Low Velocity Air Measurements (timed smoke clouds) 14 sec 12 sec 13 sec 16 sec 13 sec 15 sec 14 sec 14 sec 13 sec 14 sec 14 sec 15 sec The time.

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Presentation transcript:

Low Velocity Air Measurements (timed smoke clouds) 14 sec 12 sec 13 sec 16 sec 13 sec 15 sec 14 sec 14 sec 13 sec 14 sec 14 sec 15 sec The time it took the leading edge of the smoke cloud to travel 10 feet was recorded (4 times in each quadrant). 8.0’ 8.2’ 7.9’ 19.7’ The dimensions of the mine entry were measured. H + H + H 1 3 2 Average H = (sum of all times) Average time = A = W x H (number of times) (distance) 60 sec Average V = x x 0.9 (average time) 1 min

Low Velocity Air Measurements (timed smoke clouds) 8.0’ 8.2’ 7.9’ 19.7’ The dimensions of the mine entry were measured. 14 sec 12 sec 13 sec 16 sec 13 sec 14 sec 14 sec 15 sec H + H + H 1 2 3 14 sec 14 sec 13 sec 15 sec 13 sec 15 sec Average H = 3 The time it took the leading edge of the smoke cloud to travel 10 feet was recorded. 8.0’+8.2’+7.9’ Average H = = 8.0’ 3 (223 sec) Average time = = 13.9 sec A = W x H (16) A = 19.7’ x 8.0’ (10’) 60 sec Average V = x x 0.9 (13.9 sec) 1 min A = 158 sq.ft. Average V = 39 fpm q = V x A q = 39 fpm x 158 sq.ft. = 6162 cfm

Low Velocity Air Measurements (timed smoke clouds) 14 sec 13 sec 14 sec 15 sec no movement 4.5’ 4.7’ 4.4’ 20.4’ 15 sec 14 sec 13 sec 14 sec no movement The dimensions of the mine entry were measured. The time it took the leading edge of the smoke cloud to travel 5 feet was recorded (4 times in each quadrant). H + H + H 1 3 2 Average H = (sum of all times) (number of times) Average time = A = W x H (distance) (average time) Average V = 60 sec 1 min x x 0.9

Low Velocity Air Measurements (timed smoke clouds) 4.5’ 4.7’ 4.4’ 20.4’ 14 sec 13 sec 14 sec 15 sec The dimensions of the mine entry were measured. no movement 15 sec 14 sec 13 sec 14 sec no movement H + H + H 1 2 3 Average H = The time it took the leading edge of the smoke cloud to travel 5 feet was recorded. 3 4.5’+4.7’+4.4’ Average H = = 4.6’ (112 sec) 3 Average time = = 14 sec (8) A = W x H (5’) 60 sec A = 20.4’ x 4.6’ Average V = x x 0.9 (14 sec) 1 min A = 93.8 sq.ft. (93.8 sq.ft.) Average V = 19 fpm Effective Area = 2 Effective Area = 47 sq.ft. q = V x A q = 19 fpm x 47 sq.ft. = 893 cfm