric concepts and use properties of the altitude of a right triangle.
Similarity in Right Triangles Geometry Unit 11, Day 7 Ms. Reed.
Objective: Students will use proportional parts of triangles and divide a segment into parts. S. Calahan 2008.
Geometry 2-3 Parallel and perpendicular lines. Warm Up Warm Up Lesson Presentation Lesson Presentation California Standards California StandardsPreview.
Proportional Lengths of a Triangle
Use Similar Right Triangles
7.1 Ratio and Proportions -Ratios: A comparison of 2 quantities -Proportion: A statement that 2 ratios are equal -Extended Proportion: When 3 or more ratios.
Pythagorean Theorem Advanced Geometry Trigonometry Lesson 1.
Similar Right triangles Section 8.1. Geometric Mean The geometric mean of two numbers a and b is the positive number such that a / x = x / b, or:
9.3 Altitude-On-Hypotenuse Theorems (a.k.a Geometry Mean)
7.3 Use Similar Right Triangles
9.1 Similar Right Triangles Geometry. Objectives  Solve problems involving similar right triangles formed by the altitude drawn to the hypotenuse of.
Altitudes Recall that an altitude is a segment drawn from a vertex that is perpendicular to the opposite of a triangle. Every triangle has three altitudes.
 Lesson 7-4.  Draw one of the diagonals for your rectangle to form two right triangles. Q: What is the relationship between the two right triangles?
Lesson 7.3 Using Similar Right Triangles Students need scissors, rulers, and note cards. Today, we are going to… …use geometric mean to solve problems.
Key Learning  Solve problems involving similar right triangles formed by the altitude drawn to the hypotenuse of a right triangle.  Use a geometric mean.
8-1 Geometric Mean The student will be able to: 1.Find the geometric mean between two numbers. 2.Solve problems involving relationships between parts of.
9.1 Similar Right Triangles
9.1 Similar Right Triangles
Geometric Mean 7.1.
9.1 Similar Right Triangles
9.1 Similar Right Triangles
Similar Right Triangles
8-1: Similarity in Right Triangles
5.4: The Pythagorean Theorem
concepts, and examples Lesson Objectives: I will be able to …
Similar Right Triangles: Geometric Mean
9.3 Warmup Find the value of x and y
7.3 Use Similar Right Triangles
9.3 Altitude-On-Hypotenuse Theorems
Lesson 13.1 Similar Figures pp
Similar Right Triangles
DO NOW.
Lesson 7.4 Inequalities pp
5.4: The Pythagorean Theorem
Similar Triangles and Proportions
8.1 Geometric Mean The geometric mean between two numbers is the positive square root of their product. Another way to look at it… The geometric mean is.
Using Similar Right Triangles
Similar Right Triangles
Right Triangles with an altitude drawn.
Lesson 5-4: Proportional Parts
Presentation transcript:

Similar Right Triangles Lesson 13.3 Similar Right Triangles pp. 548-553

Objectives: 1. To prove that the altitude to the hypotenuse of a right triangle divides it into two right triangles, each similar to the original. 2. To define and apply geometric means. 3. To compute lengths of sides and related segments for right triangles by using proportions.

Theorem 13.4 An altitude drawn from the right angle to the hypotenuse of a right triangle separates the original triangle into two similar triangles, each of which is similar to the original triangle.

A C D B BDC ~ ABC ADB ~ BDC ADB ~ ABC

In the proportion , notice that the denominator of one ratio is the same as the numerator of the other ratio. When this happens, x is called the geometric mean. b x a =

For example, 8 is the geometric mean between 16 and 4 because = .

EXAMPLE 1 Find the geometric mean between 3 and 27. = x2 = 81 x =  81 x = 9

EXAMPLE 2 Find the geometric mean between 6 and 9. = x2 = 54 x =  54 x = 3 6

Practice: Find the geometric mean between 5 and 25. x 5 = x2 = 125 125 x ± = ≈ 11.2 5 x =

Practice: Find the geometric mean between 12 and 20.

Theorem 13.5 In a right triangle, the altitude to the hypotenuse cuts the hypotenuse into two segments. The length of the altitude is the geometric mean between the lengths of the two segments of the hypotenuse.

D C B A a b x BC DB AB or , b x a =

Theorem 13.6 In a right triangle, the altitude to the hypotenuse divides the hypotenuse into two segments such that the length of a leg is the geometric mean between the hypotenuse and the segment of the hypotenuse adjacent to the leg.

D C B A AC DC BC = AC AD AB =

EXAMPLE 3 Given the measurements in HIJ, find x, y, and z. 4 16 16 x 4 = x2 = 64 x = 8

EXAMPLE 3 Given the measurements in HIJ, find x, y, and z. 4 16 20 y 4 = y2 = 80 y = 4 5

EXAMPLE 3 Given the measurements in HIJ, find x, y, and z. 4 16 20 z 16 = z2 = 320 z = 8 5

Practice: Given: Right JKL. with altitude to the Practice: Given: Right JKL with altitude to the hypotenuse, MK; LJ = 20, and MJ = 4, find KM. K J L M

Practice: Given: Right JKL. with altitude to the Practice: Given: Right JKL with altitude to the hypotenuse, MK; MJ = 4, and KJ = 6, find LJ. K J L M

Homework pp. 552-553

►A. Exercises Solve each proportion; assume that x is positive. 3. x 4 9 =

►A. Exercises Solve each proportion; assume that x is positive. 5. x 2 x – 3 =

7. AD = 15 units; DB = 5 units; find AC ►B. Exercises Given that ∆ABC is a right triangle and DC is an altitude to the hypotenuse, AB, find the length of the indicated sides. 7. AD = 15 units; DB = 5 units; find AC A D B C

9. AB = 32 units; DB = 6 units; find CD ►B. Exercises Given that ∆ABC is a right triangle and DC is an altitude to the hypotenuse, AB, find the length of the indicated sides. 9. AB = 32 units; DB = 6 units; find CD A D B C

11. AD = 6 units; AB = 10 units; find CD ►B. Exercises Given that ∆ABC is a right triangle and DC is an altitude to the hypotenuse, AB, find the length of the indicated sides. 11. AD = 6 units; AB = 10 units; find CD A D B C

13. AD = 11 units; DB = 5 units; find AC ►B. Exercises Given that ∆ABC is a right triangle and DC is an altitude to the hypotenuse, AB, find the length of the indicated sides. 13. AD = 11 units; DB = 5 units; find AC A D B C

15. AD = 12 units; AB = 18 units; find CB ►B. Exercises Given that ∆ABC is a right triangle and DC is an altitude to the hypotenuse, AB, find the length of the indicated sides. 15. AD = 12 units; AB = 18 units; find CB A D B C

■ Cumulative Review Which pairs of figures are similar? For each pair of similar figures, give the scale factor, k. 23. Two circles with radii 3 and 6

■ Cumulative Review Which pairs of figures are similar? For each pair of similar figures, give the scale factor, k. 24. Two rectangles: 6 by 9 and 8 by 12.

■ Cumulative Review Which pairs of figures are similar? For each pair of similar figures, give the scale factor, k. 25. Two rectangles: 6 by 8 and 16 by 18.

■ Cumulative Review Which pairs of figures are similar? For each pair of similar figures, give the scale factor, k. 26. Two regular tetrahedra with sides of length 9 and 6 respectively

■ Cumulative Review Which pairs of figures are similar? For each pair of similar figures, give the scale factor, k. 27. Two squares with sides of length s and t respectively.

Analytic Geometry Slopes of Perpendicular Lines

Theorem If two distinct nonvertical lines are perpendicular, then their slopes are negative reciprocals.

Z(x2, y1) X(x1, 0) Y(x3, 0) W(x2, 0) l1 l2

►Exercises Give the equation of the line perpendicular to the line described and satisfying the given conditions. 1. y = -4/3x + 5 with y-intercept (0, -8)

►Exercises Give the equation of the line perpendicular to the line described and satisfying the given conditions. 2. y = 2x – 1 and passing through (1, 4)

►Exercises Give the equation of the line perpendicular to the line described and satisfying the given conditions. 3. the line containing (2, 5) and (3, 4) at the first point.

►Exercises Give the equation of the line perpendicular to the line described and satisfying the given conditions. 4. y = 1/2x + 5, if their point of intersection occurs when x = 2