Weight hangs motionless

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Presentation transcript:

Weight hangs motionless P. 142 # 97 30 FT = ? Horizontal Cable Fg = 750 N

Weight hangs motionless P. 142 # 97 30 FT = ? Fy = 750 N FT = Fx Horizontal Cable (750N)Tan 30° =Fx Fg = 750 N FT = 433 N

A sign hangs motionless from two cables. Find the Tension in Cable 2 A sign hangs motionless from two cables. Find the Tension in Cable 2. Include the direction of the cable, also. F1 = 85 N F2 65 N 45 N 50 2 54.6 N 54.6 N Fg = 110 N 65 N + y2 = 110 N y2 = 45 N F2 = 70.7 N @  = 39.4 above Horizontal

θ 30 F2 F1 = 720 N Fg = 600 N

Lab Example Fx = 0 Fy = 0