Give Chapter 12 HW on Thursday test day Then do 8 – Friday, 9 – Monday, 10 – Tuesday, 11 – Wednesday, 12 – Thursday the following week, then free review days Friday and Monday

R—05/31/12—HW #73: Pg 778-779: 1—11 all; Pg 825-826: 1—35 odd, 34 2) E 4) C 6) D 8) A 10) C 34) 288.89pi, 666.67pi

Chapter 12 Review

Is it a polyhedron. If so, count the faces, edges, and vertices Is it a polyhedron? If so, count the faces, edges, and vertices. Also say whether or not it is convex. Yes 7 faces, 15 edges 10 vertices Convex Yes 6 faces, 12 edges 8 vertices Convex Euler’s Theorem: F + V = E + 2 (Like FAVE two, or cube method)

Terms P  Perimeter of one base B  Area of base b  base (side) h  Height (relating to altitude) l  Slant Height TA  Total Area (Also SA for surface Area) LA  Lateral Area V  Volume

Lateral Area of a right prism is the sum of area of all the LATERAL faces. = bh + bh + bh + bh = (b + b + b + b)h LA = Ph Total Area is the sum of ALL the faces. TA = 2B + Ph

Cylinder

Find the LA, SA of this rectangular prism. Height = 8 cm Radius = 4 cm 5 3 8 LA = SA = (22)5 = 110 units2

b l + b l + b l + b l + b l (b + b + b + b + b) l = Pl Lateral Area of a regular pyramid is the area of all the LATERAL faces. Total area is area of bases. TA = B + Pl b l + b l + b l + b l + b l (b + b + b + b + b) l = Pl

Cone

Find Lateral Area, Total Area 13 cm 10 cm Slant Height = 15 in. Radius = 9 in

Altitude is segment perpendicular to the parallel planes, also referred to as “Height”. Volume of a right prism equals the area of the base times the height of the prism. V = Bh Prism

Find the V of this triangular prism. 8 4 3 5

Find Volume Height = 8 cm Radius = 4 cm Cylinder

Cone Slant Height = 15 in. Radius = 9 in 10 cm 13 cm

Find SA and V with radius 6 m.

Circumference of great circle Radius of Sphere Circumference of great circle Surface Area of Sphere Volume of sphere 3 m 4π in2 6π cm 9π ft3 2

Two shapes are similar if all the the sides have the same scale factor. If the scale factor of two similar solid is a:b, then The ratio of the corresponding perimeters is a:b The ratio of the base areas, lateral areas, and total areas is a2:b2 The ratio of the volumes is a3:b3 There be a problem where they give you area or volume, you must convert correctly to other ratio, set up proportion, then solve. We will talk about these.

R—05/31/12—HW #73: Pg 778-779: 1—11 all; Pg 825-826: 1—35 odd, 34