Hough Transform.

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Presentation transcript:

Hough Transform

Finding lines in an image Option 1: Search for the line at every possible position/orientation What is the cost of this operation? Option 2: Use a voting scheme: Hough transform

Finding lines in an image y b b0 x m0 m image space Hough space Connection between image (x,y) and Hough (m,b) spaces A line in the image corresponds to a point in Hough space To go from image space to Hough space: given a set of points (x,y), find all (m,b) such that y = mx + b

Finding lines in an image y b A: the solutions of b = -x0m + y0 this is a line in Hough space y0 x0 x m image space Hough space Connection between image (x,y) and Hough (m,b) spaces A line in the image corresponds to a point in Hough space To go from image space to Hough space: given a set of points (x,y), find all (m,b) such that y = mx + b What does a point (x0, y0) in the image space map to?

Hough transform algorithm Typically use a different parameterization d is the perpendicular distance from the line to the origin  is the angle this perpendicular makes with the x axis Why?

Hough transform algorithm Typically use a different parameterization d is the perpendicular distance from the line to the origin  is the angle this perpendicular makes with the x axis Why? Basic Hough transform algorithm Initialize H[d, ]=0 for each edge point I[x,y] in the image for  = 0 to 180 H[d, ] += 1 Find the value(s) of (d, ) where H[d, ] is maximum The detected line in the image is given by What’s the running time (measured in # votes)?

Extensions Extension 1: Use the image gradient same for each edge point I[x,y] in the image compute unique (d, ) based on image gradient at (x,y) H[d, ] += 1 What’s the running time measured in votes? Extension 2 give more votes for stronger edges Extension 3 change the sampling of (d, ) to give more/less resolution Extension 4 The same procedure can be used with circles, squares, or any other shape

Extensions Extension 1: Use the image gradient same for each edge point I[x,y] in the image compute unique (d, ) based on image gradient at (x,y) H[d, ] += 1 What’s the running time measured in votes? Extension 2 give more votes for stronger edges Extension 3 change the sampling of (d, ) to give more/less resolution Extension 4 The same procedure can be used with circles, squares, or any other shape

Hough demos A video that explains Hough transforms for lines and circles: A demonstrations for line detection on an image : https://www.youtube.com/watch?v=4zHbI-fFIlI Circle : http://www.markschulze.net/java/hough/

Hough Transform for Curves The H.T. can be generalized to detect any curve that can be expressed in parametric form: Y = f(x, a1,a2,…ap) a1, a2, … ap are the parameters The parameter space is p-dimensional The accumulating array is LARGE! For circle: vote on x0, y0, r

H.T. Summary H.T. is a “voting” scheme points vote for a set of parameters describing a line or curve. The more votes for a particular set the more evidence that the corresponding curve is present in the image. Can detect MULTIPLE curves in one shot. Computational cost increases with the number of parameters describing the curve.