ANSWERS WILL BE IN SQUARE UNITS

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Presentation transcript:

ANSWERS WILL BE IN SQUARE UNITS 6.8 Area of a circle A = p r2 ANSWERS WILL BE IN SQUARE UNITS

Find the area. 10 in 7.6 cm 181.5 square cm or 57.76p sq.cm 78.54 square in or 25p sq. in.

A = pr2 C = 2pr A = p 52 10p = 2pr A = 25p or 5 = r A = 78.54 in2 If S has a circumference of 10p inches, find the area of the circle to the nearest hundredth. A = pr2 C = 2pr A = p 52 10p = 2pr A = 25p or 5 = r A = 78.54 in2

SECTOR: R Q O

R 6 cm 60° Q R 7 cm Q 120 °

Area of a segment: a segment is a region bound by a chord and its corresponding arc. The area of a segment is equal to the area of the sector - the area of the triangle. X Y Z

R Q 12 yd

Given arc XY is 90º and ZX = 8 Find the shaded area. X Z Y Segment = sector – triangle = 90π(82) – ½(8)(8) 360 = 16π – 32 units2 X Y Z

Find the area of the shaded region. A = p22 A = p82 A = p4 A = p64 2 in A = 12.57 in2 A = 201.06 in2 6in A shaded = A – A= 201.06 - 12.57 = 60p or 188.49in2