Lecture Objectives Finish the cooling load example Learn about Heating Systems
HW2 due date Moved to March 5th On Friday we will have TA office hours to help with specific questions for this HW
Example problem Calculate the cooling load for the building in Pittsburgh PA with the geometry shown on figure. On east north and west sides are buildings which create shade on the whole wall. Windows: Champion Window CDP number CHW-A-8 https://www.energystar.gov/products/most_efficient/horizontal_slider_windows Walls: 4” face brick + 2” insulation + 4” concrete block, Uvalue = 0.1, Dark color Roof: 2” internal insulation + 4” concrete , Uvalue = 0.120 , Dark color Below the building is basement wit temperature of 75 F. Internal design parameters: air temperature 75 F Relative humidity 50% Find the amount of fresh air that needs to be supplied by ventilation system.
Example problem (continuing) Internal loads: 10 occupants, who are there from 8:00 A.M. to 5:00 P.M. doing moderately active office work 1 W/ft2 heat gain from computers and other office equipment from 8:00 A.M. to 5:00 P.M. 0.2 W/ft2 heat gain from computers and other office equipment from 5:00 P.M. to 8:00 A.M. 0.5 W/ft2 heat gain from suspended fluorescent lights from 8:00 A.M. to 5:00 P.M. 0.1 W/ft2 heat gain from suspended fluorescent lights from 5:00 P.M. to 8:00 A.M. Infiltration: 0.5 ACH per hour
Example solution SOLUTION steps (see handouts): 1. Calculate cooling load from conduction through opaque surfaces using TETD. 2. Calculate conduction and solar transmission through windows. 3. Add sensible internal gains and infiltration. 4. The result is your raw sensible cooling load. 5. Calculate latent internal gains. 6. Calculate latent gains due to infiltration. 7. The sum of 5 and 6 is your raw latent cooling load.
Example solution SOLUTION: For which hour to do the calculation ? With computer calculation for all and select the largest.
Example solution For which hour to do the calculation when you do manual calculation? Identify the major single contributor to the cooling load and do the calculation for the hour when the maximum cooling load for this contributor appear. For example problem major heat gains are through the roof or solar through windows! Roof: maximum TETD=61F at 6 pm (Table 2.12) South windows: max. SHGF=109 Btu/hft2 at 12 am (July 21st Table 2.15 A) If you are not sure, do the calculation for both hours: at 6 pm Roof gains = A x U x TETD = 900 ft2 x 0.12 Btu/hFft2 x 61 F = 6.6 kBtu/h Window solar gains = A x SC x SHGF =80 ft2 x 0.71 x 10 Btu/hft2 = 0.6 kBtu/h total = 7.2 kBtu/h at 12 am Roof gains = A x U x TETD = 900 ft2 x 0.12 Btu/hFft2 x 30 F = 3.2 kBtu/h Window solar gains = A x SC x SHGF =80 ft2 x 0.71 x 109 Btu/hft2 = 6.2 kBtu/h total= 9.4 kBtu/h For the example critical hour is July 12 AM.
Solution On the board
Heating systems
Choosing a Heating System What is it going to burn? What is it going to heat? How much is it going to heat it? What type of equipment? Where are you going to put it? What else do you need to make it work?
Choosing a Fuel Type Availability Storage Cost Code restrictions Emergencies, back-up power, peak demand Storage Space requirements, aesthetic impacts, safety Cost Capital, operating, maintenance Code restrictions Safety, emissions
Selecting a Heat Transfer Medium Air Not very effective (will see later) Steam Necessary for steam loads, little/no pumping But: lower heat transfer, condensate return, bigger pipes Water Better heat transfer, smaller pipes, simpler But: requires pumps, lower velocities, can require complex systems
Choosing Water Temperature Low temperature water (180 °F – 240 °F) single buildings, simple Medium and high temperature (over 350 °F) Campuses where steam isn’t viable/needed Requires high temperature and pressure equipment Nitrogen system to prevent steam formation
Choosing Steam Pressure Low pressure (<15 psig) No pumping for steam Requires pumping/gravity for condensate Medium and high-pressure systems Often used for steam loads
Steam Systems Steam needs bigger pipes for same heat transfer Water is more dense and has better heat transfer properties
What About Air? Really bad heat transfer medium But ! Very low density and specific heat Requires electricity for fans to move air Excessive space requirements for ducts But ! Can be combined with cooling Lowest maintenance Very simple equipment Still need a heat exchanger
Furnace Load demand, load profile Efficiency Combustion air supply Amount and type of heat Response time Efficiency 80 – 85 % is typical Electricity is ~100 % Combustion air supply Flue gas discharge (stack height)
Choosing a Boiler Fuel source Transfer medium Operating temperatures/pressures Equipment Type Space requirements Auxiliary systems
Water Boilers Types Water Tube Boiler Fire Tube Boiler Water in tubes, hot combustion gasses in shell Quickly respond to changes in loads Fire Tube Boiler Hot combustion gasses in tubes, water in shell Slower to respond to changes in loads
Electric Types Resistance Electrode Resistor gets hot Typically slow response time (demand issues) Electrode Use water as heat conducting medium Bigger systems Cheap to buy, very expensive to run Clean, no local emissions
Auxiliary Burner type (atmospheric or power vented) Feedwater systems Returns steam condensate (including accumulator) Adds water to account for blowdown and leaks Preheats the water Removes dissolved gasses Blowdown system Periodically drain and cool water
Auxiliary Water treatment Treatment options Dissolved minerals and gasses cause: Reduced heat transfer Reduced flow (increased pressure drop) Corrosion Treatment options Chemical (add bases, add ions, add inhibitor) Temperature (heat to remove oxygen)
Location Depends on type Aesthetics Stack height Integration with cooling systems
Reading Assignment Tao and Janis Chapter 5