On average, there are 3(4.42) =13.26 claims waiting be processed.

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On average, there are 3(4.42) =13.26 claims waiting be processed. Problem 8.8 Ri = 3.5 /week Ri = 3.5/5 = .7 /day Tp = 1.2 day Rp = 1/1.2 = .833 /day a1) Across all districts, on average, how many claims are waiting to be processed. On average, there are 3(4.42) =13.26 claims waiting be processed.

A2) what fraction of claims is completed in less than 10 business days A2) what fraction of claims is completed in less than 10 business days? T≤ 10 Whenever there is no info on CV, assume Poisson Process In the above example with utilization = 0.84 Suppose we check the claim processor at 100 random times. On average on how many times is s/he processing a claim? 84% one customer, 16% no customer. On average .84 customer are in the server. In a single server ρ customer are served, in multi server cρ customers

We can reach the same conclusion using the Little’s law

We need to compute T: Average time in the system A2) what fraction of claims is completed in less than 10 business days? T≤ 10 We need to compute T: Average time in the system Alternatively

Three Servers, Poisson Process Combined Individual

b) One Server, Reduced Cp from 1 to .5 Rduction is service time variability, improves the probability from 73.6% to 86%