CSSE463: Image Recognition Day 14

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CSSE463: Image Recognition Day 14 Market analysis headline: “The image recognition market is estimated to grow from $9.65 billion in 2014 to $25.65 billion by 2019.” Lab due Weds. These solutions assume that you don't threshold the shapes.ppt image: Shape1: elongation = 1.632636, C1 = 19.2531, C2 = 5.0393 Feedback on midterm plus/delta Projects/labs reinforce theory; interesting examples, topics, presentation; favorite class; enjoying Lecture and assignment pace OK or slightly off. This week: Tuesday: Support Vector Machine (SVM) Introduction and derivation Thursday: Project info, SVM demo Friday: SVM lab

SVMs: “Best” decision boundary Consider a 2-class problem Start by assuming each class is linearly separable There are many separating hyperplanes… Which would you choose?

SVMs: “Best” decision boundary The “best” hyperplane is the one that maximizes the margin, r, between the classes. Some training points will always lie on the margin These are called “support vectors” #2,4,9 to the left Why does this name make sense intuitively? margin r Q1

Support vectors The support vectors are the toughest to classify What would happen to the decision boundary if we moved one of them, say #4? A different margin would have maximal width! Q2

Problem Maximize the margin width while classifying all the data points correctly…

Mathematical formulation of the hyperplane On paper Key ideas: Optimum separating hyperplane: Distance to margin: Can show the margin width = Want to maximize margin Q3-4

Finding the optimal hyperplane We need to find w and b that satisfy the system of inequalities: where w minimizes the cost function: (Recall that we want to minimize ||w0||, which is equivalent to minimizing ||wop||2=wTw) Quadratic programming problem Use Lagrange multipliers Switch to the dual of the problem

Non-separable data Allow data points to be misclassifed But assign a cost to each misclassified point. The cost is bounded by the parameter C (which you can set) You can set different bounds for each class. Why? Can weigh false positives and false negatives differently

Can we do better? Cover’s Theorem from information theory says that we can map nonseparable data in the input space to a feature space where the data is separable, with high probability, if: The mapping is nonlinear The feature space has a higher dimension The mapping is called a kernel function. Replace every instance of xixj in derivation with K(xixj) Lots of math would follow here to show it works Example: separate x1 XOR x2 by adding a dimension x3 = x1x2

Most common kernel functions Polynomial Gaussian Radial-basis function (RBF) Two-layer perceptron You choose p, s, or bi My experience with real data: use Gaussian RBF! Easy Difficulty of problem Hard p=1, p=2, higher p RBF Q5