Using Chemical Formulas

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Presentation transcript:

Using Chemical Formulas Chapter 7 Using Chemical Formulas

Formula Mass Formula Mass—the sum of the average atomic masses of all atoms represented in the formula. Numerically equal to molar mass (different units). Difference is molar mass is the total mass of 1 mol of the substance (g/mol), and formula mass is the mass of only 1 unit of that formula (amu).

Formulas Subscript numbers tell how many moles of each atom are in 1 mol of the compound or molecule. Example: Al2S3 shows there are 2 mol of Aluminum and 3 mol of Sulfur in every 1 mol of Al2S3

Practice Determine the number of moles of each atom present in the following formulas: Mg(OH)2 H2SO4 Ca(NO3)2 Determine the molar mass for each compound

REVIEW Determine the number of moles in 2.3 g of NH3 Determine the number of grams in 5 moles of Ca(NO3)2

REVIEW MOLE TO MOLE RATIO The only way to convert from one substance to another is through a mole to mole ratio!!!

More Review Determine the number of moles of silver in 102.3 g of Silver (II) Phosphate. Determine the number of grams of carbon in 17.4 g of heptane.

BELL RINGER (5 minutes) How many moles of phosphorus are in 16.2 grams of sodium phosphate? How many grams of calcium are in 108.4 grams of calcium nitride?

Review: Percent composition mass of element in sample of compound x 100 = % element in compound mass of sample of compound mass of element in 1 mole of compound x 100 = % element in compound molar mass of compound

Percent composition Examples Determine the percent composition of KClO3 Determine the percent composition of Copper in Copper (I) Sulfide

Percent composition of Hydrates Na2CO3 ● 10H2O - name? 10 water molecules are present for every 1 formula unit of Na2CO3 Find the mass percentage of water in sodium carbonate decahydrate:

White boarding Practice Calculate the percent composition of each element in aluminum sulfate Calculate the percentage of water in barium hydroxide heptahydrate

Percent composition Bellringer 1. Find the percent composition of each element in silver (I) nitrate. 2. Find the mass percentage of water in copper (II) sulfate pentahydrate. 3. Find the percent of iron in iron (III) chloride dehydrate.

Determining Chemical Formulas Empirical formula—the formula showing the smallest whole-number mole ratio of different atoms in a compound. Molecular formula—represents the actual number of atoms present in a molecule.

What’s the difference? Empirical Formula Molecular formula Name of Molecule Boiling Point (oC) CH2O Formaldehyde -21 C2H4O2 Acetic Acid 117 C3H6O3 Glyceraldehyde 140

Calculation of Empirical Formulas From percent composition 3 steps—Example: Compound containing 78.1% B and 21.9% H. Convert all percentages to masses out of 100 g. Convert masses to moles using molar mass of element. Divide each number of moles by smallest mole value to get ratios for empirical formula. If not whole numbers after dividing, multiply all values by whole numbers until all are made whole numbers.

Practice Quantitative analysis shows a compound with 32.38% Na, 22.65% S, and 44.99% O. Find the empirical formula of the compound. Analysis of a 10.150 g sample of a compound containing only P and O indicates a P content of 4.433 g. What is the empirical formula of the compound?

Empirical Formula of Hydrates A 5.018 gram sample of a certain hydrate of magnesium sulfate, MgSO4 • xH2O, is heated until all the water is driven off. The resulting anhydrous compound weighs 2.449 grams. What is the formula of the hydrate?

Calculation of Molecular Formulas Empirical formula = smallest ratio of whole numbers, therefore the molecular formula must be thus: x(empirical formula) = molecular formula 𝒎𝒐𝒍𝒆𝒄𝒖𝒍𝒂𝒓 𝒇𝒐𝒓𝒎𝒖𝒍𝒂 𝒎𝒂𝒔𝒔 𝒆𝒎𝒑𝒊𝒓𝒊𝒄𝒂𝒍 𝒇𝒐𝒓𝒎𝒖𝒍𝒂 𝒎𝒂𝒔𝒔 =𝒙 x = the number by which to multiply ratios in empirical formula to get molecular formula

Practice Determine the molecular formula of a compound with an empirical formula of CH and a molecular mass of 78.110 amu. A sample with a formula mass of 34.00 amu consists of 0.44 g of H and 6.92 g O. Find the molecular formula.