Using letters Write five expressions which simplify to 2a – b + 3

Slides:



Advertisements
Similar presentations
Solve an equation with variables on both sides
Advertisements

Solve an equation by combining like terms
Solve an equation using subtraction EXAMPLE 1 Solve x + 7 = 4. x + 7 = 4x + 7 = 4 Write original equation. x + 7 – 7 = 4 – 7 Use subtraction property of.
Standardized Test Practice
Lesson 2-4. Many equations contain variables on each side. To solve these equations, FIRST use addition and subtraction to write an equivalent equation.
Standardized Test Practice
Standardized Test Practice
© 2007 by S - Squared, Inc. All Rights Reserved.
EXAMPLE 2 Rationalize denominators of fractions Simplify
1.4 Solving Equations ●A variable is a letter which represents an unknown number. Any letter can be used as a variable. ●An algebraic expression contains.
Solving Multi- Step Equations. And we don’t know “Y” either!!
Evaluating Algebraic Expressions 1-7 Solving Equations by Adding or Subtracting Preparation for AF4.0 Students solve simple linear equations and inequalities.
Solve an equation by combining like terms EXAMPLE 1 8x – 3x – 10 = 20 Write original equation. 5x – 10 = 20 Combine like terms. 5x – =
5.3: Solving Addition Equations Goal #1: Solving Addition Problems Goal #2: Writing Addition Equations.
Do Now (3x + y) – (2x + y) 4(2x + 3y) – (8x – y)
Multi-Step Equations We must simplify each expression on the equal sign to look like a one, two, three step equation.
Solve an equation using addition EXAMPLE 2 Solve x – 12 = 3. Horizontal format Vertical format x– 12 = 3 Write original equation. x – 12 = 3 Add 12 to.
Example 1 Solving Two-Step Equations SOLUTION a. 12x2x + 5 = Write original equation. 112x2x + – = 15 – Subtract 1 from each side. (Subtraction property.
Solving Linear Equations Substitution. Find the common solution for the system y = 3x + 1 y = x + 5 There are 4 steps to this process Step 1:Substitute.
Bell Ringer 2. Systems of Equations 4 A system of equations is a collection of two or more equations with a same set of unknowns A system of linear equations.
© 2007 by S - Squared, Inc. All Rights Reserved.
Topic 6.5. Solve Systems by Substitution Objectives: Solve Systems of Equations using Substitution Standards: Functions, Algebra, Patterns. Connections.
Solving Equations. An equation links an algebraic expression and a number, or two algebraic expressions with an equals sign. For example: x + 7 = 13 is.
1.4 Solving Equations.
EXAMPLE 2 Rationalize denominators of fractions Simplify
Preview Warm Up California Standards Lesson Presentation.
Objective 3.6 solve multi-step inequalities.
Solve for variable 3x = 6 7x = -21
Solve an equation by multiplying by a reciprocal
Multi-Step Equations with variable(s) on one side
One-Step Equations with Subtraction
3. Further algebraic skills and techniques
3-2: Solving Systems of Equations using Substitution
Radicals.
Introduction Two equations that are solved together are called systems of equations. The solution to a system of equations is the point or points that.
6-3 Solving Systems Using Elimination
Solving Algebraic Equations
3-2: Solving Systems of Equations using Substitution
Simplifying expressions
Solving Systems of Equations using Substitution
What angles greater than 180 could be measured? 10°
Do Now 1) t + 3 = – 2 2) 18 – 4v = 42.
3-2: Solving Systems of Equations using Substitution
Solve an equation by combining like terms
1.4 Solving Equations I’ve taught you how to solve equations the “simonized” way but here’s another way of doing the same thing!
Solving Multi-Step Equations
Solving Equations Finding Your Balance
Solving 1-Step Integer Equations
Multi-Step Equations Notes and Practice.
Algebraic fractions [ A2.1 Core Plenary]
Formulae and expressions
Learning Objective Students will be able to: Solve equations in one variable that contain absolute-value expressions.
What number is he thinking of? 2x = x + 4 so x = 4 (a) 2x + x = 39
3-2: Solving Systems of Equations using Substitution
Equations …. are mathematical sentences stating that two expressions are equivalent.
Algebra 1 Section 2.7.
Section 6.1 Solving Inequalities Using Addition or Subtraction
Lesson 7-6 Multiplying a Polynomial by a Monomial
Solving Equations.
Example 2B: Solving Linear Systems by Elimination
3-2: Solving Systems of Equations using Substitution
3-2: Solving Systems of Equations using Substitution
One-Step Equations with Addition and Subtraction
Adding and subtracting fractions
3-2: Solving Systems of Equations using Substitution
3-2: Solving Systems of Equations using Substitution
Solving Equations with Fractions
Expressions [ A1.2 Extension Plenary]
Formulae and expressions
Presentation transcript:

Using letters Write five expressions which simplify to 2a – b + 3 [ A1.1 Core Starter] Write five expressions which simplify to 2a – b + 3 Make them as complicated as you can! Check each other’s expressions to make sure they are correct. Write five equations which have x = 2 as their solution. Check that each other’s equations have the correct solution x = 2. Preamble This activity, suitable for small groups, gives pupils the opportunity think a little deeper about simplifying and substituting into expressions, it gives practice in solving simple equations. Pupils, if possible, should be encouraged to move out of their comfort zone and devise complicated expressions. Obviously checking answers is an all important part of the activity and this could be done between small groups. If pupils are unsure you could start with: simplify the example to 1 variable. E.g.: 2a + 3 Make the expression into an equation by using the equals sign. E.g.: 2a + 3 = 7 This would also provide an opportunity to explain the difference between an expression and an equation. Possible content Simplifying and substituting into algebraic expressions Solution/Notes Pupils’ own expressions and equations. Possible examples for the 5 expressions: Add /subtract a number to both sides: 2a – b + 5 = 2 (2 added to both sides) Add/subtract a and/or b to both sides: 2a + 4b + 3 = 5b (5b added to both sides) Multiply/divide by a number: 6a – 3b + 9 (multiplied by 3) Including a variable that cancels: 2a – b + 2c + 3 = 2c Possible examples for 5 equations : Pupils could start with simple examples, but encourage them to not use a repeating strategy such as x + 1 = 3, 2x + 1 = 5, 3x + 1 = 7 Encourage pupils to use combinations to create multi-stage equations such as 4(3x -2) = 20 – 4 Pupils may quite happily use x on both sides in this context such as 5x + 3 = 7x - 1 Original Material © Cambridge University Press 2010 Original Material © Cambridge University Press 2010