THANKSGIVING H.W. ANSWERS K2Cr2O7 K 2 mol x 39.00 g/mol = 78.00 g Cr 51.996 g/mol= 103.992 g O 7mol x 15.99 g/mol= 111.93 g 1a) Molar mass (GFM) = 293.992 g/mol 1b) 2 moles of K are in I mole of K2Cr2O7 1c)How many moles are in the 150.00 grams of ( ) 150.0 g 1 ( ) 293 g 1 mol =0.5102mol K2Cr2O7 K2Cr2O7

( ) ( ) ( ) ( ) ( ) ( ) 1c) How many particles are in the 150.00 g 1 mol ( ) 1 mol 6.02 x 1023 particles = 3.07 x 1023 molecules K2Cr2O7 1d) What is the mass of 12.04 x 1023 particles of K2Cr2O7 ( ) ( ) ( ) 12.01 x 1023 particles 1 mol 293 g = 3.07 x 1023 molecules K2Cr2O7 1 6.02 x 1023 particles 1 mol

( ) ( ) ( ) ( ) ( ) ( ) 1 mol 17 g 51.0 g NH3 1 1 mol 2a-b)what is the mass of 18.06 x 1023 particles of NH3 (gfm=17g/mol) ( ) ( ) ( ) 18.06 x 1023 PARTICLES 1 mol 17 g 51.0 g NH3 1 6.02 x 1023 PARTICLES 1 mol 2c) What is the mass of 12.04 x 1023 particles of K2Cr2O7 ( ) 18.06 x 1023 particles 1 ( ) ( ) 1 mol 22.4L =67.2 L NH3 6.02 x 1023 particles 1 mol

( ) ( ) ( ) ( ) Pb(NO3)2 Molar mass (GFM) = 331.152 g/mol Pb 1 mol x 3)How many grams of lead nitrate = the moles of 150.00 grams of ( ) 150.0 g 1 ( ) 293 g 1 mol K2Cr2O7 ? =0.5102 mol K2Cr2O7 ( ) ( ) 331.152 g 0.5102 mol 168.954 g= Pb(NO3)2 1 1 mol Pb(NO3)2 Pb 1 mol x 207.2 g/mol = 207.20 g N 2 mol x 14.006 g/mol= 28.012 g O 6mol x 15.99 g/mol= 95.94 g Molar mass (GFM) = 331.152 g/mol