Mendel’s Contribution(s)?
This Week Finish C. elegans experiment, Tinker with wasps, Exam Review (April 20th) Exam I (April 23rd), Basic Mendel! C. elegans! Bioinfomatics! Nasonia!
Mendel’s First Postulate Unit Factors in Pairs Genetic characteristics are controlled by unit factors that exist in pairs* in individual organisms, each individual receives one unit factor from each parent*, in a monohybrid cross, three combinations of unit factors are possible, * not in Nasonia males!
Mendel’s Second Postulate Dominant/Recessive When two unlike unit factors are present in a single individual, one unit factor is dominant to the other, which is said to be recessive.
Mendel’s Third Postulate Segregation During the processes of heredity, the paired unit factors separate so that the offspring receives one unit factor from each parent, The unit factors segregate to offspring randomly.
Mendel’s Forth Postulate Independent Assortment How do two traits segregate in the offspring of an individual that is heterozygous for both traits?
Independent Assortment …checking complementation in the F2 P: F1: F2: AAdd x aaDD AaDd 9: A_D_ 3: aaD_ 3: A_dd 1: aadd P: F1: F2: aadd x AADD AaDd 9: A_D_ 3: aaD_ 3: A_dd 1: aadd Both Recessive? Both Dominant? One of each? 9:7 wt : mut 1:15 wt : mut 3:13 wt : mut
P to F1 Haplo/Diplo: Thinking about complementation groups… Both recessive: aaDD x Ad female: AaDd, male aD Both Dominant: aaDD x Ad female: AaDd, male aD One dominant*: aadd x AD female: AaDd, male ad or… AADD x ad female: AaDd, male AD * need to define which is dominant!
P to F1 to “F2” Haplo/Diplo: Thinking about complementation groups… Both recessive: aaDD x Ad female: AaDd ¼AD + ¼Ad + ¼aD + ¼ad Both Dominant: aaDD x Ad female: AaDd ¼AD + ¼Ad + ¼aD + ¼ad One dominant*: aadd x AD female: AaDd ¼AD + ¼Ad + ¼aD + ¼ad or… AADD x ad female: AaDd ¼AD + ¼Ad + ¼aD + ¼ad * need to define which is dominant!
Forked-Line Method Haplo/Diplo F2 AaDd x AD. ( Forked-Line Method Haplo/Diplo F2 AaDd x AD* (*male genotype could be ad, aD, Ad) 1/2 x 1/2 = 1/4 AD 1 AD = ¼ AADD ½ D ½ d 1/2 D 1/2 A 1/2 a 1/2 x 1/2 = 1/4 Ad 1 AD = ¼ AADd 1/2 x 1/2 = 1/4 aD 1 AD = ¼ AaDD 1/2 x 1/2 = 1/4 ad 1 AD = ¼ AaDd
Forked-Line Method Haplo/Diplo F2 AaDd x AD. ( Forked-Line Method Haplo/Diplo F2 AaDd x AD* (*male genotype could be ad, aD, Ad) 1/4 AD 1/4 Ad 1/4 aD 1/4 ad x 1 AD = ¼ AADD 1/4 AD 1/4 Ad 1/4 aD 1/4 ad x 1 ad = ¼ AaDd x 1 AD = ¼ AADd x 1 ad = ¼ Aadd x 1 AD = ¼ AaDD x 1 ad = ¼ aaDd x 1 AD = ¼ AaDd x 1 ad = ¼ aadd Have Fun! 1/4 AD 1/4 Ad 1/4 aD 1/4 ad x 1 aD = ¼ AaDD 1/4 AD 1/4 Ad 1/4 aD 1/4 ad x 1 Ad = ¼ AADd x 1 aD = ¼ AaDd x 1 Ad = ¼ AAdd x 1 aD = ¼ aaDD x 1 Ad = ¼ aaDd x 1 aD = ¼ aaDd x 1 Ad = ¼ Aadd
Lab Life Cycles
Wasp Development Timelines Life Cycles, Mating, etc.
C. elegans Nomenclature Tower of Babel
This Week Wednesday, Friday, score F3s, discuss Mendel Review Formal Lab Write-Up, think about or tinker with wasps? Friday, midterm,