Arrays of Two-Dimensions Syntax ( in Algorithm ): Syntax ( in C++ ): Array aname [nrows] [ncolumns] of atype Example: //declaring array B of 2 rows and 3 columns Array B [2] [3] of type integer atype aname [nrows] [ncolumns] ; int B [2] [3] ; Array in diagram:

Arrays of Two-Dimensions Reading array of two-dimensions: Syntax ( in Algorithm ): Syntax ( in C++ ): Array B [2] [3] of type integer for ( i  1 to 2 by 1 ) do for ( j  1 to 3 by 1 ) do input B[i][j] End for int B [2] [3] ; int i , j ; for ( i = 0 ; i < 2 ; i++ ) for ( j = 0 ; j < 3 ; j++ ) cin >> B[ i ] [ j ] ;

Example1 Write algorithm and a C++ program that reads array A of size (2 x 3) and finds the sum of the elements in each column. Algorithm sum_columns begin Array B[2][3] of type integer output "Enter 6 array elements: " for ( i 1 to 2 by 1 ) do for ( j1 to 3 by 1)do input B[i][j] End for End for // Process the array now clmsum  clmsum + B[i][j] output " sum of column no. " , j , " is " , clmsum clmsum  0 End sum_columns 3

Example1 #include <iostream> void main ( ) using namespace std; void main ( ) { int i, j , clmsum = 0 ; int B[2][3]; cout << "Enter 6 array elements: " ; for ( i = 0 ; i < 2 ; i++ ) for ( j = 0 ; j < 3 ; j++) cin >> B[i][j] ; // Process the array now { clmsum = clmsum + B[i][j] ; cout << " sum of column no. " << j << " is " << clmsum<<endl; clmsum = 0; }

Example2 of Two-Dimensional Array Write algorithm and a C++ program that reads an array of size (3 x 3) and finds the product of the diagonal elements.

Example2(Algorithm) Algorith Product_D_E Begin Array B[3][3] of type integer product  1 output "Enter the 9 array elements: " for ( i  1 to 3 by 1 ) do for ( j  1 to 3 by 1 ) do input B[i][j] End for // Process the array now if ( i = j ) then product  product * B[i][j] End if output " The product of the diagonal elements = " , product End Product_D_E

Example2(C++) #include <iostream> Using namespace std; void main ( ) { int i, j , product = 1 ; int B[3][3]; cout << "Enter the 9 array elements: " ; for ( i = 0 ; i <3 ; i++ ) for ( j = 0 ; j < 3 ; j++) cin >> B[i][j] ; // Process the array now for ( i = 0 ; i < 3 ; i++) for ( j = 0 ; j < 3 ; j++ ) if ( i == j ) product = product * B[i][j] ; cout << " The product of the diagonal elements = " << product << endl; }