Kp = Kc(RT)∆n Kp = Kc(RT)∆n = 0.042(RT)-1 = 0.042/RT #17..ch15) PCl3 + Cl2  PCl5 ∆n = -1 Kp = Kc(RT)∆n = 0.042(RT)-1 = 0.042/RT Kp = 0.042 = 0.001024 = 0.001 (0.08206)(500) Kp = Kc(RT)∆n

#20 ch15) A) 2 NO(g) + O2(g)  2 NO2 (g) Kp forward = P2 NO2 = 1.48 * 104 P2 NO * P O2 B) 2 NO2 (g)  2 NO(g) + O2(g) Kp reverse = P2 NO * P O2 = 1 = 6.76 * 10-5 P2 NO2 1.48 * 104 NO2 is favored as the K of its formation is greater than for its consumption.

#27 ch 15) Kc = [H2 ] [ I2 ] = (4.79 * 10-4)( 4.79 * 10-4) = 0.018413 = 0.0184 [HI]2 (3.53 * 10-3)2 #30 CH 15) Kp = P PCl5 = 1.30 ATM = 66.8 P PCl3 * P CL2 0.124 ATM * 0.157 ATM PRODUCTS ARE FAVORED, K > 1 2 HI (g)  H2(g) + I2(g) PCl3 (g) + Cl2 (g)  PCl5 (g)