Find the following: sin 30˚ (no calculator allowed)

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Presentation transcript:

Find the following: sin 30˚ (no calculator allowed) sin 75˚ (use a calculator) Is sin 30˚ + sin 45˚ = sin 75˚? What two unit circle values combine to be 165˚? What two unit circle values combine to be 105˚?

Find the following: sin 30˚ (no calculator allowed) = ½ sin 75˚ (use a calculator) Is sin 30˚ + sin 45˚ = sin 75˚? What two unit circle angles combine to be 165˚? What two unit circle angles combine to be 105˚? = ½ = = 0.9659 No, the two are not equal ½ + ≠ 0.9659 120 + 45 135 – 30 or 60 + 45

Difference Identities Chapter 5 Trigonometric Equations 5.4 Using Sum and Difference Identities MATHPOWERTM 12, WESTERN EDITION 5.4.1

Sum and Difference Identities sin(A + B) = sin A cos B + cos A sin B sin(A - B) = sin A cos B - cos A sin B cos(A + B) = cos A cos B - sin A sin B cos(A - B) = cos A cos B + sin A sin B 5.5.2

1. Find the exact value for sin 750. Finding Exact Values 1. Find the exact value for sin 750. Think of the angle measures that produce exact values: 300, 450, and 600. Use the sum and difference identities. Which angles, used in combination of addition or subtraction, would give a result of 750? sin 750 = sin(300 + 450) = sin 300 cos 450 + cos 300 sin 450 5.5.4

2. Find the exact value for cos 150. cos 150 = cos(450 - 300) Finding Exact Values 2. Find the exact value for cos 150. cos 150 = cos(450 - 300) = cos 450 cos 300 + sin 450 sin300 3. Find the exact value for 5.5.5

4. Find the exact value for tan 1650. tan 1650 = tan(1350 + 300) Finding Exact Values 4. Find the exact value for tan 1650. tan 1650 = tan(1350 + 300)

Rationalize the denominator Multiply top and bottom by the conjugate of the bottom

4. Find the exact value for tan 1650 (continued) Finding Exact Values 4. Find the exact value for tan 1650 (continued) tan 1650 Rationalize the denominator

Assignment

Simplifying Trigonometric Expressions 1. Express cos 1000 cos 800 + sin 800 sin 1000 as a trig function of a single angle. This function has the same pattern as cos (A - B), with A = 1000 and B = 800. cos 100 cos 80 + sin 80 sin 100 = cos(1000 - 800) = cos 200 2. Express as a single trig function. This function has the same pattern as sin(A - B), with 5.5.3

Using the Sum and Difference Identities Prove L.S. = R.S. 5.5.6

Using the Sum and Difference Identities x = 3 r = 5 θ 5 3 y = ± 4 sinθ = 4/5 5.5.7

Using the Sum and Difference Identities A B x y r 4 2 3 3 5 5.5.8

Assignment Complete #’s 3-12 on worksheet Answers: – sin x Hints: cos x sin x – tan x + 2 sin x Hints: 345 = 300 + 45 195 = 240 – 45

Identities Prove L.S. = R.S. 5.5.16

Double-Angle Identities The identities for the sine and cosine of the sum of two numbers can be used, when the two numbers A and B are equal, to develop the identities for sin 2A and cos 2A. sin 2A = sin (A + A) = sin A cos A + cos A sin A = 2 sin A cos A cos 2A = cos (A + A) = cos A cos A - sin A sin A = cos2 A - sin2A Identities for sin 2x and cos 2x: sin 2x = 2sin x cos x cos 2x = cos2x - sin2x cos 2x = 2cos2x - 1 cos 2x = 1 - 2sin2x 5.5.9

Double-Angle Identities Express each in terms of a single trig function. a) 2 sin 0.45 cos 0.45 b) cos2 5 - sin2 5 sin 2x = 2sin x cos x sin 2(0.45) = 2sin 0.45 cos 0.45 sin 0.9 = 2sin 0.45 cos 0.45 cos 2x = cos2 x - sin2 x cos 2(5) = cos2 5 - sin2 5 cos 10 = cos2 5 - sin2 5 Find the value of cos 2x for x = 0.69. cos 2x = cos2 x - sin2 x cos 2(0.69) = cos2 0.69 - sin2 0.69 cos 2x = 0.1896 5.5.10

Double-Angle Identities Verify the identity L.S = R.S. 5.5.11

Double-Angle Identities Verify the identity L.S = R.S. 5.5.12

Double-Angle Equations p 2p y = cos 2A 5.5.13

Double-Angle Equations y = sin 2A 5.5.14

Rewrite f(x) as a single trig function: f(x) = sin 2x Using Technology Graph the function and predict the period. The period is p. Rewrite f(x) as a single trig function: f(x) = sin 2x 5.5.15

Applying Skills to Solve a Problem The horizontal distance that a soccer ball will travel, when kicked at an angle q, is given by , where d is the horizontal distance in metres, v0 is the initial velocity in metres per second, and g is the acceleration due to gravity, which is 9.81 m/s2. a) Rewrite the expression as a sine function. Use the identity sin 2A = 2sin A cos A: 5.5.17

Applying Skills to Solve a Problem [cont’d] b) Find the distance when the initial velocity is 20 m/s. From the graph, the maximum distance occurs when q = 0.785398. The maximum distance is 40.7747 m. The graph of sin q reaches its maximum when Sin 2q will reach a maximum when Distance Angle q 5.5.18

Assignment Suggested Questions: Pages 272-274 A 1-16, 25-35 odd B 17-24, 37-40, 43, 47, 52 5.5.19