Key Areas covered Resolving a force into two perpendicular components.

Slides:



Advertisements
Similar presentations
 The force that act on the object are balanced in all direction.  The force cancel each other, so that the resultant force or net force is zero.  Newton’s.
Advertisements

Problem A small 200-g collar C can slide on a
APPLICATION OF VECTOR ADDITION
Students will be able to : a) Resolve a 2-D vector into components
Make a sketch Problem: A 10.0 kg box is pulled along a horizontal surface by a rope that makes a 30.0 o angle with the horizontal. The tension in the rope.
Forces applied at an Angle & Inclined Planes
Kinetic energy Vector dot product (scalar product) Definition of work done by a force on an object Work-kinetic-energy theorem Lecture 10: Work and kinetic.
Examples from Chapter 4.
NEWTON’S SECOND LAW.
Vectors. Vector quantity has magnitude and direction. is represented by an arrow. Example: velocity, force, acceleration Scalar quantity has magnitude.
Vectors and Scalars and Their Physical Significance.
Horizontal Projectiles Physics Level 1. Vector Resolution The study of vectors allows for breaking a single vector into components: – the vertical y component.
Aristotle 384 – 322 BC ISAAC NEWTON.
Projectile Motion Introduction Horizontal launch.
Vectors and Scalars.  A scalar quantity is a quantity that has magnitude only and has no direction in space Examples of Scalar Quantities:  Length 
2 - 1 Engineering Mechanics Lecture 2 Composition and Resolution of forces
Newton’s third law of motion 1 Force 2
Key Areas covered Balanced and unbalanced forces. The effects of friction. Terminal velocity. Forces acting in one plane only. Analysis of motion using.
Essential Idea for the Lesson
Key Areas covered Projectiles and satellites.
on an inclined surface. The surface makes 30⁰ angle with horizon.
V = 20 m/s magnitude of the velocity vector.
Vector Worksheet 3 Answers
Revision tips and key areas
Key Areas covered Resolving a force into two perpendicular components.
Components or resolved forces
2.3.1 scalars and vectors Lesson 2.
Vectors.
The Nature of Friction OR Here’s where things start to get rough
Copyright © John O’Connor For non-commercial purposes only….. Enjoy!
Making Pretty Pictures
What are the three fundamental forces outside of the nucleus?
More Vector Examples Answers
not the “dark side” of the force
Key Areas covered Resolving the weight of an object on a slope into a component acting down the slope and a component acting normal to the slope. Systems.
2015 EdExcel A Level Physics
Force Vectors and Equilibrium
Mechanics & Materials 2015 AQA A Level Physics Vectors 9/17/2018.
Forces on an inclined plane
Projectile Motion Everyday applications Vector additions
Vectors and Scalars.
FORCE VECTORS, VECTOR OPERATIONS & ADDITION COPLANAR FORCES
Chapter 3.
Net Force.
The height of the building
Statics Dr. Aeid A. Abdulrazeg Course Code: CIVL211
Vectors and Scalars.
Aim: How do we explain motion along an inclined plane?
1. A ball of mass m is suspended from two strings of unequal length as shown above. The magnitudes of the tensions T1 and T2 in the strings must satisfy.
Newton's Three laws of Motion:-
35. Resolving Vectors (applications)
5.3 Components of Vectors The perpendicular components of a vector are independent of each other.
Aim: How do we explain motion along an inclined plane?
Key Areas covered Projectiles and satellites.
Key Areas covered Resolving the weight of an object on a slope into a component acting down the slope and a component acting normal to the slope. Systems.
Horizontal Surface (no friction)
Scalars A scalar quantity is a quantity that has magnitude only and has no direction in space Examples of Scalar Quantities: Length Area Volume Time Mass.
Key Areas covered Balanced and unbalanced forces. The effects of friction. Terminal velocity. Forces acting in one plane only. Analysis of motion using.
Unit 1 Our Dynamic Universe Projectiles
Resolving Vectors in Components
Forces applied at an Angle & Inclined Planes
How does an inclined plane make work easier How does an inclined plane make work easier? How does it change the force that is applied to the inclined.
Force Problems.
Chapter 4 Additional Problems
Vectors A vector is a quantity which has a value (magnitude) and a direction. Examples of vectors include: Displacement Velocity Acceleration Force Weight.
Vectors and Scalars.
Work and Energy Chapter 5 Physics.
Forces The unedited story.
Motion in Two Dimensions
Consider 7.0 kg mass pulled with a force of 60 N up an incline with an angle of 15º. The coefficient of friction between the surfaces is Given:
Presentation transcript:

Key Areas covered Resolving a force into two perpendicular components. Forces acting at an angle to the direction of movement.

What we will do today: Identify how to solve problems when we have two forces acting at different angles (component of forces). Carry out problems on the above

Resolution (Rectangular Components) of a Vector T. Ferns – 4/8/04 LO’s 1.1.5, 1.2.5

The horizontal component xh The vertical component xv Any vector, x, can be resolved into two components at right angles to each other. The horizontal component xh The vertical component xv x xv is equivalent to θ xh

sin θ = xv / x xv = x sin θ cos θ = xh / x xh = x cos θ x xv θ xh

Force The vertical and horizontal components of a Force vector, F, are, respectively: Fv = F sin θ Fh = F cos θ

Velocity (more on this later) The vertical and horizontal components of a velocity vector, v, are, respectively: vv = v sin θ vh = v cos θ

Components of Forces T. Ferns – 13/9/04 LO’s 1.1.5, 1.2.4, 1.2.5

This can obviously apply to a force. is equivalent to In the previous section, a vector was split into horizontal and vertical components. This can obviously apply to a force. is equivalent to Remember that the resultant of a number of forces is the single force which has the same effect, in both magnitude and direction, as the sum of the individual forces. Fv = F sin θ F θ Fh = F cos θ

Example 1 A man pulls a garden roller of mass 100 kg with a force of 200 N acting at 30º to the horizontal. If there is a frictional force of 100 N between the roller and the ground, what is the acceleration of the roller along the ground? Solution Fh = F cos θ = 200 cos 30º = 173.2 N Fun = 173.2 N – Friction = 173.2 – 100 = 73.2 N a = Fun / m = 73.2 / 100 = 0.732 ms-2 200 N 30º Fh Friction = 100 N

Example 2 An oil rig is pulled by two barges as shown. Each barge applies a force of 10 kN. What is the resultant force acting on the rig? Solution: Work out Fh for one barge: Fh = F cos θ = 10 000 cos 30 = 8660N Then double this to include forces from both barges: 2 x 8660 = 17 300 N (3 sig fig)

Experiment

Experiment

2004 Qu: 1

2009 Qu: 3

2001 Qu: 21

2001 Qu: 21