Have hmwk out for me to come check GOFORM: Bellringer 9/1/17 On the coordinate plane: graph the points (-3, 4) and (5, -2) Find the distance between the two points. New Seats Have hmwk out for me to come check

Bellringer 9/1/17 On the coordinate plane: graph the points (-3, 4) and (5, -2) Find the distance between the two points.

http://www.mathplayground.com/spaceboyrescue.html http://www.mathplayground.com/locate_aliens.html http://www.math-play.com/Pythagorean-Theorem-Game.html http://www.math4children.com/games-k-to-6/5th%20grade/pythagorean%20theorem/

Agenda Learning Target *Bellringer & Plotting Points Review game *Quiz #2 *Hmwk check any ?’s *PT On Coordinate Plane Practice *If you finish practice early, can do the Pythag Games listed on my website. Learning Target 8.G.B.8 I can apply the Pythagorean Theorem to find the distance between two points in a coordinate system. 8.G.B.7 I can draw a diagram and use the Pythagorean Theorem to solve real world problems involving right triangles.

Pythag Practice on GoForm Solo Time Pythag Practice on GoForm p. 435 #1-3 (basic) #8 p. 438 #20-21 p. 440 #1-6

p. 435 #1-3 (basic) #8

p. 438 #20-21

p. 440 #1-6

Graph on a grid and find the Distance between, turn in EXIT TICKET: Graph on a grid and find the Distance between, turn in R(-4, 5) and Q(8, -2) http://tube.geogebra.org/m/136191

Error Analysis *Highlight the mistake in each solution. *Describe the error. *Solve this problem correctly.

Bellringer~ Error Analysis 8/27/15 *Highlight the mistake in each solution. *Describe the error. *Solve this problem correctly. 5 is the hypotenuse, and they subs. As a side in the formula. 3 squared isn’t 6 it is 9 Just subtracted sides-formula requires sides to be squared The sqrt of 16 is 4 not 8

Math Task Challenge Your team will be solving various tasks. You need to sketch a picture and label it accurately. Then, apply the Pythagorean Theorem to solve. Finally, make any adjustments (measure conversions, etc.) and do a quick write of 1-3 sentences explaining the solution.

Math Task Challenge 2nd   1. Frank Rd and James Rd. make a perpendicular intersection. The state wants to build a new road. The new road will intersect 3 miles north of the intersection on Frank Rd. and 4 miles west of the intersection on James Rd. How long will the new road be that intersects Frank and James Rd? The new road would cost $10,000 per mile to pave. What would be the cost of the new road?

Math Task Challenge 2nd Block   2. You are planning to put a new digital flat TV on a wall that is 12 ft long and 9 ft high. The digital TV has a diagonal of 72 inches. The length of the TV is twice the width of the TV. How much of the wall will still need to be decorated around the TV?

Math Task Challenge   1. Frank Rd and James Rd. make a perpendicular intersection. The state wants to build a new road. The new road will intersect 3 miles north of the intersection on Frank Rd. and 4 miles west of the intersection on James Rd. How long will the new road be that intersects Frank and James Rd? The new road would cost $10 per foot to pave. What would be the cost of the new road?

Math Task Challenge   2. The mobile phone company is anchoring wires to the top of their 1200 ft high communication towers. The cable for the support wire comes in a roll that is 3900 ft long. The company requires you to use the entire roll. The cable can only be cut twice to ensure its strength. All cables need to be equal. How long will each cable be and how far from the base of the tower do they need to be anchored?

Math Task Challenge   3. In the city planning meeting, a scale drawing of a park was drawn. The park fills inside a square city block. The scale was 3 inches equal 3/10 miles. One side of the city blocks was 4 inches in the drawing. One member of the city planners said, " There needs to be a short cut through the park from the corners." How long in miles will the short cut be? Round answers to the nearest tenth of a mile.

Math Task Challenge   4. You are planning to put a new digital flat TV on a wall that is 12 ft long and 9 ft high. The digital TV has a diagonal of 72 inches. The length of the TV is twice the width of the TV. How much of the wall will still need to be decorated around the TV?

2. 64.3 sq in length rounded to 5ft total area for TV is 15 sq ft Pythagorean Math Tasks Solutions Answers   5 miles long cost $50,000 2. 64.3 sq in length rounded to 5ft total area for TV is 15 sq ft remaining area around TV is 93 sq ft.

2. 1300 ft cables, 500 ft from the tower about 6/10 miles Pythagorean Math Tasks Solutions Answers   5 miles long cost $264,000 2. 1300 ft cables, 500 ft from the tower about 6/10 miles 3. 32.2 sq in width rounded to 3 ft 4. 64.3 sq in length rounded to 5ft total area for TV is 15 sq ft remaining area around TV is 93 sq ft.

Homework  Pencils on floor.

Show your work on a piece of paper. You will be turning in your work. Review Kahoot Show your work on a piece of paper. You will be turning in your work. https://play.kahoot.it/#/k/44516a38-1179-4dd5-9f7c-8e2f23081666

Pythagorean Ther. also used in 3D situations Find My Phone Pythagorean Ther. also used in 3D situations http://www.city-data.com/towers/cell-Knoxville-Tennessee.html

Find My Phone The app says my phone is 68 feet away from the signal. The tower measures 30 feet high-where should I look?

Triangulation uses 3 towers and their intersecting ranges to more accurately locate a device. http://www.cloudetal.com/triangulation-fun-time-with-maths

Triangulation in the Movies Your text here Triangulation in the Movies https://www.youtube.com/watch?v=HUg1BPIGEzo Independence Day 37 mins into http://www.dailymotion.com/video/x2klkye

Find My Phone The app says my phone is 68 feet away from the signal. The tower measures 30 feet high-where should I look? 68 ft?

Find My Phone The app says my phone is 68 feet away from the signal. The tower measures 30 feet high-where should I look? 68 ft?

Find My Phone If we assume the phone is on the ground can we use PT to determine how far away from the base? The app says my phone is 68 feet away from the signal. The tower measures 30 feet high-where should I look? 68 ft 30ft ?

Find My Phone 68 ft 30ft ? 𝑎 2 + 𝑏 2 = 𝑐 2 30 2 + 𝑏 2 = 68 2 900+ 𝑏 2 =4624 −900 =−900 𝑏 2 =3724 𝑏 2 = 3724 𝑏=61.02 ft

Bellringer 8/18/16 A B C D

Bellringer 8/18/16 A B C D